# Find the character made by adding all the characters of the given string

Given a string str consisting of lowercase English alphabets. The task is to add all the character values i.e. ‘a’ = 1, ‘b’ = 2, ‘c’ = 3, …, ‘z’ = 26 and output the character corresponding to the sum value. If it exceeds 26 then take sum % 26.

Examples:

Input: str = “gfg”
Output: t
(g + f + g) = 7 + 6 + 7 = 20 and t = 20

Input: str = “geeks”
Output: u

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

1. Find the sum of all character of the string and store it in a variable sum.
2. If sum % 26 = 0 then print ‘z’.
3. Else update sum = sum % 26 and print (sum + ‘a’ + 1).

Below is the implementation of the above approach:

## C++

 // C++ implementation of the approach #include using namespace std;    // Function to return the required character char getChar(string str) {        // To store the sum of the characters     // of the given string     int sum = 0;        for (int i = 0; i < str.length(); i++) {            // Add the current character to the sum         sum += (str[i] - 'a' + 1);     }        // Return the requried character     if (sum % 26 == 0)         return 'z';     else {         sum = sum % 26;         return (char)('a' + sum - 1);     } }    // Driver code int main() {     string str = "gfg";        cout << getChar(str);        return 0; }

## Java

 // Java implementation of the approach  class GFG {        // Function to return the required character  static char getChar(String str)  {         // To store the sum of the characters      // of the given string      int sum = 0;         for (int i = 0; i < str.length(); i++)      {             // Add the current character to the sum          sum += (str.charAt(i) - 'a' + 1);      }         // Return the requried character      if (sum % 26 == 0)          return 'z';      else      {          sum = sum % 26;          return (char)('a' + sum - 1);      }  }     // Driver code  public static void main (String[] args)  {      String str = "gfg";         System.out.println(getChar(str));  }  }    // This code is contributed by AnkitRai01

## Python3

 # Python3 implementation of the approach    # Function to return the required character def getChar(strr):        # To store the summ of the characters     # of the given strring     summ = 0        for i in range(len(strr)):            # Add the current character to the summ         summ += (ord(strr[i]) - ord('a') + 1)        # Return the requried character     if (summ % 26 == 0):         return ord('z')     else:         summ = summ % 26         return chr(ord('a') + summ - 1)    # Driver code strr = "gfg"    print(getChar(strr))    # This code is contributed by Mohit Kumar

## C#

 // C# implementation of the approach  using System;    class GFG {        // Function to return the required character  static char getChar(String str)  {         // To store the sum of the characters      // of the given string      int sum = 0;         for (int i = 0; i < str.Length; i++)      {             // Add the current character to the sum          sum += (str[i] - 'a' + 1);      }         // Return the requried character      if (sum % 26 == 0)          return 'z';      else     {          sum = sum % 26;          return (char)('a' + sum - 1);      }  }     // Driver code  public static void Main (String[] args)  {      String str = "gfg";         Console.WriteLine(getChar(str));  }  }        // This code is contributed by PrinciRaj1992

Output:

t

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