Find temperature of missing days using given sum and average
Given integers x and y which denotes the average temperature of the week except for days Day1 and Day2 respectively, and the sum of the temperature of Day1 and Day2 as S, the task is to find the temperature of the days Day1 and Day2.
Input: x = 15, y = 10, S = 50
Output: Day1 = 10, Day2 = 40
The average of week excluding Day1 is 15, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 50. Individual temperature of the two days are 10 and 40 respecticvely.
Input: x = 5, y = 10, s = 40
Output: Day1 = 35, Day2 = 5
The average of week excluding Day1 is 5, the average of week excluding Day2 is 10 and the sum of temperature of Day1 and Day2 is 40. Individual temperature of the two days are 35 and 5 respecticvely.
Approach: We know that Average = sum of all observation / total number of observation. Hence, the sum of observation = Average * number of observation i.e., S = A * n
So after excluding Day1 or Day2 we are left with only 6 days
so N = 6 and the equations are:
on subtracting the above two equations we get,
and it is given in the problem statement that
Solving the above two equations, the value of Day1 and Day2 is given by:
[Tex]Day1 = S – Day2 [/Tex]
Below is the implementation of above approach:
Day1 : 35 Day2 : 5
Time Complexity: O(1)
Auxiliary Space: O(1)