# Find the root of the sub-tree whose weighted sum is minimum

Given a tree, and the weights of all the nodes, the task is to find the root of the sub-tree whose weighted sum is minimum.

**Examples:**

Input:

Output:5

Weight of sub-tree for parent 1 = ((-1) + (5) + (-2) + (-1) + (3)) = 4

Weight of sub-tree for parent 2 = ((5) + (-1) + (3)) = 7

Weight of sub-tree for parent 3 = -1

Weight of sub-tree for parent 4 = 3

Weight of sub-tree for parent 5 = -2

Node 5 gives the minimum sub-tree weighted sum.

**Approach:** Perform dfs on the tree, and for every node calculate the sub-tree weighted sum rooted at the current node then find the minimum sum value for a node.

Below is the implementation of the above approach:

`// C++ implementation of the approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `int` `ans = 0, mini = INT_MAX; ` ` ` `vector<` `int` `> graph[100]; ` `vector<` `int` `> weight(100); ` ` ` `// Function to perform dfs and update the tree ` `// such that every node's weight is the sum of ` `// the weights of all the nodes in the sub-tree ` `// of the current node including itself ` `void` `dfs(` `int` `node, ` `int` `parent) ` `{ ` ` ` `for` `(` `int` `to : graph[node]) { ` ` ` `if` `(to == parent) ` ` ` `continue` `; ` ` ` `dfs(to, node); ` ` ` ` ` `// Calculating the weighted ` ` ` `// sum of the subtree ` ` ` `weight[node] += weight[to]; ` ` ` `} ` `} ` ` ` `// Function to find the node ` `// having minimum sub-tree sum ` `void` `findMin(` `int` `n) ` `{ ` ` ` ` ` `// For every node ` ` ` `for` `(` `int` `i = 1; i <= n; i++) { ` ` ` ` ` `// If current node's weight ` ` ` `// is minimum so far ` ` ` `if` `(mini > weight[i]) { ` ` ` `mini = weight[i]; ` ` ` `ans = i; ` ` ` `} ` ` ` `} ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `int` `n = 5; ` ` ` ` ` `// Weights of the node ` ` ` `weight[1] = -1; ` ` ` `weight[2] = 5; ` ` ` `weight[3] = -1; ` ` ` `weight[4] = 3; ` ` ` `weight[5] = -2; ` ` ` ` ` `// Edges of the tree ` ` ` `graph[1].push_back(2); ` ` ` `graph[2].push_back(3); ` ` ` `graph[2].push_back(4); ` ` ` `graph[1].push_back(5); ` ` ` ` ` `dfs(1, 1); ` ` ` `findMin(n); ` ` ` ` ` `cout << ans; ` ` ` ` ` `return` `0; ` `} ` |

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**Output:**

5

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