# Find the sum of first N terms of the series 2×3 + 4×4 + 6×5 + 8×6 + …

Given an integer N. The task is to find the sum upto N terms of the given series:

2×3 + 4×4 + 6×5 + 8×6 + … + upto n terms

Examples:

Input : N = 5
Output : Sum = 170

Input : N = 10
Output : Sum = 990


## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Let the N-th term of the series be tN.
t1 = 2 × 3 = (2 × 1)(1 + 2)
t2 = 4 × 4 = (2 × 2)(2 + 2)
t3 = 6 × 5 = (2 × 3)(3 + 2)
t4 = 8 × 6 = (2 × 4)(4 + 2)
.
.
.
tN = (2 × N)(N + 2)

The sum of n terms of the series,

 Sn = t1 + t2 +... + tn
= = = = = = = Below is the implementation of above approach:

## C++

 // C++ program to find sum upto  // N term of the series:   // 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...   #include  using namespace std;     // calculate sum upto N term of series   void Sum_upto_nth_Term(int n)   {      int r = n * (n + 1) *                   (2 * n + 7) / 3;      cout << r;  }     // Driver code   int main()  {      int N = 5;      Sum_upto_nth_Term(N) ;      return 0;  }

## Java

 // Java program to find sum upto  // N term of the series:      import java.io.*;     class GFG {  // calculate sum upto N term of series   static void Sum_upto_nth_Term(int n)   {      int r = n * (n + 1) *                   (2 * n + 7) / 3;      System.out.println(r);  }     // Driver code      public static void main (String[] args) {      int N = 5;      Sum_upto_nth_Term(N);      }  }

## Python3

 # Python program to find sum upto N term of the series:  # 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...     # calculate sum upto N term of series  def Sum_upto_nth_Term(n):      return n * (n + 1) * (2 * n + 7) // 3    # Driver code  N = 5 print(Sum_upto_nth_Term(N))

## C#

 // C# program to find sum upto  // N term of the series:   // 2 × 3 + 4 × 4 + 6 × 5 + 8 × 6 + ...      using System;     class GFG  {  // calculate sum upto N term of series   static void Sum_upto_nth_Term(int n)   {      int r = n * (n + 1) *                   (2 * n + 7) / 3;      Console.Write(r);  }     // Driver code   public static void Main()  {      int N = 5;      Sum_upto_nth_Term(N);  }  }     // This code is contributed   // by Akanksha Rai(Abby_akku)

## PHP

 

Output:

170


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