Given two strings string1 and string2, the task is to find the smallest substring in string1 containing all characters of string2 efficiently.
Input: string = “this is a test string”, pattern = “tist”
Output: Minimum window is “t stri”
Explanation: “t stri” contains all the characters of pattern.
Input: string = “geeksforgeeks”, pattern = “ork”
Output: Minimum window is “ksfor”
Method 1 ( Brute force solution )
1- Generate all substrings of string1 (“this is a test string”)
2- For each substring, check whether the substring contains all characters of string2 (“tist”)
3- Finally, print the smallest substring containing all characters of string2.
Method 2 ( Efficient Solution )
- First check if the length of the string is less than the length of the given pattern, if yes then “no such window can exist “.
- Store the occurrence of characters of the given pattern in a hash_pat.
- we will be using two pointer technique basically
- Start matching the characters of pattern with the characters of string i.e. increment count if a character matches.
- Check if (count == length of pattern ) this means a window is found.
- If such a window found, try to minimize it by removing extra characters from the beginning of the current window.
- delete one character from first and again find this deleted key at right, once found apply step 5 .
- Update min_length.
- Print the minimum length window.
A diagram to explain the stated algorithm:
Below is the program to implement the above algorithm:
Smallest window is : t stri
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