Given an integer n, we need to find a range of positive integers such that all the number in that range are composite and length of that range is n. You may print anyone range in the case of more than one answer. A composite number is a positive integer that has at least one divisor other than 1 and itself (Source : wiki )

**Examples :**

Input : 3 Output : [122, 124] Explanation 122, 123, 124 are all composite numbers

The solution is little tricky. Since there are many possible answers, we discuss a generalized solution here.

Let the length of range be n and range starts from a then, a, a+1, a+2, ...., a+n-1 all should be composite. So the problem boils down to finding such 'a'. If we closely observe p! (where p is a positive integers) then we will find that, p! has factors of 2, 3, 4, ..., p-1, Hence if we add i to p! such that 1 < i < p, then p! + i has a factor i, so p! + i must be composite. So we end up finding p! + 2, p! + 3, .... p! + p-1 are all composite and continuous integers forming a range [p! + 2, p! + p-1] The above range consists of p-2 elements. For a range of n elements we need to consider (n+2)!If we take a = (n+2)! + 2,Then, a + 1 = (n+2)! + 3 Then, a + 2 = (n+2)! + 4 ... Then, a + n-1 = (n+2)! + n+1 Hence, a = (n+2)! + 2 = 2*3*....*(n+2) + 2 a has 2 as its divisor because (n+2)! and 2 both divides 2 a + 1 = 2*3*....*(n+2) + 3 a + 1 has 3 as its divisor because (n+2)! and 3 both divides 3 ... a + n-1 = 2*3*....*(n+2) + n+1 a + n-1 has n+1 as its divisor because (n+2)! and n+1 both divides n+1 Therefore range will be [ (n+2)! + 2, ( (n+2)! + 2 ) + n-1]

Example for above algorithm

n = 3 Then a = (n+2)! + 2 a = 5! + 2 a + 1 = 5! + 3 a + 2 = 5! + 4 Here a is divisible by 2 Here a + 1 is divisible by 3 Here a + 2 is divisible by 4 Hence a, a+1, a+2 are all composites

## C++

`// C++ program to find a range of` `// composite numbers of given length` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// method to find factorial` `// of given number` `int` `factorial (` `int` `n)` `{` ` ` `if` `(n == 0)` ` ` `return` `1;` ` ` `return` `n * factorial(n-1);` `}` `// to print range of length n` `// having all composite integers` `int` `printRange(` `int` `n)` `{` `int` `a = factorial(n + 2) + 2;` `int` `b = a + n - 1;` `cout << ` `"["` `<< a << ` `", "` `<< b << ` `"]"` `;` `return` `0;` `}` `// Driver method` `int` `main()` `{` ` ` `int` `n = 3 ;` ` ` `printRange(n);` ` ` `return` `0;` `}` `// This code is contributed by Anshika Goyal` |

## Java

`// Java program to find a range of composite` `// numbers of given length` `class` `Test` `{` ` ` `// method to find factorial of given number` ` ` `static` `int` `factorial(` `int` `n)` ` ` `{` ` ` `if` `(n == ` `0` `)` ` ` `return` `1` `;` ` ` ` ` `return` `n*factorial(n-` `1` `);` ` ` `}` ` ` ` ` `// to print range of length n` ` ` `// having all composite integers` ` ` `static` `void` `printRange(` `int` `n)` ` ` `{` ` ` `int` `a = factorial(n + ` `2` `) + ` `2` `;` ` ` `int` `b = a + n - ` `1` `;` ` ` `System.out.println(` `"["` `+ a + ` `", "` `+ b + ` `"]"` `);` ` ` `}` ` ` ` ` `// Driver method` ` ` `public` `static` `void` `main(String args[]) ` `throws` `Exception` ` ` `{` ` ` `int` `n = ` `3` `;` ` ` `printRange(n);` ` ` `}` `}` |

## Python

`# Python program to find a range of composite` `# numbers of given length` `# function to calculate factorial` `def` `factorial(n):` ` ` `a ` `=` `1` ` ` `for` `i ` `in` `range` `(` `2` `, n ` `+` `1` `):` ` ` `a ` `*` `=` `i` ` ` `return` `a` `# to print range of length n` `# having all composite integers` `def` `printRange(n):` ` ` `a ` `=` `factorial(n ` `+` `2` `) ` `+` `2` ` ` `b ` `=` `a ` `+` `n ` `-` `1` ` ` `print` `(` `"["` `+` `str` `(a)` `+` `", "` `+` `str` `(b)` `+` `"]"` `)` `# driver code to test above functions` `n ` `=` `3` `printRange(n)` |

## C#

`// C# program to find a range of` `// composite numbers of given` `// length` `using` `System;` `class` `GFG {` ` ` ` ` `// method to find factorial` ` ` `// of given number` ` ` `static` `int` `factorial(` `int` `n)` ` ` `{` ` ` `if` `(n == 0)` ` ` `return` `1;` ` ` ` ` `return` `n*factorial(n-1);` ` ` `}` ` ` ` ` `// to print range of length n` ` ` `// having all composite integers` ` ` `static` `void` `printRange(` `int` `n)` ` ` `{` ` ` `int` `a = factorial(n + 2) + 2;` ` ` `int` `b = a + n - 1;` ` ` `Console.WriteLine(` `"["` `+ a +` ` ` `", "` `+ b + ` `"]"` `);` ` ` `}` ` ` ` ` `// Driver method` ` ` `public` `static` `void` `Main()` ` ` `{` ` ` `int` `n = 3 ;` ` ` `printRange(n);` ` ` `}` `}` `// This code is contributed by anuj_67.` |

## PHP

`<?php` `// PHP program to find a range of` `// composite numbers of given length` `// method to find factorial` `// of given number` `function` `factorial ( ` `$n` `)` `{` ` ` `if` `(` `$n` `== 0)` ` ` `return` `1;` ` ` `return` `$n` `* factorial(` `$n` `- 1);` `}` `// to print range of length n` `// having all composite integers` `function` `printRange(` `$n` `)` `{` `$a` `= factorial(` `$n` `+ 2) + 2;` `$b` `= ` `$a` `+ ` `$n` `- 1;` `echo` `"["` `, ` `$a` `, ` `", "` `, ` `$b` `, ` `"]"` `;` `return` `0;` `}` `// Driver Code` `$n` `= 3 ;` `printRange(` `$n` `);` `// This code is contributed by anuj_67.` `?>` |

## Javascript

`<script>` ` ` `// Javascript program to find a range of` `// composite numbers of given length` `// Method to find factorial` `// of given number` `function` `factorial(n)` `{` ` ` `if` `(n == 0)` ` ` `return` `1;` ` ` `return` `n * factorial(n - 1);` `}` `// To print range of length n` `// having all composite integers` `function` `printRange(n)` `{` ` ` `let a = factorial(n + 2) + 2;` ` ` `let b = a + n - 1;` ` ` ` ` `document.write(`[${a}, ${b}]`);` ` ` ` ` `return` `0;` `}` `// Driver Code` `let n = 3;` `printRange(n);` `// This code is contributed by _saurabh_jaiswal.` `</script>` |

**Output :**

[122, 124]

**Analysis of above algorithm**

Time Complexity : O(n)

Auxiliary Space : O(1)

This article is contributed by **Pratik Chhajer**. If you like GeeksforGeeks and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

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