Given two integers N and K, the task is to find K numbers(A1, A2, …, AK) such that ?i=1KAi is equal to N and ?i=1KAi2 is maximum.
Examples:
Input: N = 3, K = 2
Output: 1 2
Explanation: The two numbers are 1 and 2 as their sum is equal to N and 12 + 22 is maximum.
Input: N = 10, K = 3
Output: 1 8 1
Approach: The idea is to take number 1, K – 1 times and number N – K + 1 once. The sum of these numbers is equal to N and sum of squares of these numbers is always maximum. For any two non-negative numbers a and b, (a2 + b2) is always less than 1 + (a + b – 1)2.
Below is the implementation of the above approach:
// C++ program to find K numbers // with sum equal to N and the // sum of their squares maximized #include <bits/stdc++.h> using namespace std;
// Function that prints the // required K numbers void printKNumbers( int N, int K)
{ // Print 1, K-1 times
for ( int i = 0; i < K - 1; i++)
cout << 1 << " " ;
// Print (N-K+1)
cout << (N - K + 1);
} // Driver Code int main()
{ int N = 10, K = 3;
printKNumbers(N, K);
return 0;
} |
// Java program to find K numbers // with sum equal to N and the // sum of their squares maximized class GFG{
// Function that prints the // required K numbers static void printKNumbers( int N, int K)
{ // Print 1, K-1 times
for ( int i = 0 ; i < K - 1 ; i++)
System.out.print( 1 + " " );
// Print (N - K + 1)
System.out.print(N - K + 1 );
} // Driver Code public static void main(String[] args)
{ int N = 10 , K = 3 ;
printKNumbers(N, K);
} } // This code is contributed by Amit Katiyar |
# Python3 program to find K numbers # with a sum equal to N and the # sum of their squares maximized # Function that prints the # required K numbers def printKNumbers(N, K):
# Print 1, K-1 times
for i in range (K - 1 ):
print ( 1 , end = ' ' )
# Print (N-K+1)
print (N - K + 1 )
# Driver code if __name__ = = '__main__' :
(N, K) = ( 10 , 3 )
printKNumbers(N, K)
# This code is contributed by rutvik_56 |
// C# program to find K numbers // with sum equal to N and the // sum of their squares maximized using System;
class GFG{
// Function that prints the // required K numbers static void printKNumbers( int N, int K)
{ // Print 1, K-1 times
for ( int i = 0; i < K - 1; i++)
Console.Write(1 + " " );
// Print (N - K + 1)
Console.Write(N - K + 1);
} // Driver code public static void Main(String[] args)
{ int N = 10, K = 3;
printKNumbers(N, K);
} } // This code is contributed by shivanisinghss2110 |
<script> // Javascript program to find K numbers
// with sum equal to N and the
// sum of their squares maximized
// Function that prints the
// required K numbers
function printKNumbers(N, K)
{
// Print 1, K-1 times
for (let i = 0; i < K - 1; i++)
document.write(1 + " " );
// Print (N-K+1)
document.write(N - K + 1);
}
let N = 10, K = 3;
printKNumbers(N, K);
</script> |
1 1 8
Time Complexity: O(K)
Auxiliary Space: O(1)