# Find the Nth digit from right in base B of the given number in Decimal base

Given a number A in decimal base, the task is to find the Nth digit from last in base B

Examples:

Input: A = 100, N = 3, B = 4
Output: 2
Explanation:
(100)4 = 1210
3rd digit from last is 2

Input: A = 50, N = 3, B = 5
Output: 2
Explanation:
(50)5 = 200
3rd digit from last is 2

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: The idea is to skip (N-1) digits of the given number in base B by dividing the number with B, (N – 1) times and then return the modulo of the current number by the B to get the Nth digit from the right.

Below is the implementation of the above approach:

## C++

 `// C++ Implementation to find Nth digit ` `// from right in base B ` ` `  `#include ` `using` `namespace` `std; ` ` `  `// Function to compute Nth digit ` `// from right in base B ` `int` `nthDigit(``int` `a, ``int` `n, ``int` `b) ` `{ ` ` `  `    ``// Skip N-1 Digits in Base B ` `    ``for` `(``int` `i = 1; i < n; i++) ` `        ``a = a / b; ` ` `  `    ``// Nth Digit from right in Base B ` `    ``return` `a % b; ` `} ` ` `  `// Driver Code ` `int` `main() ` `{ ` `    ``int` `a = 100; ` `    ``int` `n = 3; ` `    ``int` `b = 4; ` `    ``cout << nthDigit(a, n, b); ` `    ``return` `0; ` `} `

## Java

 `// Java Implementation to find Nth digit ` `// from right in base B ` `import` `java.util.*; ` ` `  `class` `GFG ` `{ ` ` `  `// Function to compute Nth digit ` `// from right in base B ` `static` `int` `nthDigit(``int` `a, ``int` `n, ``int` `b) ` `{ ` ` `  `    ``// Skip N-1 Digits in Base B ` `    ``for` `(``int` `i = ``1``; i < n; i++) ` `        ``a = a / b; ` ` `  `    ``// Nth Digit from right in Base B ` `    ``return` `a % b; ` `} ` ` `  `// Driver Code ` `public` `static` `void` `main(String[] args) ` `{ ` `    ``int` `a = ``100``; ` `    ``int` `n = ``3``; ` `    ``int` `b = ``4``; ` `    ``System.out.print(nthDigit(a, n, b)); ` `} ` `} ` ` `  `// This code is contributed by PrinciRaj1992 `

## Python3

 `# Ptyhon3 Implementation to find Nth digit ` `# from right in base B ` ` `  `# Function to compute Nth digit ` `# from right in base B ` `def` `nthDigit(a, n, b): ` ` `  `    ``# Skip N-1 Digits in Base B ` `    ``for` `i ``in` `range``(``1``, n): ` `        ``a ``=` `a ``/``/` `b ` ` `  `    ``# Nth Digit from right in Base B ` `    ``return` `a ``%` `b ` ` `  `# Driver Code ` `a ``=` `100` `n ``=` `3` `b ``=` `4` `print``(nthDigit(a, n, b)) ` ` `  `# This code is contributed by ApurvaRaj `

## C#

 `// C# Implementation to find Nth digit ` `// from right in base B ` `using` `System; ` ` `  `class` `GFG ` `{ ` ` `  `    ``// Function to compute Nth digit ` `    ``// from right in base B ` `    ``static` `int` `nthDigit(``int` `a, ``int` `n, ``int` `b) ` `    ``{ ` `     `  `        ``// Skip N-1 Digits in Base B ` `        ``for` `(``int` `i = 1; i < n; i++) ` `            ``a = a / b; ` `     `  `        ``// Nth Digit from right in Base B ` `        ``return` `a % b; ` `    ``} ` `     `  `    ``// Driver Code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `a = 100; ` `        ``int` `n = 3; ` `        ``int` `b = 4; ` `        ``Console.Write(nthDigit(a, n, b)); ` `    ``} ` `} ` ` `  `// This code is contributed by AnkitRai01 `

Output:

```2
```

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