Find N Arithmetic Means between A and B

Given three integers A, B and N the task is to find N Arithmetic means between A and B. We basically need to insert N terms in an Arithmetic progression. where A and B are first and last terms.

Examples:


Input : A = 20 B = 32 N = 5
Output : 22 24 26 28 30
The Arithmetic progression series as 
20 22 24 26 28 30 32 

Input : A = 5  B = 35  N = 5
Output : 10 15 20 25 30


Approach :
Let A1, A2, A3, A4……An be N Arithmetic Means between two given numbers A and B . Then A, A1, A2 ….. An, B will be in Arithmetic Progression .
Now B = (N+2)th term of the Arithmetic progression .
So :
Finding the (N+2)th term of the Arithmetic progression Series
where d is the Common Difference

B = A + (N + 2 – 1)d
B – A = (N + 1)d

So the Common Difference d is given by.

d = (B – A) / (N + 1)

So now we have the value of A and the value of the common difference(d),
now we can find all the N Arithmetic Means between A and B.

C++

filter_none

edit
close

play_arrow

link
brightness_4
code

// C++ program to find n arithmetic 
// means between A and B
#include <bits/stdc++.h>
using namespace std;
   
// Prints N arithmetic means between
// A and B.
void printAMeans(int A, int B, int N)
{
    // calculate common difference(d)
    float d = (float)(B - A) / (N + 1);
       
    // for finding N the arithmetic 
    // mean between A and B
    for (int i = 1; i <= N; i++) 
        cout << (A + i * d) <<" ";    
}
   
// Driver code to test above 
int main()
{
    int A = 20, B = 32, N = 5;
    printAMeans(A, B, N);    
    return 0;
}

chevron_right


Java

filter_none

edit
close

play_arrow

link
brightness_4
code

// java program to ilustrate
// n arithmetic mean between 
// A and B
import java.io.*;
import java.lang.*;
import java.util.*;
   
public class GFG {
   
    // insert function for calulating the means
    static void printAMeans(int A, int B, int N)
    {       
        // Finding the value of d Common difference
        float d = (float)(B - A) / (N + 1);
                              
        // for finding N the Arithmetic 
        // mean between A and B
        for (int i = 1; i <= N; i++) 
          System.out.print((A + i * d) + " ");
           
    }
   
    // Driver code
    public static void main(String args[])
    {
        int A = 20, B = 32, N = 5;
        printAMeans(A, B, N);
    }
}

chevron_right


Python3

filter_none

edit
close

play_arrow

link
brightness_4
code

# Python3 program to find n arithmetic
# means between A and B
  
# Prints N arithmetic means 
# between A and B.
def printAMeans(A, B, N):
  
    # Calculate common difference(d)
    d = (B - A) / (N + 1)
      
    # For finding N the arithmetic 
    # mean between A and B
    for i in range(1, N + 1): 
        print(int(A + i * d), end = " "
  
# Driver code
A = 20; B = 32; N = 5
printAMeans(A, B, N) 
  
# This code is contributed by Smitha Dinesh Semwal

chevron_right


C#

filter_none

edit
close

play_arrow

link
brightness_4
code

// C# program to ilustrate
// n arithmetic mean between 
// A and B
using System;
  
public class GFG {
  
    // insert function for calulating the means
    static void printAMeans(int A, int B, int N)
    {     
        // Finding the value of d Common difference
        float d = (float)(B - A) / (N + 1);
                              
        // for finding N the Arithmetic 
        // mean between A and B
        for (int i = 1; i <= N; i++) 
        Console.Write((A + i * d) + " ");
          
    }
  
    // Driver code
    public static void Main()
    {
        int A = 20, B = 32, N = 5;
        printAMeans(A, B, N);
    }
}
// Contributed by vt_m

chevron_right


PHP

filter_none

edit
close

play_arrow

link
brightness_4
code

<?php
// PHP program to find n arithmetic 
// means between A and B
  
// Prints N arithmetic means 
// between A and B.
function printAMeans($A, $B, $N)
{
      
    // calculate common
    // difference(d)
    $d = ($B - $A) / ($N + 1);
      
    // for finding N the arithmetic 
    // mean between A and B
    for ($i = 1; $i <= $N; $i++) 
        echo ($A + $i * $d) ," "
}
  
    // Driver Code 
    $A = 20; $B = 32; 
    $N = 5;
    printAMeans($A, $B, $N);
      
// This code is Contributed by vt_m.
?>

chevron_right


Output:

22 24 26 28 30


My Personal Notes arrow_drop_up

Check out this Author's contributed articles.

If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.

Please Improve this article if you find anything incorrect by clicking on the "Improve Article" button below.



Improved By : vt_m