# Find the balanced node in a Linked List

Given a linked list, the task is to find the balanced node in a linked list. A balanced node is a node where the sum of all the nodes on its left is equal to the sum of all the node on its right, if no such node is found then print -1.

Examples:

Input: 1 -> 2 -> 7 -> 10 -> 1 -> 6 -> 3 -> NULL
Output: 10
Sum of nodes on the left of 10 is 1 + 2 + 7 = 10
And, to the right of 10 is 1 + 6 + 3 = 10

Input: 1 -> 5 -> 5 -> 10 -> -3 -> NULL
Output: -1

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach:

• First, find the total sum of the all node values.
• Now, traverse the linked list one by one and while traversing keep track of all the previous nodes value sum and find the sum of the remaining node by subtracting current node value and the sum of the previous nodes value from the total sum.
• Compare both the sums, if they are equal then current node is the required node else print -1.

Below is the implementation of the above approach:

 `# Python3 implementation of the approach ` `import` `sys ` `import` `math ` ` `  `# Structure of a node of linked list  ` `class` `Node: ` `    ``def` `__init__(``self``, data): ` `        ``self``.``next` `=` `None` `        ``self``.data ``=` `data ` ` `  `# Push the new node to front of the linked list ` `def` `push(head, data): ` ` `  `    ``# Return new node as head if head is empty ` `    ``if` `not` `head: ` `        ``return` `Node(data) ` `    ``temp ``=` `Node(data) ` `    ``temp.``next` `=` `head ` `    ``head ``=` `temp ` `    ``return` `head ` ` `  `# Function to find the balanced node ` `def` `findBalancedNode(head): ` `    ``tsum ``=` `0` `    ``curr_node ``=` `head ` `     `  `    ``# Traverse through all node  ` `    ``# to find the total sum ` `    ``while` `curr_node: ` `        ``tsum``+``=` `curr_node.data ` `        ``curr_node ``=` `curr_node.``next` `     `  `    ``# Set current_sum and remaining sum to zero  ` `    ``current_sum, remaining_sum ``=` `0``, ``0` `    ``curr_node ``=` `head ` ` `  `    ``# Traversing the list to check balanced node ` `    ``while``(curr_node): ` `        ``remaining_sum ``=` `tsum``-``(current_sum ``+` `curr_node.data) ` ` `  `        ``# If sum of the nodes on the left and the current node  ` `        ``# is equal to the sum of the nodes on the right ` `        ``if` `current_sum ``=``=` `remaining_sum: ` `            ``return` `curr_node.data ` `        ``current_sum``+``=` `curr_node.data ` `        ``curr_node ``=` `curr_node.``next` `     `  `    ``return` `-``1` ` `  `# Driver code ` `if` `__name__``=``=``'__main__'``: ` `    ``head ``=` `None` `    ``head ``=` `push(head, ``3``) ` `    ``head ``=` `push(head, ``6``) ` `    ``head ``=` `push(head, ``1``) ` `    ``head ``=` `push(head, ``10``) ` `    ``head ``=` `push(head, ``7``) ` `    ``head ``=` `push(head, ``2``) ` `    ``head ``=` `push(head, ``1``) ` ` `  `    ``print``(findBalancedNode(head)) `

Output:

```10
```

Time Complexity: O(n)

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