# Find the Nth term in series 12, 35, 81, 173, 357, …

Given a number N, the task is to find the Nth term in series 12, 35, 81, 173, 357, …

Example:

```Input: N = 2
Output: 35
2nd term = (12*2) + 11
= 35

Input: N = 5
Output: 357
5th term = (12*(2^4))+11*((2^4)-1)
= 357
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

Below is the implementation of the above approach:

## C++

 `// C++ program to find the Nth term ` `// in series 12, 35, 81, 173, 357, ... ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to find Nth term ` `int` `nthTerm(``int` `N) ` `{ ` `    ``int` `nth = 0, first_term = 12; ` ` `  `    ``// Nth term ` `    ``nth = (first_term * (``pow``(2, N - 1))) ` `          ``+ 11 * ((``pow``(2, N - 1)) - 1); ` ` `  `    ``return` `nth; ` `} ` ` `  `// Driver Method ` `int` `main() ` `{ ` `    ``int` `N = 5; ` `    ``cout << nthTerm(N) << endl; ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find the Nth term ` `// in series 12, 35, 81, 173, 357, ... ` `class` `GFG ` `{ ` ` `  `// Function to find Nth term ` `static` `int` `nthTerm(``int` `N) ` `{ ` `    ``int` `nth = ``0``, first_term = ``12``; ` ` `  `    ``// Nth term ` `    ``nth = (``int``) ((first_term * (Math.pow(``2``, N - ``1``))) ` `        ``+ ``11` `* ((Math.pow(``2``, N - ``1``)) - ``1``)); ` ` `  `    ``return` `nth; ` `} ` ` `  `// Driver code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `N = ``5``; ` `    ``System.out.print(nthTerm(N) +``"\n"``); ` `} ` `} ` ` `  `// This code is contributed by Rajput-Ji `

## Python3

 `# Python3 program to find the Nth term  ` `# in series 12, 35, 81, 173, 357, ...  ` ` `  `# Function to find Nth term  ` `def` `nthTerm(N) : ` ` `  `    ``nth ``=` `0``; first_term ``=` `12``;  ` ` `  `    ``# Nth term  ` `    ``nth ``=` `(first_term ``*` `(``pow``(``2``, N ``-` `1``))) ``+` `\ ` `            ``11` `*` `((``pow``(``2``, N ``-` `1``)) ``-` `1``);  ` ` `  `    ``return` `nth;  ` ` `  `# Driver Method  ` `if` `__name__ ``=``=` `"__main__"` `:  ` ` `  `    ``N ``=` `5``;  ` `    ``print``(nthTerm(N)) ;  ` ` `  `# This code is contributed by AnkitRai01 `

## C#

 `// C# program to find the Nth term ` `// in series 12, 35, 81, 173, 357, ... ` `using` `System; ` ` `  `class` `GFG ` `{ ` ` `  `// Function to find Nth term ` `static` `int` `nthTerm(``int` `N) ` `{ ` `    ``int` `nth = 0, first_term = 12; ` ` `  `    ``// Nth term ` `    ``nth = (``int``) ((first_term * (Math.Pow(2, N - 1))) ` `        ``+ 11 * ((Math.Pow(2, N - 1)) - 1)); ` ` `  `    ``return` `nth; ` `} ` ` `  `// Driver code ` `public` `static` `void` `Main(String[] args) ` `{ ` `    ``int` `N = 5; ` `    ``Console.Write(nthTerm(N) +``"\n"``); ` `} ` `} ` ` `  `// This code is contributed by PrinciRaj1992 `

Output:

```357
```

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