# Find N integers with given difference between product and sum

Given two integers N and D, Find a set of N integers such that difference between their product and sum is equal to D.

Examples :

```Input : N = 2, D = 1
Output : 2 3
Explanation:
product = 2*3 = 6,
Sum = 2 + 3 = 5.
Hence, 6 - 5 = 1(D).

Input : N = 3, D = 5.
Output : 1 2 8
Explanation :
Product = 1*2*8 = 16
Sum = 1+2+8 = 11.
Hence, 16-11 = 5(D).
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

A tricky solution is to keep the difference D to choose N numbers as N-2 ‘1’s, one ‘2’ and one remaining number as ‘N+D’.
Sum = (N-2)*(1) + 2 + (N+D) = 2*N + D.
Product = 1*2*(N+D) = 2*N+2*D
Difference = (2*N+2*D) – (2*N+D) = D.

## C++

 `// CPP code to generate numbers ` `// with difference between ` `// product and sum is D ` `#include ` `using` `namespace` `std; ` ` `  `// Function to implement calculation ` `void` `findNumbers(``int` `n, ``int` `d) ` `{ ` `    ``for` `(``int` `i = 0; i < n - 2; i++) ` `        ``cout << ``"1"`  `<< ``" "``; ` ` `  `    ``cout << ``"2"` `<< ``" "``; ` `    ``cout << n + d << endl; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `N = 3, D = 5; ` `    ``findNumbers(N, D); ` `    ``return` `0; ` `} `

## Java

 `// Java code to generate numbers ` `// with difference between ` `// product and sum is D ` `import` `java.io.*; ` ` `  `class` `GFG { ` `     `  `    ``// Function to implement calculation ` `    ``static` `void` `findNumbers(``int` `n, ``int` `d) ` `    ``{ ` `        ``for` `(``int` `i = ``0``; i < n - ``2``; i++) ` `            ``System.out.print(``"1"` `+ ``" "``); ` `     `  `        ``System.out.print(``"2"` `+ ``" "``); ` `        ``System.out.println(n + d); ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `N = ``3``, D = ``5``; ` `        ``findNumbers(N, D); ` `    ``} ` `} ` ` `  `/* This code is contributed by Nikita Tiwari.*/`

## Python3

 `# Python3 code to generate numbers with ` `# difference between product and sum is D ` ` `  `# Function to implement calculation ` `def` `pattern(n, d) : ` `     `  `    ``for` `i ``in` `range``(``0``, n ``-` `2``) : ` `        ``print``(``"1"``, end``=``" "``) ` `         `  `    ``print``(``"2"``, end``=``" "``) ` `    ``print``(n ``+` `d) ` ` `  `# Driver code ` `N ``=` `3` `D ``=` `5` `pattern(N, D) ` ` `  ` `  `# This code is contributed by 'Akanshgupta' `

## C#

 `// C# code to generate numbers ` `// with difference between ` `// product and sum is D ` `using` `System; ` ` `  `class` `GFG { ` `     `  `    ``// Function to implement calculation ` `    ``static` `void` `findNumbers(``int` `n, ``int` `d) ` `    ``{ ` `        ``for` `(``int` `i = 0; i < n - 2; i++) ` `        ``Console.Write(``"1"` `+ ``" "``); ` `     `  `        ``Console.Write(``"2"` `+ ``" "``); ` `        ``Console.Write(n + d); ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `N = 3, D = 5; ` `        ``findNumbers(N, D); ` `    ``} ` `} ` ` `  `/* This code is contributed by vt_m.*/`

## PHP

 ` `

Output :

``` 1 2 8
```

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.

Improved By : jit_t

Article Tags :

Be the First to upvote.

Please write to us at contribute@geeksforgeeks.org to report any issue with the above content.