Find the character made by adding all the characters of the given string

Given a string str consisting of lowercase English alphabets. The task is to add all the character values i.e. ‘a’ = 1, ‘b’ = 2, ‘c’ = 3, …, ‘z’ = 26 and output the character corresponding to the sum value. If it exceeds 26 then take sum % 26.

Examples:

Input: str = “gfg”
Output: t
(g + f + g) = 7 + 6 + 7 = 20 and t = 20



Input: str = “geeks”
Output: u

Approach:

  1. Find the sum of all character of the string and store it in a variable sum.
  2. If sum % 26 = 0 then print ‘z’.
  3. Else update sum = sum % 26 and print (sum + ‘a’ + 1).

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
// Function to return the required character
char getChar(string str)
{
  
    // To store the sum of the characters
    // of the given string
    int sum = 0;
  
    for (int i = 0; i < str.length(); i++) {
  
        // Add the current character to the sum
        sum += (str[i] - 'a' + 1);
    }
  
    // Return the requried character
    if (sum % 26 == 0)
        return 'z';
    else {
        sum = sum % 26;
        return (char)('a' + sum - 1);
    }
}
  
// Driver code
int main()
{
    string str = "gfg";
  
    cout << getChar(str);
  
    return 0;
}

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Java

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// Java implementation of the approach 
class GFG
{
      
// Function to return the required character 
static char getChar(String str) 
  
    // To store the sum of the characters 
    // of the given string 
    int sum = 0
  
    for (int i = 0; i < str.length(); i++) 
    
  
        // Add the current character to the sum 
        sum += (str.charAt(i) - 'a' + 1); 
    
  
    // Return the requried character 
    if (sum % 26 == 0
        return 'z'
    else 
    
        sum = sum % 26
        return (char)('a' + sum - 1); 
    
  
// Driver code 
public static void main (String[] args) 
    String str = "gfg"
  
    System.out.println(getChar(str)); 
}
  
// This code is contributed by AnkitRai01

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Python3

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# Python3 implementation of the approach
  
# Function to return the required character
def getChar(strr):
  
    # To store the summ of the characters
    # of the given strring
    summ = 0
  
    for i in range(len(strr)):
  
        # Add the current character to the summ
        summ += (ord(strr[i]) - ord('a') + 1)
  
    # Return the requried character
    if (summ % 26 == 0):
        return ord('z')
    else:
        summ = summ % 26
        return chr(ord('a') + summ - 1)
  
# Driver code
strr = "gfg"
  
print(getChar(strr))
  
# This code is contributed by Mohit Kumar

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C#

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// C# implementation of the approach 
using System;
  
class GFG
{
      
// Function to return the required character 
static char getChar(String str) 
  
    // To store the sum of the characters 
    // of the given string 
    int sum = 0; 
  
    for (int i = 0; i < str.Length; i++) 
    
  
        // Add the current character to the sum 
        sum += (str[i] - 'a' + 1); 
    
  
    // Return the requried character 
    if (sum % 26 == 0) 
        return 'z'
    else
    
        sum = sum % 26; 
        return (char)('a' + sum - 1); 
    
  
// Driver code 
public static void Main (String[] args) 
    String str = "gfg"
  
    Console.WriteLine(getChar(str)); 
}
      
// This code is contributed by PrinciRaj1992

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Output:

t


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