# Find Range Value of the Expression

Given two integers L and R, the task is to calculate the value of the expression:

Examples:

Input: L = 6, R = 12
Output: 0.09

Input: L = 5, R = 6
Output: 0.06

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach: It can be observed that .

So,

Hence, the answer will be (1 / L) – (1 / (R + 1)).

Below is the implementation of the above approach:

## C++

 // C++ implementation of the approach  #include  using namespace std;     // Function to return the value  // of the given expression  double get(double L, double R)  {         // Value of the first term      double x = 1.0 / L;         // Value of the last term      double y = 1.0 / (R + 1.0);         return (x - y);  }     // Driver code  int main()  {      int L = 6, R = 12;         // Get the result      double ans = get(L, R);      cout << fixed << setprecision(2) << ans;         return 0;  }

## Java

 // Java implementation of the approach  import java.util.*;     class GFG  {     // Function to return the value  // of the given expression  static double get(double L, double R)  {         // Value of the first term      double x = 1.0 / L;         // Value of the last term      double y = 1.0 / (R + 1.0);         return (x - y);  }     // Driver code  public static void main(String []args)  {      int L = 6, R = 12;         // Get the result      double ans = get(L, R);      System.out.printf( "%.2f", ans);  }  }     // This code is contributed by Surendra_Gangwar

## Python3

 # Python3 implementation of the approach     # Function to return the value   # of the given expression   def get(L, R) :         # Value of the first term       x = 1.0 / L;          # Value of the last term       y = 1.0 / (R + 1.0);          return (x - y);      # Driver code   if __name__ == "__main__" :          L = 6; R = 12;          # Get the result       ans = get(L, R);       print(round(ans, 2));      # This code is contributed by AnkitRai01

## C#

        // C# implementation of the approach  using System;     public class GFG  {      // Function to return the value  // of the given expression  static double get(double L, double R)  {          // Value of the first term      double x = 1.0 / L;          // Value of the last term      double y = 1.0 / (R + 1.0);          return (x - y);  }      // Driver code  public static void Main(String []args)  {      int L = 6, R = 12;          // Get the result      double ans = get(L, R);      Console.Write( "{0:F2}", ans);  }  }     // This code contributed by PrinciRaj1992

Output:

0.09


Time Complexity: O(1)

My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Article Tags :
Practice Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.