Related Articles
Find other two sides and angles of a right angle triangle
• Difficulty Level : Hard
• Last Updated : 03 May, 2021

Given one side of right angle triangle, check if there exists a right angle triangle possible with any other two sides of the triangle. If possible print length of the other two sides and all the angles of the triangle. Examples:

Input : a = 12
Output : Sides are a = 12, b = 35, c = 37
Angles are A = 18.9246, B = 71.0754, C = 90
Explanation: a = 12, b = 35 and c = 37 form right
angle triangle because
12*12 + 35*35 = 37*37
Input : a = 6
Output : Sides are a = 6, b = 8, c = 10
Angles are A = 36.8699, B = 53.1301, C = 90

Approach to check if triangle exists and finding Sides
To solve this problem we first observe the Pythagoras equation. If a and b are the lengths of the legs of a right triangle and c is the length of the hypotenuse, then the sum of the squares of the lengths of the legs is equal to the square of the length of the hypotenuse.
This relationship is represented by the formula:

a*a + b*b = c*c

Case 1: a is an odd number: Given a, find b and c

c2 - b2 = a2
OR
c = (a2 + 1)/2;
b = (a2 - 1)/2;

Above solution works only for case when a is odd, because a2 + 1 is divisible by 2 only for odd a.
Case 2 : a is an even number: When c-b is 2 & c+b is (a2)/2

c-b = 2 & c+b = (a2)/2
Hence,
c = (a2)/4 + 1;
b = (a2)/4 - 1;

This works when a is even.
Approach to find Angles
First find all sides of triangle. Then Applied “SSS” rule that’s means law of cosine: Below is the implementation of the above approach:

## C++

 // C++ program to print all sides and angles of right// angle triangle given one side#include #include using namespace std; #define PI 3.1415926535 // Function to find angle A// Angle in front of side adouble findAnglesA(double a, double b, double c){    // applied cosine rule    double A = acos((b * b + c * c - a * a) / (2 * b * c));     // convert into degrees    return A * 180 / PI;} // Function to find angle B// Angle in front of side bdouble findAnglesB(double a, double b, double c){    // applied cosine rule    double B = acos((a * a + c * c - b * b) / (2 * a * c));     // convert into degrees and return    return B * 180 / PI;} // Function to print all angles// of the right angled trianglevoid printAngles(int a, int b, int c){    double x = (double)a;    double y = (double)b;    double z = (double)c;         // for calculate angle A    double A = findAnglesA(x, y, z);         // for calculate angle B    double B = findAnglesB(x, y, z);         cout << "Angles are A = " << A << ", B = " <<                        B << ", C = " << 90 << endl;} // Function to find other two sides of the// right angled trianglevoid printOtherSides(int n){      int b,c;         // if n is odd    if (n & 1)    {        // case of n = 1 handled separately        if (n == 1)            cout << -1 << endl;        else        {            b = (n*n-1)/2;            c = (n*n+1)/2;            cout << "Side b = " << b                << ", Side c = " << c << endl;        }    }    else    {        // case of n = 2 handled separately        if (n == 2)            cout << -1 << endl;        else        {            b = n*n/4-1;            c = n*n/4+1;            cout << "Side b = " << b                << ", Side c = " << c << endl;        }    }         // Print angles of the triangle    printAngles(n,b,c);} // Driver Programint main(){    int a = 12;     printOtherSides(a);         return 0;}

## Java

 // Java program to print all sides and angles of right// angle triangle given one side  import java.io.*; class GFG {   static double  PI = 3.1415926535; // Function to find angle A// Angle in front of side astatic double findAnglesA(double a, double b, double c){    // applied cosine rule    double A = Math.acos((b * b + c * c - a * a) / (2 * b * c));     // convert into degrees    return A * 180 / PI;} // Function to find angle B// Angle in front of side bstatic double findAnglesB(double a, double b, double c){    // applied cosine rule    double B = Math.acos((a * a + c * c - b * b) / (2 * a * c));     // convert into degrees and return    return B * 180 / PI;} // Function to print all angles// of the right angled trianglestatic void printAngles(int a, int b, int c){    double x = (double)a;    double y = (double)b;    double z = (double)c;         // for calculate angle A    double A = findAnglesA(x, y, z);         // for calculate angle B    double B = findAnglesB(x, y, z);         System.out.println( "Angles are A = " + A + ", B = " +                        B + ", C = " + 90);} // Function to find other two sides of the// right angled trianglestatic void printOtherSides(int n){    int b=0,c=0;         // if n is odd    if ((n & 1)>0)    {        // case of n = 1 handled separately        if (n == 1)            System.out.println( -1);        else        {            b = (n*n-1)/2;            c = (n*n+1)/2;            System.out.println( "Side b = " + b                + ", Side c = " + c );        }    }    else    {        // case of n = 2 handled separately        if (n == 2)            System.out.println( -1);        else        {            b = n*n/4-1;            c = n*n/4+1;            System.out.println( "Side b = " + b                + ", Side c = " + c);        }    }         // Print angles of the triangle    printAngles(n,b,c);} // Driver Program      public static void main (String[] args) {    int a = 12;     printOtherSides(a);    }} // This code is contributed// by inder_verma..

## Python 3

 # Python 3 program to print all# sides and angles of right# angle triangle given one sideimport math PI = 3.1415926535 # Function to find angle A# Angle in front of side adef findAnglesA( a, b, c):         # applied cosine rule    A = math.acos((b * b + c * c - a * a) /                              (2 * b * c))     # convert into degrees    return A * 180 / PI # Function to find angle B# Angle in front of side bdef findAnglesB(a, b, c):     # applied cosine rule    B = math.acos((a * a + c * c - b * b) /                              (2 * a * c))     # convert into degrees    # and return    return B * 180 / PI # Function to print all angles# of the right angled triangledef printAngles(a, b, c):     x = a    y = b    z = c         # for calculate angle A    A = findAnglesA(x, y, z)     # for calculate angle B    B = findAnglesB(x, y, z)         print("Angles are A = ", A,          ", B = ", B , ", C = ", "90 ") # Function to find other two sides# of the right angled triangledef printOtherSides(n):         # if n is odd    if (n & 1) :                 # case of n = 1 handled        # separately        if (n == 1):            print("-1")        else:                         b = (n * n - 1) // 2            c = (n * n + 1) // 2            print("Side b = ", b,                  " Side c = ", c)         else:                 # case of n = 2 handled        # separately        if (n == 2) :            print("-1")        else:            b = n * n // 4 - 1;            c = n * n // 4 + 1;            print("Side b = " , b,                  ", Side c = " , c)             # Print angles of the triangle    printAngles(n, b, c) # Driver Codeif __name__ == "__main__":    a = 12     printOtherSides(a) # This code is contributed# by ChitraNayal

## C#

 // C# program to print all sides// and angles of right angle// triangle given one sideusing System; class GFG{static double PI = 3.1415926535; // Function to find angle A// Angle in front of side astatic double findAnglesA(double a,                          double b, double c){    // applied cosine rule    double A = Math.Acos((b * b + c *                          c - a * a) /                         (2 * b * c));     // convert into degrees    return A * 180 / PI;} // Function to find angle B// Angle in front of side bstatic double findAnglesB(double a,                          double b, double c){    // applied cosine rule    double B = Math.Acos((a * a + c *                          c - b * b) /                         (2 * a * c));     // convert into degrees and return    return B * 180 / PI;} // Function to print all angles// of the right angled trianglestatic void printAngles(int a, int b, int c){    double x = (double)a;    double y = (double)b;    double z = (double)c;         // for calculate angle A    double A = findAnglesA(x, y, z);         // for calculate angle B    double B = findAnglesB(x, y, z);         Console.WriteLine( "Angles are A = " +                            A + ", B = " +                        B + ", C = " + 90);} // Function to find other two sides// of the right angled trianglestatic void printOtherSides(int n){    int b = 0, c = 0;         // if n is odd    if ((n & 1) > 0)    {        // case of n = 1 handled separately        if (n == 1)            Console.WriteLine( -1);        else        {            b = (n * n - 1) / 2;            c = (n * n + 1) / 2;            Console.WriteLine( "Side b = " + b                           + ", Side c = " + c);        }    }    else    {        // case of n = 2 handled separately        if (n == 2)            Console.WriteLine( -1);        else        {            b = n * n / 4 - 1;            c = n * n / 4 + 1;            Console.WriteLine( "Side b = " + b +                             ", Side c = " + c);        }    }         // Print angles of the triangle    printAngles(n, b, c);} // Driver Codepublic static void Main (){    int a = 12;         printOtherSides(a);}} // This code is contributed// by inder_verma

## PHP

 

## Javascript

 
Output:
Side b = 35, Side c = 37
Angles are A = 18.9246, B = 71.0754, C = 90

Attention reader! Don’t stop learning now. Get hold of all the important mathematical concepts for competitive programming with the Essential Maths for CP Course at a student-friendly price. To complete your preparation from learning a language to DS Algo and many more,  please refer Complete Interview Preparation Course.

My Personal Notes arrow_drop_up