Find the Next perfect square greater than a given number

Given a number N, the task is to find the next perfect square greater than N.

Examples:

Input: N = 6
Output: 9
9 is a greater number than 6 and
is also a perfect square

Input: N = 9
Output: 16

Approach:

  1. Find the square root of given N.
  2. Calculate its floor value using floor function in C++.
  3. Then add 1 to it.
  4. Print square of that number.

Below is the implementation of above approach:

C++

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// C++ implementation of above approach
#include <iostream>
#include<cmath>
using namespace std;
  
// Function to find the next perfect square
int nextPerfectSquare(int N)
{
    int nextN = floor(sqrt(N)) + 1;
  
    return nextN * nextN;
}
  
// Driver Code
int main()
{
    int n = 35;
  
    cout << nextPerfectSquare(n);
    return 0;
}

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Java














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// Java implementation of above approach 


import java.util.*; 


import java.lang.*; 


import java.io.*; 


  


class GFG 


{ 


      


// Function to find the 


// next perfect square 


static int nextPerfectSquare(int N) 


{ 


    int nextN = (int)Math.floor(Math.sqrt(N)) + 1; 


  


    return nextN * nextN; 


} 


  


// Driver Code 


public static void main(String args[]) 


{ 


    int n = 35; 


  


    System.out.println (nextPerfectSquare(n)); 


} 


} 


  


// This code is contributed by Subhadeep 



















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Python3














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# Python3 implementation of above approach 


  


import math 


#Function to find the next perfect square 


  


def nextPerfectSquare(N): 


  


    nextN = math.floor(math.sqrt(N)) + 1


  


    return nextN * nextN 


  


if __name__=='__main__': 


    N = 35


    print(nextPerfectSquare(N)) 


  


# this code is contributed by Surendra_Gangwar 



















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C#














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// C# implementation of above approach 


using System; 


  


class GFG 


{ 


      


// Function to find the 


// next perfect square 


static int nextPerfectSquare(int N) 


{ 


    int nextN = (int)Math.Floor(Math.Sqrt(N)) + 1; 


  


    return nextN * nextN; 


} 


  


// Driver Code 


public static void Main() 


{ 


    int n = 35; 


  


    Console.WriteLine(nextPerfectSquare(n)); 


} 


} 


  


// This code is contributed  


// by Shashank 



















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PHP














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<?php 


// PHP implementation  


// of above approach 


  


// Function to find the 


// next perfect square 


function nextPerfectSquare($N) 


{ 


    $nextN = floor(sqrt($N)) + 1; 


  


    return $nextN * $nextN; 


} 


  


// Driver Code 


$n = 35; 


  


echo nextPerfectSquare($n); 


  


// This code is contributed by mits 


?> 



















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Output:


36






          
          
          
          

            

    

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