# Find ratio of zeroes, positive numbers and negative numbers in the Array

Given an array a of integers of size N integers, the task is to find the ratio of positive numbers, negative numbers and zeros in the array up to four decimal places.

Examples:

Input: a[] = {2, -1, 5, 6, 0, -3}
Output: 0.5000 0.3333 0.1667
There are 3 positive, 2 negative, and 1 zero. Their ratio would be positive: 3/6 = 0.5000, negative: 2/6 = 0.3333, and zero: 1/6 = 0.1667.

Input: a[] = {4, 0, -2, -9, -7, 1}
Output: 0.3333 0.5000 0.1667
There are 2 positive, 3 negative, and 1 zero. Their ratio would be positive: 2/6 = 0.3333, negative: 3/6 = 0.5000, and zero: 1/6 = 0.1667.

Approach:

1. Count the total number of positive elements in the array.
2. Count the total number of negative elements in the array.
3. Count the total number of zero elements in the array.
4. Divide the total number of positive elements, negative elements, and zero elements by the size of the array, to get the ratio.
5. Print the ratio of positive, negative, and zero elements in the array up to four decimal places.

Below is the implementation of the above approach.

## C++

 `// C++ program to find the ratio of positive,` `// negative, and zero elements in the array.` `#include` `using` `namespace` `std;`     `// Function to find the ratio of` `// positive, negative, and zero elements` `void` `positiveNegativeZero(``int` `arr[], ``int` `len)` `{` `    ``// Initialize the positiveCount, negativeCount, and` `    ``// zeroCountby 0 which will count the total number` `    ``// of positive, negative and zero elements` `    ``float` `positiveCount = 0;` `    ``float` `negativeCount = 0;` `    ``float` `zeroCount = 0;`   `    ``// Traverse the array and count the total number of` `    ``// positive, negative, and zero elements.` `    ``for` `(``int` `i = 0; i < len; i++) {` `        ``if` `(arr[i] > 0) {` `            ``positiveCount++;` `        ``}` `        ``else` `if` `(arr[i] < 0) {` `            ``negativeCount++;` `        ``}` `        ``else` `if` `(arr[i] == 0) {` `            ``zeroCount++;` `        ``}` `    ``}`   `    ``// Print the ratio of positive,` `    ``// negative, and zero elements` `    ``// in the array up to four decimal places.` `    ``cout << fixed << setprecision(4) << (positiveCount / len)<<``" "``;` `    ``cout << fixed << setprecision(4) << (negativeCount / len)<<``" "``;` `    ``cout << fixed << setprecision(4) << (zeroCount / len);` `    ``cout << endl;` `}`   `// Driver Code.` `int` `main()` `{` `    ``// Test Case 1:` `    ``int` `a1[] = { 2, -1, 5, 6, 0, -3 };` `    ``int` `len=``sizeof``(a1)/``sizeof``(a1[0]);` `    ``positiveNegativeZero(a1,len);`   `    ``// Test Case 2:` `    ``int` `a2[] = { 4, 0, -2, -9, -7, 1 };` `    ``len=``sizeof``(a2)/``sizeof``(a2[0]);` `    ``positiveNegativeZero(a2,len);` `}`   `// This code is contributed by chitranayal`

## Java

 `// Java program to find the ratio of positive,` `// negative, and zero elements in the array.`   `class` `GFG {`   `    ``// Function to find the ratio of` `    ``// positive, negative, and zero elements` `    ``static` `void` `positiveNegativeZero(``int``[] arr)` `    ``{`   `        ``// Store the array length into the variable len.` `        ``int` `len = arr.length;`   `        ``// Initialize the positiveCount, negativeCount, and` `        ``// zeroCountby 0 which will count the total number` `        ``// of positive, negative and zero elements` `        ``float` `positiveCount = ``0``;` `        ``float` `negativeCount = ``0``;` `        ``float` `zeroCount = ``0``;`   `        ``// Traverse the array and count the total number of` `        ``// positive, negative, and zero elements.` `        ``for` `(``int` `i = ``0``; i < len; i++) {` `            ``if` `(arr[i] > ``0``) {` `                ``positiveCount++;` `            ``}` `            ``else` `if` `(arr[i] < ``0``) {` `                ``negativeCount++;` `            ``}` `            ``else` `if` `(arr[i] == ``0``) {` `                ``zeroCount++;` `            ``}` `        ``}`   `        ``// Print the ratio of positive,` `        ``// negative, and zero elements` `        ``// in the array up to four decimal places.` `        ``System.out.printf(``"%1.4f "``, positiveCount / len);` `        ``System.out.printf(``"%1.4f "``, negativeCount / len);` `        ``System.out.printf(``"%1.4f "``, zeroCount / len);` `        ``System.out.println();` `    ``}`   `    ``// Driver Code.` `    ``public` `static` `void` `main(String args[])` `    ``{`   `        ``// Test Case 1:` `        ``int``[] a1 = { ``2``, -``1``, ``5``, ``6``, ``0``, -``3` `};` `        ``positiveNegativeZero(a1);`   `        ``// Test Case 2:` `        ``int``[] a2 = { ``4``, ``0``, -``2``, -``9``, -``7``, ``1` `};` `        ``positiveNegativeZero(a2);` `    ``}` `}`

## Python3

 `# Python3 program to find the ratio of positive,` `# negative, and zero elements in the array.`   `# Function to find the ratio of` `# positive, negative, and zero elements` `def` `positiveNegativeZero(arr):`   `    ``# Store the array length into the variable len.` `    ``length ``=` `len``(arr);`   `    ``# Initialize the positiveCount, negativeCount, and` `    ``# zeroCountby 0 which will count the total number` `    ``# of positive, negative and zero elements` `    ``positiveCount ``=` `0``;` `    ``negativeCount ``=` `0``;` `    ``zeroCount ``=` `0``;`   `    ``# Traverse the array and count the total number of` `    ``# positive, negative, and zero elements.` `    ``for` `i ``in` `range``(length):` `        ``if` `(arr[i] > ``0``):` `            ``positiveCount ``+``=` `1``;` `        ``elif``(arr[i] < ``0``):` `            ``negativeCount ``+``=` `1``;` `        ``elif``(arr[i] ``=``=` `0``):` `            ``zeroCount ``+``=` `1``;` `        `  `    ``# Print the ratio of positive,` `    ``# negative, and zero elements` `    ``# in the array up to four decimal places.` `    ``print``(``"{0:.4f}"``.``format``((positiveCount ``/` `length)), end``=``" "``);` `    ``print``(``"%1.4f "``%``(negativeCount ``/` `length), end``=``" "``);` `    ``print``(``"%1.4f "``%``(zeroCount ``/` `length), end``=``" "``);` `    ``print``();`   `# Driver Code.` `if` `__name__ ``=``=` `'__main__'``:`   `    ``# Test Case 1:` `    ``a1 ``=` `[ ``2``, ``-``1``, ``5``, ``6``, ``0``, ``-``3` `];` `    ``positiveNegativeZero(a1);`   `    ``# Test Case 2:` `    ``a2 ``=` `[ ``4``, ``0``, ``-``2``, ``-``9``, ``-``7``, ``1` `];` `    ``positiveNegativeZero(a2);` `    `  `# This code is contributed by Rajput-Ji`

## C#

 `// C# program to find the ratio of positive,` `// negative, and zero elements in the array.` `using` `System;`   `class` `GFG {` ` `  `    ``// Function to find the ratio of` `    ``// positive, negative, and zero elements` `    ``static` `void` `positiveNegativeZero(``int``[] arr)` `    ``{` ` `  `        ``// Store the array length into the variable len.` `        ``int` `len = arr.Length;` ` `  `        ``// Initialize the positiveCount, negativeCount, and` `        ``// zeroCountby 0 which will count the total number` `        ``// of positive, negative and zero elements` `        ``float` `positiveCount = 0;` `        ``float` `negativeCount = 0;` `        ``float` `zeroCount = 0;` ` `  `        ``// Traverse the array and count the total number of` `        ``// positive, negative, and zero elements.` `        ``for` `(``int` `i = 0; i < len; i++) {` `            ``if` `(arr[i] > 0) {` `                ``positiveCount++;` `            ``}` `            ``else` `if` `(arr[i] < 0) {` `                ``negativeCount++;` `            ``}` `            ``else` `if` `(arr[i] == 0) {` `                ``zeroCount++;` `            ``}` `        ``}` ` `  `        ``// Print the ratio of positive,` `        ``// negative, and zero elements` `        ``// in the array up to four decimal places.` `        ``Console.Write(``"{0:F4} "``, positiveCount / len);` `        ``Console.Write(``"{0:F4} "``, negativeCount / len);` `        ``Console.Write(``"{0:F4} "``, zeroCount / len);` `        ``Console.WriteLine();` `    ``}` ` `  `    ``// Driver Code.` `    ``public` `static` `void` `Main(String []args)` `    ``{` ` `  `        ``// Test Case 1:` `        ``int``[] a1 = { 2, -1, 5, 6, 0, -3 };` `        ``positiveNegativeZero(a1);` ` `  `        ``// Test Case 2:` `        ``int``[] a2 = { 4, 0, -2, -9, -7, 1 };` `        ``positiveNegativeZero(a2);` `    ``}` `}`   `// This code is contributed by sapnasingh4991`

## Javascript

 ``

Output:

```0.5000 0.3333 0.1667
0.3333 0.5000 0.1667```

Time Complexity: O(len)

Auxiliary Space: O(1)

Feeling lost in the world of random DSA topics, wasting time without progress? It's time for a change! Join our DSA course, where we'll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 geeks!

Previous
Next