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Find number of candidates in the Exam

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Given the last rank ‘L’ and the number of candidates at the last rank ‘T’, the task is to find the total number of candidates in the Exam. 

Input: L = 5, T = 1
Output: 5

Input: L = 10, T = 2
Output: 11

Approach: 

  1. Suppose L = 5 and T = 2.
  2. Then there can be many possible rank combinations, like 1, 2, 3, 3, 5, 5.
  3. So now in this, as you can see, the last rank is 5 and there are 2 students at rank 5,
  4. Therefore, the total number of candidates is 6.
  5. This can be understood by a simple formula:
L+T-1

Below is the implementation of the above approach.  

C++




// C++ program to find total number of candidates
// in an Exam from given last rank
// and Number of student at this last rank.
  
#include <iostream>
using namespace std;
  
// Function to find total number of
// Participants in Exam.
int findParticipants(int L, int T)
{
    return (L + T - 1);
}
  
// Driver code
int main()
{
    int L = 10, T = 2;
    cout << findParticipants(L, T);
  
    return 0;
}


Java




// Java program to find total number of
// candidates in an Exam from given last rank 
// and Number of student at this last rank. 
class GFG 
{
  
    // Function to find total number of 
    // Participants in Exam.
    static int findParticipants(int L, int T)
    {
        return (L + T - 1);
    }
  
    // Driver code 
    public static void main(String args[]) 
    {
        int L = 10, T = 2;
        System.out.print(findParticipants(L, T));
    }
}
  
// This code is contributed by Gowtham Yuvaraj


Python3




# Python3 program to find total number 
# of candidates in an Exam from given last rank 
# and Number of student at this last rank. 
  
# Function to find total number of 
# Participants in Exam. 
def findParticipants(L, T) : 
  
    return (L + T - 1); 
  
# Driver code 
if __name__ == "__main__"
  
    L = 10; T = 2
    print(findParticipants(L, T)); 
      
# This code is contributed by AnkitRai01


C#




// C# program to find total number of
// candidates in an Exam from given last rank 
// and Number of student at this last rank. 
using System;
  
class GFG 
{
  
    // Function to find total number of 
    // Participants in Exam.
    static int findParticipants(int L, int T)
    {
        return (L + T - 1);
    }
  
    // Driver code 
    public static void Main() 
    {
        int L = 10, T = 2;
        Console.Write(findParticipants(L, T));
    }
}
  
// This code is contributed by Gowtham Yuvaraj


Javascript




<script>
  
// Javascript program to find total number of candidates
// in an Exam from given last rank
// and Number of student at this last rank.
  
// Function to find total number of
// Participants in Exam.
function findParticipants(L, T)
{
    return (L + T - 1);
}
  
// Driver code
var L = 10, T = 2;
document.write( findParticipants(L, T));
  
</script>


Output: 

11

 

Time complexity: O(1) as constant operations are being performed
Auxiliary Space: O(1)



Last Updated : 13 Mar, 2023
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