# Find the area of the rectangle if the breadth is 19 cm and length is 3 times longer than its breadth.

Rectangle is a closed two-dimensional figure composed of four sides and four vertices. All angles of the rectangle are 90^{0}. A rectangle with all sides equal is equivalent to a square. A rectangle is composed of two pairs of parallel sides, length and breadth respectively.

**Properties of rectangle**

- It has four sides and four angles.
- All the angles are right angles.
- Opposite sides are parallel and equal in length.

**Area of Rectangle**

A rectangle is composed of equal pairs which are parallel in nature and equal in length. The area of a rectangle is the space enclosed within its boundaries. The area of the rectangle is the product of the length and breadth of the rectangle.

Area of rectangle = Length × Breadth

Let us assume A to be the area of the rectangle and l and b to be the length and breadth of the rectangle respectively.

A = l × b

### Find the area of the rectangle if the breadth is 19 cm and the length is 3 times longer than its breadth.

**Solution: **

Let us assume l to be the length of the rectangle and b to be the breadth of the rectangle.

Given values,

dth, b = 19 cmAnd,

Length is three times longer than its breadth.

Length = 3 × Breadth

Length = 3 × 19 cm

Length, l = 57 cm

Now,

Area = Length × Breadth

A = l × b

A = 19 × 57 cm

^{2}A = 1083 cm

^{2}

### Sample Questions

**Question 1: If the area becomes quadruple, keeping the length the** **same, how does the breadth change?**

**Solution:**

Area = length × breadth

Area’ = 4 × Area

Now,

Length’ x Breadth’ = 4 × Length × Breadth

Given , length is constant, length’ = length

Therefore,

Breadth’ = 4 × Breadth

Thus, breadth becomes four times.

**Question 2: The length and breadth are in the** **ratio of 2:3. The area is 12 cm.**

**ulate the length and breadth.**

**Solution :**

Let the item be x. Now length = 2x and breadth = 3x respectively.

We know,

2x × 3x = 12

6x^{2} = 12

x^{2} = 2

x = √2

**Question 3: The breadth of a rectangle is 3 cm. Its length is 2/3 times longer than its breadth. Find the area of the rectangle.**

**Solution:**

Area of rectangle = Length × Breadth

Now, given,

Breadth = 3 cm

Length = 2/3 × Breadth

= 2/3 × 3 cm

= 2 cm

Area = Length × Breadth

= 2 × 3 cm

^{2}= 6 cm

^{2}

**Question 4: Find the area of a rectangle when its length is 4 times its breadth. The breadth of the rectangle is 10 m?<**

**ong>**

**Solution:**

Here we have to find the area of the rectangle

As per the question

Length of the rectangle is 4 times the breadth

Thus,

Length of rectangle = 4 × breadth

Length of rectangle = 4 × 10

Length of rectangle = 40 m

As we know that

Area of rectangle = Length × Breadth

Area of rectangle = 40 × 10

Area of rectangle = 400 m

^{2}Therefore,

Area of rectangle is 400 m

^{2}

**Question 5: The breadth of a rectangle is 4 cm. Its length is two units longer than its breadth. Find the area of the rectangle.**

**Solution:**

Area of rectangle = Length × Breadth

Now, given,

Breadth = 4 cm

Length = Breadth + 2 cm

= 4 cm × 2 cm

= 6 cm

Area = Length × Breadth

= 4 × 6 cm

^{2}= 24 cm

^{2}