Find the player to last modify a string such that even number of consonants and no vowels are left in the string

Given a string S of length N containing lowercase alphabets. Two players A and B play a game optimally in turns, starting with player A. In each move, either of the following operations can be performed:

A player loses the game if there is an even number of consonants and no vowels left in the string. The task is to determine the winner of the game. In case of a draw, print D.
 Examples:

Input: S = “abcd”
Output: Player A
Explanation:
Player A can win by performing the following moves:
Move 1: A changes a to f. Therefore, S = “fbcd”
Move 2: B removes f. Therefore, S = “bcd”.
Move 3: A removes b. Therefore, S = “cd”.
Move 4: B removes c. Therefore, S = “d”.
Move 5: A removes d. Therefore, S = “”.
Now in B’s turn, S have no vowels and an even number of consonants i.e., 0. 

Input: S = “abcde”
Output: D

 

 Approach: To solve the problem, observe the following cases:



Follow the below steps to solve the problem: 

Below is the implementation of the above approach:

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// C++ program for the above approach
 
#include <bits/stdc++.h>
using namespace std;
 
// Function to find a winner of the game
// if both the player plays optimally
void findWinner(string s)
{
    // Stores the count of vowels
    // and consonants
    int vowels_count = 0,
        consonants_count = 0;
 
    // Traverse the string
    for (int i = 0; i < s.size(); i++) {
 
        // Check if character is vowel
        if (s[i] == 'a'
            || s[i] == 'e'
            || s[i] == 'i'
            || s[i] == 'o'
            || s[i] == 'u') {
 
            // Increment vowels count
            vowels_count++;
        }
 
        // Otherwise increment the
        // consonants count
        else {
            consonants_count++;
        }
    }
 
    if (vowels_count == 0) {
 
        // Check if Player B wins
        if (consonants_count % 2 == 0) {
            cout << "Player B";
        }
 
        // Check if Player A wins
        else {
            cout << "Player A";
        }
    }
 
    // Check if Player A wins
    else if (vowels_count == 1
             && consonants_count % 2 != 0) {
        cout << "Player A";
    }
 
    // If game ends in a Draw
    else {
        cout << "D";
    }
}
 
// Driver Code
int main()
{
    // Given string s
    string s = "abcd";
 
    // Function Call
    findWinner(s);
 
    return 0;
}
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// Java program for the
// above approach
class GFG{
 
// Function to find a winner
// of the game if both the
// player plays optimally
static void findWinner(char[] s)
{
  // Stores the count of vowels
  // and consonants
  int vowels_count = 0,
  consonants_count = 0;
 
  // Traverse the String
  for (int i = 0; i < s.length; i++)
  {
    // Check if character is vowel
    if (s[i] == 'a' ||
        s[i] == 'e' ||
        s[i] == 'i' ||
        s[i] == 'o' ||
        s[i] == 'u')
    {
      // Increment vowels count
      vowels_count++;
    }
 
    // Otherwise increment the
    // consonants count
    else
    {
      consonants_count++;
    }
  }
 
  if (vowels_count == 0)
  {
    // Check if Player B wins
    if (consonants_count % 2 == 0)
    {
      System.out.print("Player B");
    }
 
    // Check if Player A wins
    else
    {
      System.out.print("Player A");
    }
  }
 
  // Check if Player A wins
  else if (vowels_count == 1 &&
           consonants_count % 2 != 0)
  {
    System.out.print("Player A");
  }
 
  // If game ends in a Draw
  else
  {
    System.out.print("D");
  }
}
 
// Driver Code
public static void main(String[] args)
{
  // Given String s
  String s = "abcd";
 
  // Function Call
  findWinner(s.toCharArray());
}
}
 
// This code is contributed by 29AjayKumar
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# Python3 program for the above approach
 
# Function to find a winner of the game
# if both the player plays optimally
def findWinner(s):
     
    # Stores the count of
    # vowels and consonants
    vowels_count = 0
    consonants_count = 0
 
    # Traverse the string
    p = len(s)
     
    for i in range(0, p):
 
        # Check if character is vowel
        if (s[i] == 'a' or s[i] == 'e' or
            s[i] == 'i' or s[i] == 'o' or
            s[i] == 'u'):
                 
            # Increment vowels count
            vowels_count = vowels_count + 1
 
        # Otherwise increment the
        # consonants count
        else:
            consonants_count = consonants_count + 1
 
    if (vowels_count == 0):
 
        # Check if Player B wins
        if (consonants_count % 2 == 0):
            print("Player B")
 
        # Check if Player A wins
        else:
            print("Player A")
         
    # Check if Player A wins
    elif (vowels_count == 1 and
       consonants_count % 2 != 0):
        print("Player A")
 
    # If game ends in a Draw
    else:
        print("D")
 
# Driver Code
s = "abcd"
 
findWinner(s)
 
# This code is contributed by sallagondaavinashreddy7
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// C# program for the
// above approach
using System;
class GFG{
 
// Function to find a winner
// of the game if both the
// player plays optimally
static void findWinner(char[] s)
{
  // Stores the count of vowels
  // and consonants
  int vowels_count = 0,
  consonants_count = 0;
 
  // Traverse the String
  for (int i = 0; i < s.Length; i++)
  {
    // Check if character is vowel
    if (s[i] == 'a' ||
        s[i] == 'e' ||
        s[i] == 'i' ||
        s[i] == 'o' ||
        s[i] == 'u')
    {
      // Increment vowels count
      vowels_count++;
    }
 
    // Otherwise increment the
    // consonants count
    else
    {
      consonants_count++;
    }
  }
 
  if (vowels_count == 0)
  {
    // Check if Player B wins
    if (consonants_count % 2 == 0)
    {
      Console.Write("Player B");
    }
 
    // Check if Player A wins
    else
    {
      Console.Write("Player A");
    }
  }
 
  // Check if Player A wins
  else if (vowels_count == 1 &&
           consonants_count % 2 != 0)
  {
    Console.Write("Player A");
  }
 
  // If game ends in a Draw
  else
  {
    Console.Write("D");
  }
}
 
// Driver Code
public static void Main(String[] args)
{
  // Given String s
  String s = "abcd";
 
  // Function Call
  findWinner(s.ToCharArray());
}
}
 
// This code is contributed by gauravrajput1
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Output
Player A




Time Complexity: O(N)
Auxiliary Space: O(N)

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