A string contains patterns of the form 1(0+)1 where (0+) represents any non-empty consecutive sequence of 0’s. Count all such patterns. The patterns are allowed to overlap.
Note : It contains digits and lowercase characters only. The string is not necessarily a binary. 100201 is not a valid pattern.
One approach to solve the problem is discussed here, other using Regular expressions is given in Set 2
Input : 1101001 Output : 2 Input : 100001abc101 Output : 2
Let size of input string be n.
1. Iterate through index ‘0’ to ‘n-1’.
2. If we encounter a ‘1’, we iterate till the elements are ‘0’.
3. After the stream of zeros ends, we check whether we encounter a ‘1’ or not.
4. Keep on doing this till we reach the end of string.
Below is the implementation of the above method.
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- Find all the patterns of "1(0+)1" in a given string | SET 2(Regular Expression Approach)
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- Check if a binary string has a 0 between 1s or not | Set 2 (Regular Expression Approach)
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- Check if a given string is a valid number (Integer or Floating Point) in Java | SET 2 (Regular Expression approach)
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Improved By : nitin mittal