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Find the area of largest circle inscribed in ellipse
  • Last Updated : 18 Mar, 2021

Given an ellipse, with major and minor axis length 2a & 2b respectively. The task is to find the area of the largest circle that can be inscribed in it.
Examples: 
 

Input : a = 5, b = 3
Output : 28.2743

Input : a = 10, b = 8
Output : 201.062

 

 

Circle Inside Ellipse

Approach : The maximal radius of the circle inscribed in the ellipse is the minor axis of the ellipse.
So, area of the largest circle = π * b * b.
Below is the implementation of the above approach: 
 

C++




// CPP program to find
// the area of the circle
#include <bits/stdc++.h>
using namespace std;
#define pi 3.1415926
 
double areaCircle(double b)
{
    double area = pi * b * b;
    return area;
}
 
// Driver Code
int main()
{
    double a = 10, b = 8;
    cout << areaCircle(b);
    return 0;
}

Java




// Java Program to find the area
// of circle
 
class GFG
{
    static double areaCircle(double b)
    {
     
     
        // Area of the Reuleaux triangle
        double area = (double)3.1415926 * b * b;
        return area;
    }
     
    // Driver code
    public static void main(String args[])
    {
        float a = 10,b = 8;
        System.out.println(areaCircle(b)) ;
    }
}
 
// This code is contributed by mohit kumar 29

Python3




# Python3 program implementation of above approach
 
import math
 
# Function to return required answer
def areaCircle(b):
    area = math.pi * b * b
    return area
 
 
# Driver Code
a = 10
b = 8
print(areaCircle(b))
 
# This code is contributed by
# Sanjit_Prasad

C#




// C# Program to find the area
// of circle
using System;
 
class GFG
{
    static double areaCircle(double b)
    {
        // Area of the Reuleaux triangle
        double area = (double)3.1415926 * b * b;
        return area;
    }
     
    // Driver code
    public static void Main()
    {
        float b = 8;
        Console.WriteLine(areaCircle(b)) ;
    }
}
 
// This code is contributed by aishwarya.27

PHP




<?php
// PHP program to find the area of the circle
 
$GLOBALS['pi'] = 3.1415926;
 
function areaCircle($b)
{
    $area = $GLOBALS['pi'] * $b * $b;
    return $area;
}
 
// Driver Code
$a = 10;
$b = 8;
 
echo round(areaCircle($b), 3);
 
// This code is contributed by Ryuga
?>

Javascript




<script>
// Javascript program to find
// the area of the circle
function areaCircle(b)
{
    let area = 3.1415926 * b * b;
    return area;
}
 
// Driver Code
    let a = 10, b = 8;
    document.write(areaCircle(b));
 
// This code is contributed by Mayank Tyagi
</script>
Output: 
201.062

 

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