Given a linked list, the task is to find the balanced node in a linked list. A balanced node is a node where the sum of all the nodes on its left is equal to the sum of all the node on its right, if no such node is found then print -1.
Input: 1 -> 2 -> 7 -> 10 -> 1 -> 6 -> 3 -> NULL
Sum of nodes on the left of 10 is 1 + 2 + 7 = 10
And, to the right of 10 is 1 + 6 + 3 = 10
Input: 1 -> 5 -> 5 -> 10 -> -3 -> NULL
- First, find the total sum of the all node values.
- Now, traverse the linked list one by one and while traversing keep track of all the previous nodes value sum and find the sum of the remaining node by subtracting current node value and the sum of the previous nodes value from the total sum.
- Compare both the sums, if they are equal then current node is the required node else print -1.
Below is the implementation of the above approach:
Time Complexity: O(n)
- Find the fractional (or n/k - th) node in linked list
- Find first node of loop in a linked list
- Find modular node in a linked list
- Find the largest node in Doubly linked list
- Find the second last node of a linked list in single traversal
- Find kth node from Middle towards Head of a Linked List
- Recursive Approach to find nth node from the end in the linked list
- Create new linked list from two given linked list with greater element at each node
- Sorted Linked List to Balanced BST
- Swap Kth node from beginning with Kth node from end in a Linked List
- Linked List | Set 3 (Deleting a node)
- Remove last node of the linked list
- Linked List | Set 2 (Inserting a node)
- Delete Nth node from the end of the given linked list
- Remove first node of the linked list
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