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# Find N Arithmetic Means between A and B

• Difficulty Level : Medium
• Last Updated : 27 Aug, 2022

Given three integers A, B and N the task is to find N Arithmetic means between A and B. We basically need to insert N terms in an Arithmetic progression. where A and B are first and last terms. Examples:

```Input : A = 20 B = 32 N = 5
Output : 22 24 26 28 30
The Arithmetic progression series as
20 22 24 26 28 30 32

Input : A = 5  B = 35  N = 5
Output : 10 15 20 25 30```

Approach : Let A1, A2, A3, A4……An be N Arithmetic Means between two given numbers A and B . Then A, A1, A2 ….. An, B will be in Arithmetic Progression . Now B = (N+2)th term of the Arithmetic progression . So : Finding the (N+2)th term of the Arithmetic progression Series where d is the Common Difference B = A + (N + 2 – 1)d B – A = (N + 1)d So the Common Difference d is given by. d = (B – A) / (N + 1) So now we have the value of A and the value of the common difference(d), now we can find all the N Arithmetic Means between A and B.

## C++

 `// C++ program to find n arithmetic``// means between A and B``#include ``using` `namespace` `std;`` ` `// Prints N arithmetic means between``// A and B.``void` `printAMeans(``int` `A, ``int` `B, ``int` `N)``{``    ``// calculate common difference(d)``    ``float` `d = (``float``)(B - A) / (N + 1);``     ` `    ``// for finding N the arithmetic``    ``// mean between A and B``    ``for` `(``int` `i = 1; i <= N; i++)``        ``cout << (A + i * d) <<``" "``;   ``}`` ` `// Driver code to test above``int` `main()``{``    ``int` `A = 20, B = 32, N = 5;``    ``printAMeans(A, B, N);   ``    ``return` `0;``}`

## Java

 `// java program to illustrate``// n arithmetic mean between``// A and B``import` `java.io.*;``import` `java.lang.*;``import` `java.util.*;`` ` `public` `class` `GFG {`` ` `    ``// insert function for calculating the means``    ``static` `void` `printAMeans(``int` `A, ``int` `B, ``int` `N)``    ``{      ``        ``// Finding the value of d Common difference``        ``float` `d = (``float``)(B - A) / (N + ``1``);``                            ` `        ``// for finding N the Arithmetic``        ``// mean between A and B``        ``for` `(``int` `i = ``1``; i <= N; i++)``          ``System.out.print((A + i * d) + ``" "``);``         ` `    ``}`` ` `    ``// Driver code``    ``public` `static` `void` `main(String args[])``    ``{``        ``int` `A = ``20``, B = ``32``, N = ``5``;``        ``printAMeans(A, B, N);``    ``}``}`

## Python3

 `# Python3 program to find n arithmetic``# means between A and B` `# Prints N arithmetic means``# between A and B.``def` `printAMeans(A, B, N):` `    ``# Calculate common difference(d)``    ``d ``=` `(B ``-` `A) ``/` `(N ``+` `1``)``    ` `    ``# For finding N the arithmetic``    ``# mean between A and B``    ``for` `i ``in` `range``(``1``, N ``+` `1``):``        ``print``(``int``(A ``+` `i ``*` `d), end ``=` `" "``)` `# Driver code``A ``=` `20``; B ``=` `32``; N ``=` `5``printAMeans(A, B, N)` `# This code is contributed by Smitha Dinesh Semwal`

## C#

 `// C# program to illustrate``// n arithmetic mean between ``// A and B``using` `System;``  ` `public` `class` `GFG {``  ` `    ``// insert function for calculating the means``    ``static` `void` `printAMeans(``int` `A, ``int` `B, ``int` `N)``    ``{     ``        ``// Finding the value of d Common difference``        ``float` `d = (``float``)(B - A) / (N + 1);``                              ` `        ``// for finding N the Arithmetic ``        ``// mean between A and B``        ``for` `(``int` `i = 1; i <= N; i++) ``        ``Console.Write((A + i * d) + ``" "``);``          ` `    ``}``  ` `    ``// Driver code``    ``public` `static` `void` `Main()``    ``{``        ``int` `A = 20, B = 32, N = 5;``        ``printAMeans(A, B, N);``    ``}``}``// Contributed by vt_m`

## PHP

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## Javascript

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Output:

`22 24 26 28 30`

Time Complexity : O(N) ,where N is the number of terms

Space Complexity : O(1), since no extra space has been taken.

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