# Find the Nth term of the series 2 + 6 + 13 + 23 + . . .

Given an integer N. The task is to write a program to find the Nth term of the given series:

2 + 6 + 13 + 23 + …

Examples:

Input : N = 5
Output : 36

Input : N = 10
Output : 146


## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Refer the article on How to find Nth term of series to know idea behind finding Nth term of any given series.

The generalized N-th term of given series is: Below is the implementation of above approach:

## C++

 //CPP program to find Nth term of the series  // 2 + 6 + 13 + 23 + 36 + ...  #include  using namespace std;     // calculate Nth term of given series  int Nth_Term(int n)  {         return (3 * pow(n, 2) - n + 2) / (2);     }     // Driver code  int main()  {     int N = 5;  cout<

## Java

 //Java program to find Nth term of the series  // 2 + 6 + 13 + 23 + 36 + ...  import java.io.*;     class GFG {     // calculate Nth term of given series  static int Nth_Term(int n)  {         return (int)(3 * Math.pow(n, 2) - n + 2) / (2);     }     // Driver code         public static void main (String[] args) {      int N = 5;      System.out.println(Nth_Term(N));      }  }  // This code is contributed by anuj_67.. 

## Python3

 # Python program to find Nth term of the series  # 2 + 6 + 13 + 23 + 36 + ...     # calculate Nth term of given series  def Nth_Term(n):      return (3 * pow(n, 2) - n + 2) // (2)     # Driver code  N = 5 print(Nth_Term(N)) 

## C#

 // C# program to find Nth term of the series  // 2 + 6 + 13 + 23 + 36 + ...     class GFG   {     // calculate Nth term of given series  static int Nth_Term(int n)  {             return (int)(3 * System.Math.Pow(n, 2) -                                n + 2) / (2);  }     // Driver code  static void Main ()  {      int N = 5;      System.Console.WriteLine(Nth_Term(N));  }  }     // This code is contributed by mits 

## PHP

  

Output:

36
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