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Find number of months between two dates in R
• Difficulty Level : Basic
• Last Updated : 21 Apr, 2021

In this article, we will discuss how to Find the number of months between two dates in the R programming language.

Example:

Input: Date_1 = 2020/02/21

Date_2 = 2020/03/21

Output: 1

Explanation: In Date_1 and Date_2 have only one difference in month.

Here we will use seq() function to get the resul. This function is used to create a sequence of elements in a Vector. It takes the length and difference between values as optional argument.

Syntax: length(seq(from=date_1, to=date_2, by=’month’)) -1

Where: seq is function generates a sequence of numbers, from is starting date, to is ending date.

Example 1: In the below example, we are storing two dates in two different variables and by using length(seq(from=date_1, to=date_2, by=’month’)) we are finding a number of months between these two dates.

## R

 `# creating date_1 variable and storing date in it.``date_1<-``as.Date``(``"2020-08-10"``)`` ` `# creating date_2 variable and storing date in it.``date_2<-``as.Date``(``"2020-10-10"``)`` ` `# Here first date will  start from 2020-08-10 and``# end by 2020-10-10.Here incremnt is done by month.``# This three dates  will be geneated as we used``# seq and this dates will be stored in a.  ``a = ``seq``(from = date_1, to = date_2, by = ``'month'``)) `` ` `# Here we are finding length of a and we are subtrating``# 1 because we dont need to include current month.``length``(a)-1`

Output:

`2`

Example 2: Checking with different dates.

## R

 `# creating date_1 variable and storing date in it.``date_1<-``as.Date``(``"2020-01-23"``)`` ` `# creating date_2 variable and storing date in it.``date_2<-``as.Date``(``"2020-9-25"``)`` ` `# Here first date will  start from 2020-01-23``# and end by 2020-9-25.Here incremnt is done ``# by month.This three dates  will be geneated ``# as we used seq and this dates will be stored in a.  ``a=``seq``(from = date_1, to = date_2, by = ``'month'``)) `` ` `# Here we are finding length of a and we are ``# subtrating 1 because we dont need to include ``# current month.``length``(a)-1`

Output:

`8`
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