# Find first non matching leaves in two binary trees

Given two binary trees, find first leaves of two trees that do not match. If there are no non-matching leaves, print nothing.

Examples:

```Input : First Tree
5
/   \
2     7
/   \
10     11

Second Tree
6
/    \
10     15

Output : 11 15
If we consider leaves of two trees in order,
we can see that 11 and 15 are the first leaves
that do not match.
```

Method 1 (Simple) :
Do Inorder traversal of both trees one by one, store the leaves of both trees in two different lists. Finally find first values which are different in both lists. Time complexity is O(n1 + n2) where n1 and n2 are number of nodes in two trees. Auxiliary space requirement is O(n1 + n2).

Method 2 (Efficient)
This solution auxiliary space requirement as O(h1 + h2) where h1 and h2 are heights of trees. We do Iterative Preorder traversal of both the trees simultaneously using stacks. We maintain a stack for each tree. For every tree, keep pushing nodes in the stack till the top node is a leaf node. Compare the two top nodes f both the stack. If they are equal, do further traversal else return.

## C++

 `// C++ program to find first leaves that are ` `// not same. ` `#include ` `using` `namespace` `std; ` ` `  `// Tree node ` `struct` `Node ` `{ ` `    ``int` `data; ` `    ``Node *left,  *right; ` `}; ` ` `  `// Utility method to create a new node ` `Node *newNode(``int` `x) ` `{ ` `    ``Node * temp = ``new` `Node; ` `    ``temp->data = x; ` `    ``temp->left = temp->right = NULL; ` `    ``return` `temp; ` `} ` ` `  `bool` `isLeaf(Node * t) ` `{ ` `    ``return` `((t->left == NULL) && (t->right == NULL)); ` `} ` ` `  `// Prints the first non-matching leaf node in ` `// two trees if it exists, else prints nothing. ` `void` `findFirstUnmatch(Node *root1, Node *root2) ` `{ ` `    ``// If any of the tree is empty ` `    ``if` `(root1 == NULL || root2 == NULL) ` `      ``return``; ` ` `  `    ``// Create two stacks for preorder traversals ` `    ``stack s1, s2; ` `    ``s1.push(root1); ` `    ``s2.push(root2); ` ` `  `    ``while` `(!s1.empty() || !s2.empty()) ` `    ``{ ` `        ``// If traversal of one tree is over ` `        ``// and other tree still has nodes. ` `        ``if` `(s1.empty() || s2.empty() ) ` `           ``return``; ` ` `  `        ``// Do iterative traversal of first tree ` `        ``// and find first lead node in it as "temp1" ` `        ``Node *temp1 = s1.top(); ` `        ``s1.pop(); ` `        ``while` `(temp1 && !isLeaf(temp1)) ` `        ``{ ` `            ``// pushing right childfirst so that ` `            ``// left child comes first while popping. ` `            ``s1.push(temp1->right); ` `            ``s1.push(temp1->left); ` `            ``temp1 = s1.top(); ` `            ``s1.pop(); ` `        ``} ` ` `  `        ``// Do iterative traversal of second tree ` `        ``// and find first lead node in it as "temp2" ` `        ``Node * temp2 = s2.top(); ` `        ``s2.pop(); ` `        ``while` `(temp2 && !isLeaf(temp2)) ` `        ``{ ` `            ``s2.push(temp2->right); ` `            ``s2.push(temp2->left); ` `            ``temp2 = s2.top(); ` `            ``s2.pop(); ` `        ``} ` ` `  `        ``// If we found leaves in both trees ` `        ``if` `(temp1 != NULL && temp2 != NULL ) ` `        ``{ ` `            ``if` `(temp1->data != temp2->data ) ` `            ``{ ` `                ``cout << ``"First non matching leaves : "` `                     ``<< temp1->data <<``"  "``<< temp2->data ` `                     ``<< endl; ` `                ``return``; ` `            ``} ` `        ``} ` `    ``} ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``struct` `Node *root1 = newNode(5); ` `    ``root1->left = newNode(2); ` `    ``root1->right = newNode(7); ` `    ``root1->left->left = newNode(10); ` `    ``root1->left->right = newNode(11); ` ` `  `    ``struct` `Node * root2 = newNode(6); ` `    ``root2->left = newNode(10); ` `    ``root2->right = newNode(15); ` ` `  `    ``findFirstUnmatch(root1,root2); ` ` `  `    ``return` `0; ` `} `

## Java

 `// Java program to find first leaves that are  ` `// not same.  ` `import` `java.util.*; ` `class` `GfG { ` ` `  `// Tree node  ` `static` `class` `Node  ` `{  ` `    ``int` `data;  ` `    ``Node left, right;  ` `} ` ` `  `// Utility method to create a new node  ` `static` `Node newNode(``int` `x)  ` `{  ` `    ``Node temp = ``new` `Node();  ` `    ``temp.data = x;  ` `    ``temp.left = ``null``; ` `    ``temp.right = ``null``;  ` `    ``return` `temp;  ` `}  ` ` `  `static` `boolean` `isLeaf(Node t)  ` `{  ` `    ``return` `((t.left == ``null``) && (t.right == ``null``));  ` `}  ` ` `  `// Prints the first non-matching leaf node in  ` `// two trees if it exists, else prints nothing.  ` `static` `void` `findFirstUnmatch(Node root1, Node root2)  ` `{  ` `    ``// If any of the tree is empty  ` `    ``if` `(root1 == ``null` `|| root2 == ``null``)  ` `    ``return``;  ` ` `  `    ``// Create two stacks for preorder traversals  ` `    ``Stack s1 = ``new` `Stack (); ` `    ``Stack s2 = ``new` `Stack ();  ` `    ``s1.push(root1);  ` `    ``s2.push(root2);  ` ` `  `    ``while` `(!s1.isEmpty() || !s2.isEmpty())  ` `    ``{  ` `        ``// If traversal of one tree is over  ` `        ``// and other tree still has nodes.  ` `        ``if` `(s1.isEmpty() || s2.isEmpty() )  ` `        ``return``;  ` ` `  `        ``// Do iterative traversal of first tree  ` `        ``// and find first lead node in it as "temp1"  ` `        ``Node temp1 = s1.peek();  ` `        ``s1.pop();  ` `        ``while` `(temp1 != ``null` `&& isLeaf(temp1) != ``true``)  ` `        ``{  ` `            ``// pushing right childfirst so that  ` `            ``// left child comes first while popping.  ` `            ``s1.push(temp1.right);  ` `            ``s1.push(temp1.left);  ` `            ``temp1 = s1.peek();  ` `            ``s1.pop();  ` `        ``}  ` ` `  `        ``// Do iterative traversal of second tree  ` `        ``// and find first lead node in it as "temp2"  ` `        ``Node temp2 = s2.peek();  ` `        ``s2.pop();  ` `        ``while` `(temp2 != ``null` `&& isLeaf(temp2) != ``true``)  ` `        ``{  ` `            ``s2.push(temp2.right);  ` `            ``s2.push(temp2.left);  ` `            ``temp2 = s2.peek();  ` `            ``s2.pop();  ` `        ``}  ` ` `  `        ``// If we found leaves in both trees  ` `        ``if` `(temp1 != ``null` `&& temp2 != ``null` `)  ` `        ``{  ` `            ``if` `(temp1.data != temp2.data )  ` `            ``{  ` `                ``System.out.println(temp1.data+``" "``+temp2.data);  ` `                ``return``;  ` `            ``}  ` `        ``}  ` `    ``}  ` `}  ` ` `  `// Driver code  ` `public` `static` `void` `main(String[] args)  ` `{  ` `    ``Node root1 = newNode(``5``);  ` `    ``root1.left = newNode(``2``);  ` `    ``root1.right = newNode(``7``);  ` `    ``root1.left.left = newNode(``10``);  ` `    ``root1.left.right = newNode(``11``);  ` ` `  `    ``Node root2 = newNode(``6``);  ` `    ``root2.left = newNode(``10``);  ` `    ``root2.right = newNode(``15``);  ` ` `  `    ``findFirstUnmatch(root1,root2);  ` ` `  `}  ` `}  `

## Python3

 `# Python3 program to find first leaves  ` `# that are not same. ` ` `  `# Tree Node ` `# Utility function to create a  ` `# new tree Node  ` `class` `newNode:  ` `    ``def` `__init__(``self``, data):  ` `        ``self``.data ``=` `data  ` `        ``self``.left ``=` `self``.right ``=` `None` `         `  `def` `isLeaf(t):  ` ` `  `    ``return` `((t.left ``=``=` `None``) ``and`  `            ``(t.right ``=``=` `None``))  ` ` `  `# Prints the first non-matching leaf node in  ` `# two trees if it exists, else prints nothing.  ` `def` `findFirstUnmatch(root1, root2) : ` ` `  `    ``# If any of the tree is empty  ` `    ``if` `(root1 ``=``=` `None` `or` `root2 ``=``=` `None``) : ` `        ``return` ` `  `    ``# Create two stacks for preorder ` `    ``# traversals  ` `    ``s1 ``=` `[] ` `    ``s2 ``=` `[]  ` `    ``s1.insert(``0``, root1)  ` `    ``s2.insert(``0``, root2)  ` ` `  `    ``while` `(``len``(s1) ``or` `len``(s2)) : ` `     `  `        ``# If traversal of one tree is over  ` `        ``# and other tree still has nodes.  ` `        ``if` `(``len``(s1) ``=``=` `0` `or` `len``(s2) ``=``=` `0``) : ` `            ``return` ` `  `        ``# Do iterative traversal of first  ` `        ``# tree and find first lead node  ` `        ``# in it as "temp1"  ` `        ``temp1 ``=` `s1[``0``]  ` `        ``s1.pop(``0``)  ` `        ``while` `(temp1 ``and` `not` `isLeaf(temp1)) : ` `         `  `            ``# pushing right childfirst so that  ` `            ``# left child comes first while popping.  ` `            ``s1.insert(``0``, temp1.right)  ` `            ``s1.insert(``0``, temp1.left)  ` `            ``temp1 ``=` `s1[``0``]  ` `            ``s1.pop(``0``)  ` `         `  `        ``# Do iterative traversal of second tree  ` `        ``# and find first lead node in it as "temp2"  ` `        ``temp2 ``=` `s2[``0``] ` `        ``s2.pop(``0``)  ` `        ``while` `(temp2 ``and` `not` `isLeaf(temp2)) : ` `         `  `            ``s2.insert(``0``, temp2.right)  ` `            ``s2.insert(``0``, temp2.left)  ` `            ``temp2 ``=` `s2[``0``] ` `            ``s2.pop(``0``)  ` `         `  `        ``# If we found leaves in both trees  ` `        ``if` `(temp1 !``=` `None` `and` `temp2 !``=` `None` `) : ` `         `  `            ``if` `(temp1.data !``=` `temp2.data ) : ` `             `  `                ``print``(``"First non matching leaves :"``, ` `                        ``temp1.data, "", temp2.data )  ` `                ``return` ` `  `# Driver Code  ` `if` `__name__ ``=``=` `'__main__'``: ` `    ``root1 ``=` `newNode(``5``)  ` `    ``root1.left ``=` `newNode(``2``)  ` `    ``root1.right ``=` `newNode(``7``)  ` `    ``root1.left.left ``=` `newNode(``10``)  ` `    ``root1.left.right ``=` `newNode(``11``)  ` ` `  `    ``root2 ``=` `newNode(``6``)  ` `    ``root2.left ``=` `newNode(``10``)  ` `    ``root2.right ``=` `newNode(``15``)  ` ` `  `    ``findFirstUnmatch(root1,root2) ` ` `  `# This code is contributed by ` `# SHUBHAMSINGH10 `

## C#

 `// C# program to find first leaves that are  ` `// not same.  ` `using` `System; ` `using` `System.Collections.Generic; ` ` `  `class` `GfG  ` `{ ` ` `  `    ``// Tree node  ` `    ``public` `class` `Node  ` `    ``{  ` `        ``public` `int` `data;  ` `        ``public` `Node left, right;  ` `    ``} ` ` `  `    ``// Utility method to create a new node  ` `    ``static` `Node newNode(``int` `x)  ` `    ``{  ` `        ``Node temp = ``new` `Node();  ` `        ``temp.data = x;  ` `        ``temp.left = ``null``; ` `        ``temp.right = ``null``;  ` `        ``return` `temp;  ` `    ``}  ` ` `  `    ``static` `bool` `isLeaf(Node t)  ` `    ``{  ` `        ``return` `((t.left == ``null``) && (t.right == ``null``));  ` `    ``}  ` ` `  `    ``// Prints the first non-matching leaf node in  ` `    ``// two trees if it exists, else prints nothing.  ` `    ``static` `void` `findFirstUnmatch(Node root1, Node root2)  ` `    ``{  ` `        ``// If any of the tree is empty  ` `        ``if` `(root1 == ``null` `|| root2 == ``null``)  ` `        ``return``;  ` ` `  `        ``// Create two stacks for preorder traversals  ` `        ``Stack s1 = ``new` `Stack (); ` `        ``Stack s2 = ``new` `Stack ();  ` `        ``s1.Push(root1);  ` `        ``s2.Push(root2);  ` ` `  `        ``while` `(s1.Count != 0 || s2.Count != 0)  ` `        ``{  ` `            ``// If traversal of one tree is over  ` `            ``// and other tree still has nodes.  ` `            ``if` `(s1.Count == 0 || s2.Count == 0 )  ` `            ``return``;  ` ` `  `            ``// Do iterative traversal of first tree  ` `            ``// and find first lead node in it as "temp1"  ` `            ``Node temp1 = s1.Peek();  ` `            ``s1.Pop();  ` `            ``while` `(temp1 != ``null` `&& isLeaf(temp1) != ``true``)  ` `            ``{  ` `                ``// pushing right childfirst so that  ` `                ``// left child comes first while popping.  ` `                ``s1.Push(temp1.right);  ` `                ``s1.Push(temp1.left);  ` `                ``temp1 = s1.Peek();  ` `                ``s1.Pop();  ` `            ``}  ` ` `  `            ``// Do iterative traversal of second tree  ` `            ``// and find first lead node in it as "temp2"  ` `            ``Node temp2 = s2.Peek();  ` `            ``s2.Pop();  ` `            ``while` `(temp2 != ``null` `&& isLeaf(temp2) != ``true``)  ` `            ``{  ` `                ``s2.Push(temp2.right);  ` `                ``s2.Push(temp2.left);  ` `                ``temp2 = s2.Peek();  ` `                ``s2.Pop();  ` `            ``}  ` ` `  `            ``// If we found leaves in both trees  ` `            ``if` `(temp1 != ``null` `&& temp2 != ``null` `)  ` `            ``{  ` `                ``if` `(temp1.data != temp2.data )  ` `                ``{  ` `                    ``Console.WriteLine(temp1.data + ``" "` `+ temp2.data);  ` `                    ``return``;  ` `                ``}  ` `            ``}  ` `        ``}  ` `    ``}  ` ` `  `    ``// Driver code  ` `    ``public` `static` `void` `Main(String[] args)  ` `    ``{  ` `        ``Node root1 = newNode(5);  ` `        ``root1.left = newNode(2);  ` `        ``root1.right = newNode(7);  ` `        ``root1.left.left = newNode(10);  ` `        ``root1.left.right = newNode(11);  ` ` `  `        ``Node root2 = newNode(6);  ` `        ``root2.left = newNode(10);  ` `        ``root2.right = newNode(15);  ` ` `  `        ``findFirstUnmatch(root1,root2);  ` ` `  `    ``}  ` `}  ` ` `  `// This code has been contributed by 29AjayKumar `

Output:

```First non matching leaves : 11  15
```

References:

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