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Find max or min value in an array of primitives using Java

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Java as a whole is a language that generally requires a lot of coding to execute specific tasks. Hence, having shorthand for several utilities can be beneficial. One such utility, to find maximum and minimum element in array is explained in this article using “aslist()“. aslist() type casts a list from the array passed in its argument. This function is defined in “Java.utils.Arrays“. 
To get the minimum or maximum value from the array we can use the Collections.min() and Collections.max() methods. 
But as this method requires a list type of data we need to convert the array to list first using above explained “aslist()” function.

Note:  “The array you are passing to the Arrays.asList() must have a return type of Integer or whatever class you want to use”, since the Collections.sort() accepts ArrayList object as a parameter. 

Note: If you use type int while declaring the array you will end up seeing this error: “no suitable method found for min(List<int[]>)”


// Java code to demonstrate how to
// extract minimum and maximum number
// in 1 line.
import java.util.Arrays;
import java.util.Collections;
public class MinNMax {
    public static void main(String[] args)
        // Initializing array of integers
        Integer[] num = { 2, 4, 7, 5, 9 };
        // using Collections.min() to
        // find minimum element
        // using only 1 line.
        int min = Collections.min(Arrays.asList(num));
        // using Collections.max()
        // to find maximum element
        // using only 1 line.
        int max = Collections.max(Arrays.asList(num));
        // printing minimum and maximum numbers
        System.out.println("Minimum number of array is : "
                           + min);
        System.out.println("Maximum number of array is : "
                           + max);


Minimum number of array is : 2
Maximum number of array is : 9

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Last Updated : 21 Jun, 2022
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