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Find ratio of zeroes, positive numbers and negative numbers in the Array

  • Last Updated : 23 Apr, 2021

Given an array a of integers of size N integers, the task is to find the ratio of positive numbers, negative numbers and zeros in the array up to four decimal places.

Examples: 

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Input: a[] = {2, -1, 5, 6, 0, -3} 
Output: 0.5000 0.3333 0.1667 
There are 3 positive, 2 negative, and 1 zero. Their ratio would be positive: 3/6 = 0.5000, negative: 2/6 = 0.3333, and zero: 1/6 = 0.1667.



Input: a[] = {4, 0, -2, -9, -7, 1} 
Output: 0.3333 0.5000 0.1667 
There are 2 positive, 3 negative, and 1 zero. Their ratio would be positive: 2/6 = 0.3333, negative: 3/6 = 0.5000, and zero: 1/6 = 0.1667. 

Approach:  

  1. Count the total number of positive elements in the array.
  2. Count the total number of negative elements in the array.
  3. Count the total number of zero elements in the array.
  4. Divide the total number of positive elements, negative elements, and zero elements by the size of the array, to get the ratio.
  5. Print the ratio of positive, negative, and zero elements in the array up to four decimal places.

Below is the implementation of the above approach.  

C++




// C++ program to find the ratio of positive,
// negative, and zero elements in the array.
#include<bits/stdc++.h>
using namespace std;
 
 
// Function to find the ratio of
// positive, negative, and zero elements
void positiveNegativeZero(int arr[], int len)
{
    // Initialize the postiveCount, negativeCount, and
    // zeroCountby 0 which will count the total number
    // of positive, negative and zero elements
    float positiveCount = 0;
    float negativeCount = 0;
    float zeroCount = 0;
 
    // Traverse the array and count the total number of
    // positive, negative, and zero elements.
    for (int i = 0; i < len; i++) {
        if (arr[i] > 0) {
            positiveCount++;
        }
        else if (arr[i] < 0) {
            negativeCount++;
        }
        else if (arr[i] == 0) {
            zeroCount++;
        }
    }
 
    // Print the ratio of positive,
    // negative, and zero elements
    // in the array up to four decimal places.
    cout << fixed << setprecision(4) << (positiveCount / len)<<" ";
    cout << fixed << setprecision(4) << (negativeCount / len)<<" ";
    cout << fixed << setprecision(4) << (zeroCount / len);
    cout << endl;
}
 
// Driver Code.
int main()
{
    // Test Case 1:
    int a1[] = { 2, -1, 5, 6, 0, -3 };
    int len=sizeof(a1)/sizeof(a1[0]);
    positiveNegativeZero(a1,len);
 
    // Test Case 2:
    int a2[] = { 4, 0, -2, -9, -7, 1 };
    len=sizeof(a2)/sizeof(a2[0]);
    positiveNegativeZero(a2,len);
}
 
// This code is contributed by chitranayal

Java




// Java program to find the ratio of positive,
// negative, and zero elements in the array.
 
class GFG {
 
    // Function to find the ratio of
    // positive, negative, and zero elements
    static void positiveNegativeZero(int[] arr)
    {
 
        // Store the array length into the variable len.
        int len = arr.length;
 
        // Initialize the postiveCount, negativeCount, and
        // zeroCountby 0 which will count the total number
        // of positive, negative and zero elements
        float positiveCount = 0;
        float negativeCount = 0;
        float zeroCount = 0;
 
        // Traverse the array and count the total number of
        // positive, negative, and zero elements.
        for (int i = 0; i < len; i++) {
            if (arr[i] > 0) {
                positiveCount++;
            }
            else if (arr[i] < 0) {
                negativeCount++;
            }
            else if (arr[i] == 0) {
                zeroCount++;
            }
        }
 
        // Print the ratio of positive,
        // negative, and zero elements
        // in the array up to four decimal places.
        System.out.printf("%1.4f ", positiveCount / len);
        System.out.printf("%1.4f ", negativeCount / len);
        System.out.printf("%1.4f ", zeroCount / len);
        System.out.println();
    }
 
    // Driver Code.
    public static void main(String args[])
    {
 
        // Test Case 1:
        int[] a1 = { 2, -1, 5, 6, 0, -3 };
        positiveNegativeZero(a1);
 
        // Test Case 2:
        int[] a2 = { 4, 0, -2, -9, -7, 1 };
        positiveNegativeZero(a2);
    }
}

Python3




# Python3 program to find the ratio of positive,
# negative, and zero elements in the array.
 
# Function to find the ratio of
# positive, negative, and zero elements
def positiveNegativeZero(arr):
 
    # Store the array length into the variable len.
    length = len(arr);
 
    # Initialize the postiveCount, negativeCount, and
    # zeroCountby 0 which will count the total number
    # of positive, negative and zero elements
    positiveCount = 0;
    negativeCount = 0;
    zeroCount = 0;
 
    # Traverse the array and count the total number of
    # positive, negative, and zero elements.
    for i in range(length):
        if (arr[i] > 0):
            positiveCount += 1;
        elif(arr[i] < 0):
            negativeCount += 1;
        elif(arr[i] == 0):
            zeroCount += 1;
         
    # Print the ratio of positive,
    # negative, and zero elements
    # in the array up to four decimal places.
    print("{0:.4f}".format((positiveCount / length)), end=" ");
    print("%1.4f "%(negativeCount / length), end=" ");
    print("%1.4f "%(zeroCount / length), end=" ");
    print();
 
# Driver Code.
if __name__ == '__main__':
 
    # Test Case 1:
    a1 = [ 2, -1, 5, 6, 0, -3 ];
    positiveNegativeZero(a1);
 
    # Test Case 2:
    a2 = [ 4, 0, -2, -9, -7, 1 ];
    positiveNegativeZero(a2);
     
# This code is contributed by Rajput-Ji

C#




// C# program to find the ratio of positive,
// negative, and zero elements in the array.
using System;
 
class GFG {
  
    // Function to find the ratio of
    // positive, negative, and zero elements
    static void positiveNegativeZero(int[] arr)
    {
  
        // Store the array length into the variable len.
        int len = arr.Length;
  
        // Initialize the postiveCount, negativeCount, and
        // zeroCountby 0 which will count the total number
        // of positive, negative and zero elements
        float positiveCount = 0;
        float negativeCount = 0;
        float zeroCount = 0;
  
        // Traverse the array and count the total number of
        // positive, negative, and zero elements.
        for (int i = 0; i < len; i++) {
            if (arr[i] > 0) {
                positiveCount++;
            }
            else if (arr[i] < 0) {
                negativeCount++;
            }
            else if (arr[i] == 0) {
                zeroCount++;
            }
        }
  
        // Print the ratio of positive,
        // negative, and zero elements
        // in the array up to four decimal places.
        Console.Write("{0:F4} ", positiveCount / len);
        Console.Write("{0:F4} ", negativeCount / len);
        Console.Write("{0:F4} ", zeroCount / len);
        Console.WriteLine();
    }
  
    // Driver Code.
    public static void Main(String []args)
    {
  
        // Test Case 1:
        int[] a1 = { 2, -1, 5, 6, 0, -3 };
        positiveNegativeZero(a1);
  
        // Test Case 2:
        int[] a2 = { 4, 0, -2, -9, -7, 1 };
        positiveNegativeZero(a2);
    }
}
 
// This code is contributed by sapnasingh4991

Javascript




<script>
 
// Javascript program to find the
// ratio of positive, negative, and
// zero elements in the array.
 
// Function to find the ratio of
// positive, negative, and zero elements
function positiveNegativeZero(arr)
{
     
    // Store the array length into
    // the variable len.
    let len = arr.length;
 
    // Initialize the postiveCount,
    // negativeCount, and zeroCountby
    // 0 which will count the total number
    // of positive, negative and zero elements
    let positiveCount = 0;
    let negativeCount = 0;
    let zeroCount = 0;
 
    // Traverse the array and count the
    // total number of positive, negative,
    // and zero elements.
    for(let i = 0; i < len; i++)
    {
        if (arr[i] > 0)
        {
            positiveCount++;
        }
        else if (arr[i] < 0)
        {
            negativeCount++;
        }
        else if (arr[i] == 0)
        {
            zeroCount++;
        }
    }
 
    // Print the ratio of positive,
    // negative, and zero elements
    // in the array up to four decimal places.
    document.write((positiveCount / len).toFixed(4) + " ");
    document.write((negativeCount / len).toFixed(4) + " ");
    document.write((zeroCount / len).toFixed(4));
    document.write("<br>");
}
 
// Driver Code.
 
// Test Case 1:
let a1 = [ 2, -1, 5, 6, 0, -3 ];
positiveNegativeZero(a1);
 
// Test Case 2:
let a2 = [ 4, 0, -2, -9, -7, 1 ];
positiveNegativeZero(a2);
 
// This code is contributed by sravan kumar G
 
</script>
Output: 
0.5000 0.3333 0.1667 
0.3333 0.5000 0.1667

 

Time Complexity: O(len)

Auxiliary Space: O(1)




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