# Find the node whose absolute difference with X gives minimum value

Given a tree, and the weights of all the nodes and an integer **x**, the task is to find a node **i** such that **|weight[i] – x|** is minimum.

**Examples:**

Input:

x = 15

Output:3

Node 1: |5 – 15| = 10

Node 2: |10 – 15| = 5

Node 3: |11 -15| = 4

Node 4: |8 – 15| = 7

Node 5: |6 -15| = 9

**Approach:** Perform dfs on the tree and keep track of the node whose weighted absolute difference with **x** gives the minimum value.

Below is the implementation of the above approach:

`// C++ implementation of the approach ` `#include <bits/stdc++.h> ` `using` `namespace` `std; ` ` ` `int` `minimum = INT_MAX, x, ans; ` ` ` `vector<` `int` `> graph[100]; ` `vector<` `int` `> weight(100); ` ` ` `// Function to perform dfs to find ` `// the minimum value ` `void` `dfs(` `int` `node, ` `int` `parent) ` `{ ` ` ` `// If current value is less than ` ` ` `// the current minimum ` ` ` `if` `(minimum > ` `abs` `(weight[node] - x)) { ` ` ` `minimum = ` `abs` `(weight[node] - x); ` ` ` `ans = node; ` ` ` `} ` ` ` `for` `(` `int` `to : graph[node]) { ` ` ` `if` `(to == parent) ` ` ` `continue` `; ` ` ` `dfs(to, node); ` ` ` `} ` `} ` ` ` `// Driver code ` `int` `main() ` `{ ` ` ` `x = 15; ` ` ` ` ` `// Weights of the node ` ` ` `weight[1] = 5; ` ` ` `weight[2] = 10; ` ` ` `weight[3] = 11; ` ` ` `weight[4] = 8; ` ` ` `weight[5] = 6; ` ` ` ` ` `// Edges of the tree ` ` ` `graph[1].push_back(2); ` ` ` `graph[2].push_back(3); ` ` ` `graph[2].push_back(4); ` ` ` `graph[1].push_back(5); ` ` ` ` ` `dfs(1, 1); ` ` ` ` ` `cout << ans; ` ` ` ` ` `return` `0; ` `} ` |

*chevron_right*

*filter_none*

**Output:**

3

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