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Find the position of number that is multiple of certain number

  • Last Updated : 11 Oct, 2020

In this type of question, a number is given and we have to find the position or index of all multiples of that number. For doing this question we use a function named numpy.argwhere().

Syntax:

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numpy.argwhere(array)

Example 1: 



Sometimes we need to find the indexes of the element that are divisible by int or float number.

Python3




# Importing Pandas and Numpy libraries
import pandas as pd
import numpy as np
  
# Creating a Series of random numbers
n_series = pd.Series(np.random.randint(1, 25, 15))
print("Original Series:\n")
print(n_series)
  
# Finding the indexes of numbers divisible by 3
res_index = np.argwhere(n_series % 3==0)
print("Positions of numbers that are multiples of 3:\n")
print(res_index)

Output:

In the above example, we find the indexes of all numbers divisible by 3.

Example 2:

Python3




# Importing Pandas and Numpy libraries
import pandas as pd
import numpy as np
  
# Creating a Series of random numbers
n_series = pd.Series(np.random.randint(1, 20, 10))
print("Original Series:\n")
print(n_series)
  
# Finding the indexes of numbers divisible by 3.5
res_index = np.argwhere(n_series % 3.5==0)
print("Positions of numbers that are multiples of 3.5:\n")
print(res_index)

Output:

In the above example, we find the indexes of all numbers divisible by floating-point number 3.5




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