Given first two numbers of series, find n terms of series with these two numbers. The given series follows the same concept as Fibonacci series, i.e., n-th term is sum of (n-1)-th and (n-2)-th terms.
Input: first = 5, sec = 8, n = 5 Output: 5, 8, 13, 21, 34 Input: first = 2, sec = 4, n = 5 Output: 2, 4, 6, 10, 16
The approach is similar to finding Fibonacci series where the summation of last two terms form the next term. Find the sum of first two given numbers, second number now will serve as first number to find the next term and the sum produced will serve as second number to find the next term. Sum of these two newly formed first and second term will form the next required term.
Below is the implementation program:
2 4 6 10 16
Similarly, To find Nth number, generate N terms of series in the above manner and print Nth number.
- Sum of nth terms of Modified Fibonacci series made by every pair of two arrays
- Find the sum of first N terms of the series 2*3*5, 3*5*7, 4*7*9, ...
- Find the sum of first N terms of the series 2×3 + 4×4 + 6×5 + 8×6 + ...
- Find the sum of n terms of the series 1,8,27,64 ....
- Find the sum of all the terms in the n-th row of the given series
- Find Sum of Series 1^2 - 2^2 + 3^2 - 4^2 ..... upto n terms
- Find the sum of series 3, -6, 12, -24 . . . upto N terms
- Find sum of the series ?3 + ?12 +......... upto N terms
- Find the sum of series 0.X + 0.XX + 0.XXX +... upto k terms
- Program to find the sum of the series 23+ 45+ 75+..... upto N terms
- Find sum of the series 1+22+333+4444+...... upto n terms
- Find the sum of the series 1+11+111+1111+..... upto n terms
- Minimum Fibonacci terms with sum equal to K
- Sum of Fibonacci numbers at even indexes upto N terms
- Deriving the expression of Fibonacci Numbers in terms of golden ratio
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