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Find temperature of missing days using given sum and average

  • Difficulty Level : Basic
  • Last Updated : 01 Apr, 2021
Geek Week

Given integers x and y which denotes the average temperature of the week except for days Day1 and Day2 respectively, and the sum of the temperature of Day1 and Day2 as S, the task is to find the temperature of the days Day1 and Day2.
Examples: 
 

Input: x = 15, y = 10, S = 50 
Output: Day1 = 10, Day2 = 40 
Explanation: 
The average of week excluding Day1 is 15, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 50. Individual temperature of the two days are 10 and 40 respecticvely.
Input: x = 5, y = 10, s = 40 
Output: Day1 = 35, Day2 = 5 
Explanation: 
The average of week excluding Day1 is 5, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 40. Individual temperature of the two days are 35 and 5 respecticvely. 
 

 

Approach: We know that Average = sum of all observation / total number of observation. Hence, the sum of observation = Average * number of observation i.e., S = A * n
 

So after excluding Day1 or Day2 we are left with only 6 days 
so N = 6 and the equations are: 
 



total - Day1 = 6 * x
 

and 
 

total - Day2 = 6 * y
 

on subtracting the above two equations we get, 
 

Day2 - Day1 = ( x - y ) * 6
 

(Equation 1) 
and it is given in the problem statement that 
 

Day2 + Day1 = S
 

(Equation 2) 
 



 

Solving the above two equations, the value of Day1 and Day2 is given by: 
 

Day2 = \frac{(S +(x-y)*6)}{2}   [Tex]Day1 = S – Day2  [/Tex]

Below is the implementation of above approach:
 

C++




// C++ program for the above approach
 
#include <bits/stdc++.h>
using namespace std;
 
// Function for finding the temperature
void findTemperature(int x, int y, int s)
{
    double Day1, Day2;
 
    // Store Day1 - Day2 in diff
    double diff = (x - y) * 6;
 
    Day2 = (diff + s) / 2;
 
    // Remaining from s will be Day1
    Day1 = s - Day2;
 
    // Print Day1 and Day2
    cout << "Day1 : " << Day1 << endl;
    cout << "Day2 : " << Day2 << endl;
}
 
// Driver Code
int main()
{
    int x = 5, y = 10, s = 40;
 
    // Functions
    findTemperature(x, y, s);
 
    return 0;
}

Java




// Java program for the above approach
class GFG{
  
// Function for finding the temperature
static void findTemperature(int x, int y, int s)
{
    double Day1, Day2;
  
    // Store Day1 - Day2 in diff
    double diff = (x - y) * 6;
  
    Day2 = (diff + s) / 2;
  
    // Remaining from s will be Day1
    Day1 = s - Day2;
  
    // Print Day1 and Day2
    System.out.println( "Day1 : " + Day1);
    System.out.println( "Day2 : " + Day2);
}
  
// Driver Code
public static void main(String[] args)
{
    int x = 5, y = 10, s = 40;
  
    // Functions
    findTemperature(x, y, s);
}
}
 
// This code is contributed by rock_cool

Python




# Python3 program for the above approach
 
# Function for finding the temperature
def findTemperature(x, y, s):
 
    # Store Day1 - Day2 in diff
    diff = (x - y) * 6
    Day2 = (diff + s) // 2
 
    # Remaining from s will be Day1
    Day1 = s - Day2
 
    # Print Day1 and Day2
    print("Day1 : ", Day1)
    print("Day2 : ", Day2)
 
# Driver Code
if __name__ == '__main__':
    x = 5
    y = 10
    s = 40
 
    # Functions
    findTemperature(x, y, s)
 
# This code is contributed by Mohit Kumar

C#




// C# program for the above approach
using System;
class GFG{
   
// Function for finding the temperature
static void findTemperature(int x, int y, int s)
{
    double Day1, Day2;
   
    // Store Day1 - Day2 in diff
    double diff = (x - y) * 6;
   
    Day2 = (diff + s) / 2;
   
    // Remaining from s will be Day1
    Day1 = s - Day2;
   
    // Print Day1 and Day2
    Console.Write( "Day1 : " + Day1 + '\n');
    Console.WriteLine( "Day2 : " + Day2 + '\n');
}
   
// Driver Code
public static void Main(string[] args)
{
    int x = 5, y = 10, s = 40;
   
    // Functions
    findTemperature(x, y, s);
}
}
 
// This code is contributed by Ritik Bansal

Javascript




<script>
 
    // Javascript program for the above approach
     
    // Function for finding the temperature
    function findTemperature(x, y, s)
    {
        let Day1, Day2;
 
        // Store Day1 - Day2 in diff
        let diff = (x - y) * 6;
 
        Day2 = (diff + s) / 2;
 
        // Remaining from s will be Day1
        Day1 = s - Day2;
 
        // Print Day1 and Day2
        document.write("Day1 : " + Day1 + "</br>");
        document.write("Day2 : " + Day2 + "</br>");
    }
 
    let x = 5, y = 10, s = 40;
   
    // Functions
    findTemperature(x, y, s);
     
</script>

 

Output: 
Day1 : 35
Day2 : 5

 

 

Time Complexity: O(1) 
Auxiliary Space: O(1)
 

 

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