Given a number N, find the remainder when the first digit of N is divided by its last digit.**Examples:**

Input:N = 1234Output:1 First digit = 1 Last digit = 4 Remainder = 1 % 4 = 1Input:N = 5223Output:2 First digit = 5 Last digit = 3 Remainder = 5 % 3 = 2

**Approach:** Find the first digit and the last digit of the number. Find then the remainder when the first digit is divided by the last digit.

Below is the implementation of the above approach:

## C++

`// C++ program to find the remainder` `// when the First digit of a number` `// is divided by its Last digit` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find the remainder` `void` `findRemainder(` `int` `n)` `{` ` ` `// Get the last digit` ` ` `int` `l = n % 10;` ` ` `// Get the first digit` ` ` `while` `(n >= 10)` ` ` `n /= 10;` ` ` `int` `f = n;` ` ` `// Compute the remainder` ` ` `int` `remainder = f % l;` ` ` `cout << remainder << endl;` `}` `// Driver code` `int` `main()` `{` ` ` `int` `n = 5223;` ` ` `findRemainder(n);` ` ` `return` `0;` `}` |

## Java

`// Java program to find the remainder` `// when the First digit of a number` `// is divided by its Last digit` `class` `GFG` `{` ` ` `// Function to find the remainder` `static` `void` `findRemainder(` `int` `n)` `{` ` ` `// Get the last digit` ` ` `int` `l = n % ` `10` `;` ` ` `// Get the first digit` ` ` `while` `(n >= ` `10` `)` ` ` `n /= ` `10` `;` ` ` `int` `f = n;` ` ` `// Compute the remainder` ` ` `int` `remainder = f % l;` ` ` `System.out.println(remainder);` `}` `// Driver code` `public` `static` `void` `main(String[] args)` `{` ` ` `int` `n = ` `5223` `;` ` ` `findRemainder(n);` `}` `}` `// This code is contributed by Code_Mech` |

## Python3

`# Python3 program to find the remainder` `# when the First digit of a number` `# is divided by its Last digit` `# Function to find the remainder` `def` `findRemainder(n):` ` ` ` ` `# Get the last digit` ` ` `l ` `=` `n ` `%` `10` ` ` ` ` `# Get the first digit` ` ` `while` `(n >` `=` `10` `):` ` ` `n ` `/` `/` `=` `10` ` ` `f ` `=` `n` ` ` `# Compute the remainder` ` ` `remainder ` `=` `f ` `%` `l` ` ` `print` `(remainder)` `# Driver code` `n ` `=` `5223` `findRemainder(n)` `# This code is contributed by Mohit Kumar` |

## C#

`// C# program to find the remainder` `// when the First digit of a number` `// is divided by its Last digit` `using` `System;` `class` `GFG` `{` ` ` `// Function to find the remainder` `static` `void` `findRemainder(` `int` `n)` `{` ` ` `// Get the last digit` ` ` `int` `l = n % 10;` ` ` `// Get the first digit` ` ` `while` `(n >= 10)` ` ` `n /= 10;` ` ` `int` `f = n;` ` ` `// Compute the remainder` ` ` `int` `remainder = f % l;` ` ` `Console.WriteLine(remainder);` `}` `// Driver code` `public` `static` `void` `Main()` `{` ` ` `int` `n = 5223;` ` ` `findRemainder(n);` `}` `}` `// This code is contributed by Code_Mech` |

## Javascript

`<script>` ` ` `// Javascript program to find the remainder` `// when the First digit of a number` `// is divided by its Last digit` `// Function to find the remainder` `function` `findRemainder( n)` `{` ` ` `// Get the last digit` ` ` `let l = n % 10;` ` ` `// Get the first digit` ` ` `while` `(n >= 10)` ` ` `n /= 10;` ` ` `let f = n;` ` ` `// Compute the remainder` ` ` `let remainder = f % l;` ` ` `document.write(Math.floor(remainder));` `}` `// Driver code` ` ` `let n = 5223;` ` ` `findRemainder(n);` `// This code is contributed by mohan pavan` `</script>` |

**Output:**

2

**Time Complexity:** O(L ) where L is length of number in decimal representation

**Auxiliary Space:** O(1)

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