Given an ellipse, with major and minor axis length 2a & 2b respectively. The task is to find the area of the largest circle that can be inscribed in it.
Input : a = 5, b = 3 Output : 28.2743 Input : a = 10, b = 8 Output : 201.062
Approach : The maximal radius of the circle inscribed in the ellipse is the minor axis of the ellipse.
So, area of the largest circle = π * b * b.
Below is the implementation of the above approach:
- Area of the Largest square that can be inscribed in an ellipse
- Area of Largest rectangle that can be inscribed in an Ellipse
- Area of a triangle inscribed in a rectangle which is inscribed in an ellipse
- Largest ellipse that can be inscribed within a rectangle which in turn is inscribed within a semicircle
- Area of a square inscribed in a circle which is inscribed in an equilateral triangle
- Area of a circle inscribed in a rectangle which is inscribed in a semicircle
- Area of a square inscribed in a circle which is inscribed in a hexagon
- Area of the biggest ellipse inscribed within a rectangle
- Largest triangle that can be inscribed in an ellipse
- Area of the circle that has a square and a circle inscribed in it
- Find area of the larger circle when radius of the smaller circle and difference in the area is given
- Area of circle inscribed within rhombus
- Area of decagon inscribed within the circle
- Area of a circle inscribed in a regular hexagon
- Area of circle which is inscribed in equilateral triangle
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