Find the Nth term in series 12, 35, 81, 173, 357, …

Given a number **N**, the task is to find the **Nth** term in series **12, 35, 81, 173, 357, …****Example:**

Input:N = 2Output:35 2nd term = (12*2) + 11 = 35Input:N = 5Output:357 5th term = (12*(2^4))+11*((2^4)-1) = 357

**Approach:**

- Each and every number is obtained by multiplying the previous number by 2 and the addition of 11 to it.
- Since starting number is 12.

1st term = 12 2nd term = (12 * 2) / 11 = 35 3rd term = (35 * 2) / 11 = 81 4th term = (81 * 2) / 11 = 173 And, so on....

- In general, Nth number is obtained by formula:

Below is the implementation of the above approach:

## C++

`// C++ program to find the Nth term` `// in series 12, 35, 81, 173, 357, ...` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Function to find Nth term` `int` `nthTerm(` `int` `N)` `{` ` ` `int` `nth = 0, first_term = 12;` ` ` `// Nth term` ` ` `nth = (first_term * (` `pow` `(2, N - 1)))` ` ` `+ 11 * ((` `pow` `(2, N - 1)) - 1);` ` ` `return` `nth;` `}` `// Driver Method` `int` `main()` `{` ` ` `int` `N = 5;` ` ` `cout << nthTerm(N) << endl;` ` ` `return` `0;` `}` |

## Java

`// Java program to find the Nth term` `// in series 12, 35, 81, 173, 357, ...` `class` `GFG` `{` `// Function to find Nth term` `static` `int` `nthTerm(` `int` `N)` `{` ` ` `int` `nth = ` `0` `, first_term = ` `12` `;` ` ` `// Nth term` ` ` `nth = (` `int` `) ((first_term * (Math.pow(` `2` `, N - ` `1` `)))` ` ` `+ ` `11` `* ((Math.pow(` `2` `, N - ` `1` `)) - ` `1` `));` ` ` `return` `nth;` `}` `// Driver code` `public` `static` `void` `main(String[] args)` `{` ` ` `int` `N = ` `5` `;` ` ` `System.out.print(nthTerm(N) +` `"\n"` `);` `}` `}` `// This code is contributed by Rajput-Ji` |

## Python3

`# Python3 program to find the Nth term` `# in series 12, 35, 81, 173, 357, ...` `# Function to find Nth term` `def` `nthTerm(N) :` ` ` `nth ` `=` `0` `; first_term ` `=` `12` `;` ` ` `# Nth term` ` ` `nth ` `=` `(first_term ` `*` `(` `pow` `(` `2` `, N ` `-` `1` `))) ` `+` `\` ` ` `11` `*` `((` `pow` `(` `2` `, N ` `-` `1` `)) ` `-` `1` `);` ` ` `return` `nth;` `# Driver Method` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `N ` `=` `5` `;` ` ` `print` `(nthTerm(N)) ;` `# This code is contributed by AnkitRai01` |

## C#

`// C# program to find the Nth term` `// in series 12, 35, 81, 173, 357, ...` `using` `System;` `class` `GFG` `{` `// Function to find Nth term` `static` `int` `nthTerm(` `int` `N)` `{` ` ` `int` `nth = 0, first_term = 12;` ` ` `// Nth term` ` ` `nth = (` `int` `) ((first_term * (Math.Pow(2, N - 1)))` ` ` `+ 11 * ((Math.Pow(2, N - 1)) - 1));` ` ` `return` `nth;` `}` `// Driver code` `public` `static` `void` `Main(String[] args)` `{` ` ` `int` `N = 5;` ` ` `Console.Write(nthTerm(N) +` `"\n"` `);` `}` `}` `// This code is contributed by PrinciRaj1992` |

## Javascript

`<script>` ` ` `// Javascript program to find the Nth term` ` ` `// in series 12, 35, 81, 173, 357, ...` ` ` ` ` `// Function to find Nth term` ` ` `function` `nthTerm(N)` ` ` `{` ` ` `let nth = 0, first_term = 12;` ` ` `// Nth term` ` ` `nth = (first_term * (Math.pow(2, N - 1)))` ` ` `+ 11 * ((Math.pow(2, N - 1)) - 1);` ` ` `return` `nth;` ` ` `}` ` ` ` ` `let N = 5;` ` ` `document.write(nthTerm(N));` `// This code is contributed by divyeshrabadiya07.` `</script>` |

**Output:**

357

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