Given two integers A and X, denoting the length of a side of a rhombus and an angle respectively, the task is to find the area of the rhombus.
A rhombus is a quadrilateral having 4 sides of equal length, in which both the opposite sides are parallel, and opposite angles are equal.
Input: A = 4, X = 60
Input: A = 4, X = 30
Approach:For a Rhombus ABCD having the length of a side a and an angle x, the area of triangle ABD can be calculated using Side-Angle-Side property of triangle by the following equation:
Area of Triangle ABD = 1/2 (a2) sin x
Area of Rhombus ABCD will be double the area of ABD triangle.
Therefore, Area of Rhombus ABCD = (a2) sin x
Below is the implementation of the above approach:
Time Complexity: O(1)
Auxiliary Space: O(1)
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Improved By : Rajput-Ji