# Find N Arithmetic Means between A and B

Given three integers A, B and N the task is to find N Arithmetic means between A and B. We basically need to insert N terms in an Arithmetic progression. where A and B are first and last terms.

Examples:

```
Input : A = 20 B = 32 N = 5
Output : 22 24 26 28 30
The Arithmetic progression series as
20 22 24 26 28 30 32

Input : A = 5  B = 35  N = 5
Output : 10 15 20 25 30
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution.

Approach :
Let A1, A2, A3, A4……An be N Arithmetic Means between two given numbers A and B . Then A, A1, A2 ….. An, B will be in Arithmetic Progression .
Now B = (N+2)th term of the Arithmetic progression .
So :
Finding the (N+2)th term of the Arithmetic progression Series
where d is the Common Difference

B = A + (N + 2 – 1)d
B – A = (N + 1)d

So the Common Difference d is given by.

d = (B – A) / (N + 1)

So now we have the value of A and the value of the common difference(d),
now we can find all the N Arithmetic Means between A and B.

## C++

 `// C++ program to find n arithmetic  ` `// means between A and B ` `#include ` `using` `namespace` `std; ` `  `  `// Prints N arithmetic means between ` `// A and B. ` `void` `printAMeans(``int` `A, ``int` `B, ``int` `N) ` `{ ` `    ``// calculate common difference(d) ` `    ``float` `d = (``float``)(B - A) / (N + 1); ` `      `  `    ``// for finding N the arithmetic  ` `    ``// mean between A and B ` `    ``for` `(``int` `i = 1; i <= N; i++)  ` `        ``cout << (A + i * d) <<``" "``;     ` `} ` `  `  `// Driver code to test above  ` `int` `main() ` `{ ` `    ``int` `A = 20, B = 32, N = 5; ` `    ``printAMeans(A, B, N);     ` `    ``return` `0; ` `} `

## Java

 `// java program to illustrate ` `// n arithmetic mean between  ` `// A and B ` `import` `java.io.*; ` `import` `java.lang.*; ` `import` `java.util.*; ` `  `  `public` `class` `GFG { ` `  `  `    ``// insert function for calculating the means ` `    ``static` `void` `printAMeans(``int` `A, ``int` `B, ``int` `N) ` `    ``{        ` `        ``// Finding the value of d Common difference ` `        ``float` `d = (``float``)(B - A) / (N + ``1``); ` `                             `  `        ``// for finding N the Arithmetic  ` `        ``// mean between A and B ` `        ``for` `(``int` `i = ``1``; i <= N; i++)  ` `          ``System.out.print((A + i * d) + ``" "``); ` `          `  `    ``} ` `  `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `A = ``20``, B = ``32``, N = ``5``; ` `        ``printAMeans(A, B, N); ` `    ``} ` `} `

## Python3

 `# Python3 program to find n arithmetic ` `# means between A and B ` ` `  `# Prints N arithmetic means  ` `# between A and B. ` `def` `printAMeans(A, B, N): ` ` `  `    ``# Calculate common difference(d) ` `    ``d ``=` `(B ``-` `A) ``/` `(N ``+` `1``) ` `     `  `    ``# For finding N the arithmetic  ` `    ``# mean between A and B ` `    ``for` `i ``in` `range``(``1``, N ``+` `1``):  ` `        ``print``(``int``(A ``+` `i ``*` `d), end ``=` `" "``)  ` ` `  `# Driver code ` `A ``=` `20``; B ``=` `32``; N ``=` `5` `printAMeans(A, B, N)  ` ` `  `# This code is contributed by Smitha Dinesh Semwal `

## C#

 `// C# program to illustrate ` `// n arithmetic mean between  ` `// A and B ` `using System; ` ` `  `public class GFG { ` ` `  `    ``// insert function for calculating the means ` `    ``static void printAMeans(int A, int B, int N) ` `    ``{      ` `        ``// Finding the value of d Common difference ` `        ``float d = (float)(B - A) / (N + 1); ` `                             `  `        ``// for finding N the Arithmetic  ` `        ``// mean between A and B ` `        ``for (int i = 1; i <= N; i++)  ` `        ``Console.Write((A + i * d) + " "); ` `         `  `    ``} ` ` `  `    ``// Driver code ` `    ``public static void Main() ` `    ``{ ` `        ``int A = 20, B = 32, N = 5; ` `        ``printAMeans(A, B, N); ` `    ``} ` `} ` `// Contributed by vt_m `

## PHP

 ` `

Output:

```22 24 26 28 30
```

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