Find Nth term of the series 0, 6, 0, 12, 0, 90…

Given a number N. The task is to write a program to find the Nth term in the below series:

0, 6, 0, 12, 0, 90…

Examples:



Input : N = 4
Output : 12
For N = 4
Nth term = abs( 4 * ((4-1) * (4-3) * (4-5)) );
         = 12
Input : N = 6 
Output : 90

We can generalize the Nth term of the above series as:

Nth term = abs( N * ((N-1) * (N-3) * (N-5)) )

Below is the implementation of the above approach:

C++

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// CPP program to find N-th term of the series
// 0, 6, 0, 12, 0, 90...
  
#include <iostream>
using namespace std;
  
// Function to return the Nth term
int nthTerm(int N)
{
    return abs(N * ((N - 1) * (N - 3) * (N - 5)));
}
  
// Driver code
int main()
{
    int N = 6;
  
    cout << nthTerm(N);
  
    return 0;
}

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Java














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// Java program to find N-th term of the series 


// 0, 6, 0, 12, 0, 90... 


  


import java.io.*; 


import java.lang.*; 


  


class GFG { 


    // Function to calculate Nth term of  


    // the series 


    public static int nthTerm(int N) 


    { 


        // By using above formula 


        return Math.abs(N * ((N - 1) * (N - 3) * (N - 5))); 


    } 


      


    // Driver code 


    public static void main(String[] args) 


    { 


        int N = 6; // Nth term is 6 


         


        System.out.println(nthTerm(N)); 


    } 


} 



















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Python3














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# Python3 program to find N-th  


# term of the series  


# 0, 6, 0, 12, 0, 90... 


  


# Function to return the Nth term  


def nthTerm(N) : 


  


    return (abs(N * ((N - 1) * (N - 3)  


           * (N - 5)))) 


  


# Driver code      


if __name__ == "__main__" : 


  


    N = 6


  


    # Function calling 


    print(nthTerm(N)) 


  


  


# This code is contributed by  


# ANKITRAI1 



















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C#














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// C# program to find N-th term of the series 


// 0, 6, 0, 12, 0, 90... 


  


using System; 


  


class GFG { 


    // Function to calculate Nth term of  


    // the series 


    public static int nthTerm(int N) 


    { 


        // By using above formula 


        return Math.Abs(N * ((N - 1) * (N - 3) * (N - 5))); 


    } 


      


    // Driver code 


    public static void Main() 


    { 


        int N = 6; // Nth term is 6 


          


        Console.WriteLine(nthTerm(N)); 


    } 


} 


// This code is contributed by anuj_67. 



















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PHP














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<?php 


// PHP program to find  


// N-th term of the series  


// 0, 6, 0, 12, 0, 90...  


  


// Function to return the Nth term  


function nthTerm( $N)  


{  


    return abs($N * (($N - 1) *  


              ($N - 3) * ($N - 5)));  


}  


  


// Driver code  


$N = 6;  


  


echo nthTerm($N);  


  


// This code is contributed 


// by inder_verma.. 


?> 



















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Output:


90





Time Complexity: O(1)


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