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Number of elements greater than modified mean in matrix

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Normally mean of the matrix is the average of all elements present in the matrix. Consider a modified mean as the floor of the mean of the row-wise minimum and column-wise maximum. The row-wise minimum is the minimum element from each row of the given matrix and the column-wise maximum is the maximum element from each column. Given a matrix of order n*m, find the number of elements greater than the new mean obtained.

mean = floor ( (sum(row-wise Min) + sum (col-wise Max )) / 
                                  (row_no. + col_no.) )

Examples :  

Input : mat[][] = {1, 5, 6,
                   2, 3, 0,
                   5, 2, 8}
Output : 4

Input : mat[][] = {1, 5,
                   5, 2}
Output : 2

Find the sum of all row-wise minimums and the sum of all column-wise maximums. Take the mean of this sum by dividing the sum value with (n+m) i.e., the total number of rows and columns. Now, as we have the mean of the row-wise minimum and column-wise maximum, iterate over the matrix to find the number of elements greater than the calculated mean

Below is the implementation of the above approach:

C++




// CPP program to count number of
// elements greater than mean
#include <bits/stdc++.h>
using namespace std;
 
// define constant for row and column
#define n 4
#define m 5
 
// function to count elements
// greater than mean
int countElements(int mat[][m])
{
    // For each row find minimum
    // element and add to rowSum
    int rowSum = 0;
    for (int i = 0; i < n; i++) {
        int min = mat[i][0];
        for (int j = 1; j < m; j++)
            if (mat[i][j] < min)
                min = mat[i][j];
        rowSum += min;
    }
     
    // For each column find maximum
    // element and add to colSum
    int colSum = 0;
    for (int i = 0; i < m; i++) {
        int max = mat[0][i];
        for (int j = 1; j < n; j++)
            if (max < mat[j][i])
                max = mat[j][i];
        colSum += max;
    }
 
    // Calculate mean of row-wise
    // minimum and column wise maximum
    int mean = (rowSum + colSum) / (m + n);
     
    // For whole matrix count
    // elements greater than mean
    int count = 0;
    for (int i = 0; i < n; i++)
        for (int j = 0; j < m; j++)
            if (mean < mat[i][j])
                count++;
    return count;
}
 
// driver function
int main()
{
    int mat[n][m] = { 5, 4, 2, 8, 7,
                      1, 5, 8, 3, 4,
                      8, 5, 4, 6, 0,
                      2, 5, 8, 9, 4 };
    cout << countElements(mat);
    return 0;
}


Java




// Java program to count
// number of elements
// greater than mean
class GFG {
     
    static int n = 4, m = 5;
     
    // function to count
    // elements greater
    // than mean
    static int countElements(int mat[][])
    {
        // For each row find
        // minimum element
        // and add to rowSum
        int rowSum = 0;
        for (int i = 0; i < n; i++)
        {
            int min = mat[i][0];
         
            for (int j = 1; j < m; j++)
                if (mat[i][j] < min)
                    min = mat[i][j];
             
            rowSum += min;
        }
         
        // For each column
        // find maximum
        // element and add
        // to colSum
        int colSum = 0;
        for (int i = 0; i < m; i++) {
            int max = mat[0][i];
         
            for (int j = 1; j < n; j++)
                if (max < mat[j][i])
                    max = mat[j][i];
         
            colSum += max;
        }
     
        // Calculate mean of
        // row-wise minimum
        // and column wise
        // maximum
        int mean = (rowSum + colSum) / (m + n);
         
        // For whole matrix
        // count elements
        // greater than mean
        int count = 0;
        for (int i = 0; i < n; i++)
            for (int j = 0; j < m; j++)
         
                if (mean < mat[i][j])
                    count++;
         
        return count;
    }
     
    // driver function
    public static void main(String[] args)
    {
        int mat[][] = {{ 5, 4, 2, 8, 7},
                        {1, 5, 8, 3, 4},
                        {8, 5, 4, 6, 0},
                        {2, 5, 8, 9, 4}};
        System.out.println(countElements(mat));
    }
}
 
// This article is contribute by Prerna Saini.


Python3




# Python3 program to count
# number of elements
# greater than mean
n = 4;
m = 5;
 
# Function to count
# elements greater
# than mean
def countElements(mat):
   
    # For each row find
    # minimum element
    # and add to rowSum
    rowSum = 0;
     
    for i in range(n):
        min = mat[i][0];
        for j in range(1, m):
            if (mat[i][j] < min):
                min = mat[i][j];
 
        rowSum += min;
 
    # For each column
    # find maximum
    # element and add
    # to colSum
    colSum = 0;
     
    for i in range(m):
        max = mat[0][i];
        for j in range(1, n):
            if (max < mat[j][i]):
                max = mat[j][i];
 
        colSum += max;
 
    # Calculate mean of
    # row-wise minimum
    # and column wise
    # maximum
    mean = ((rowSum + colSum) /
           (m + n));
 
    # For whole matrix
    # count elements
    # greater than mean
    count = 0;
    for i in range(n):
        for j in range(m):
            if (mean < mat[i][j]):
                count += 1;
 
    return count;
 
# Driver code
if __name__ == '__main__':
   
    mat = [[5, 4, 2, 8, 7],
           [1, 5, 8, 3, 4],
           [8, 5, 4, 6, 0],
           [2, 5, 8, 9, 4]];
    print(countElements(mat));
 
# This code is contributed by 29AjayKumar


C#




// C# program to count number of
// elements greater than mean
using System;
 
class GFG {
     
    static int n = 4, m = 5;
     
    // function to count elements
    // greater than mean
    static int countElements(int [,]mat)
    {
        // For each row find minimum
        // element and add to rowSum
        int rowSum = 0;
        for (int i = 0; i < n; i++)
        {
            int min = mat[i,0];
         
            for (int j = 1; j < m; j++)
                if (mat[i,j] < min)
                    min = mat[i,j];
             
            rowSum += min;
        }
         
        // For each column find maximum
        // element and add to colSum
        int colSum = 0;
        for (int i = 0; i < m; i++) {
            int max = mat[0,i];
         
            for (int j = 1; j < n; j++)
                if (max < mat[j,i])
                    max = mat[j,i];
         
            colSum += max;
        }
     
        // Calculate mean of row-wise minimum
        // and column wise maximum
        int mean = (rowSum + colSum) / (m + n);
         
        // For whole matrix count
        // elements greater than mean
        int count = 0;
        for (int i = 0; i < n; i++)
            for (int j = 0; j < m; j++)
         
                if (mean < mat[i,j])
                    count++;
         
        return count;
    }
     
    // Driver function
    public static void Main()
    {
        int [,]mat = {{5, 4, 2, 8, 7},
                      {1, 5, 8, 3, 4},
                      {8, 5, 4, 6, 0},
                      {2, 5, 8, 9, 4}};
    Console.Write(countElements(mat));
    }
}
 
//


PHP




<?php
// PHP program to count number of
// elements greater than mean
 
// define constant for
// row and column
$n = 4;
$m = 5;
 
// function to count elements
// greater than mean
function countElements($mat)
{
     
    // For each row find minimum
    // element and add to rowSum
    $rowSum = 0;
    global $n, $m;
    for ($i = 0; $i < $n; $i++)
    {
        $min = $mat[$i][0];
        for ($j = 1; $j < $m; $j++)
            if ($mat[$i][$j] < $min)
                $min = $mat[$i][$j];
        $rowSum += $min;
    }
     
    // For each column find maximum
    // element and add to colSum
    $colSum = 0;
    for ($i = 0; $i < $m; $i++)
    {
        $max = $mat[0][$i];
        for ($j = 1; $j < $n; $j++)
            if ($max < $mat[$j][$i])
                $max = $mat[$j][$i];
        $colSum += $max;
    }
 
    // Calculate mean of row-wise
    // minimum and column wise maximum
    $mean = ($rowSum + $colSum) / ($m + $n);
     
    // For whole matrix count
    // elements greater than mean
    $count = 0;
    for ($i = 0; $i < $n; $i++)
        for ($j = 0; $j < $m; $j++)
            if ($mean < $mat[$i][$j])
                $count++;
    return $count;
}
 
// Driver Code
$mat = array(array(5, 4, 2, 8, 7),
             array(1, 5, 8, 3, 4),
             array(8, 5, 4, 6, 0),
             array(2, 5, 8, 9, 4));
echo countElements($mat);
// This code is contribute by vt_m.
?>


Javascript




<script>
 
// Javascript program to count number of
// elements greater than mean
 
// define constant for row and column
var n = 4
var m = 5
 
// function to count elements
// greater than mean
function countElements(mat)
{
    // For each row find minimum
    // element and add to rowSum
    var rowSum = 0;
    for (var i = 0; i < n; i++) {
        var min = mat[i][0];
        for (var j = 1; j < m; j++)
            if (mat[i][j] < min)
                min = mat[i][j];
        rowSum += min;
    }
     
    // For each column find maximum
    // element and add to colSum
    var colSum = 0;
    for (var i = 0; i < m; i++) {
        var max = mat[0][i];
        for (var j = 1; j < n; j++)
            if (max < mat[j][i])
                max = mat[j][i];
        colSum += max;
    }
 
    // Calculate mean of row-wise
    // minimum and column wise maximum
    var mean = (rowSum + colSum) / (m + n);
     
    // For whole matrix count
    // elements greater than mean
    var count = 0;
    for (var i = 0; i < n; i++)
        for (var j = 0; j < m; j++)
            if (mean < mat[i][j])
                count++;
    return count;
}
 
// driver function
var mat = [ [5, 4, 2, 8, 7],
                  [1, 5, 8, 3, 4],
                  [8, 5, 4, 6, 0],
                  [2, 5, 8, 9, 4 ]];
document.write( countElements(mat));
 
</script>


Output

11

Time Complexity: O(n*m), where n is the number of rows and m is the number of columns.
Auxiliary Space: O(1)



Last Updated : 20 Mar, 2023
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