Find final value if we double after every successful search in array

Given an array and an integer k, traverse the array and if the element in array is k, double the value of k and continue traversal. In the end return value of k.

Examples:

Input : arr[] = { 2, 3, 4, 10, 8, 1 }, k = 2
Output :16
First k = 2 is found, then we search for 4
which is also found, then we search for 8
which is also found, then we search for 16.
 
Input : arr[] = { 2, 4, 5, 6, 7 }, k = 3
Output :3

1- Traverse each element of an array if arr[i] == k then k = 2 * k
2- Repeat the same process till last element of an array
3- At last Return the value of k

C++

// CPP program to find value if we double 
// the value after every successful search
#include <iostream>
using namespace std;

// Function to Find the value of k
int findValue(int arr[], int n, int k) {

  // Search for k. After every successful
  // search, double k.
  for (int i = 0; i < n; i++) 
    if (arr[i] == k)
      k *= 2;
  
  return k;
}

// Driver's Code
int main() {
  int arr[] = {2, 3, 4, 10, 8, 1}, k = 2;
  int n = sizeof(arr) / sizeof(arr[0]);
  cout << findValue(arr, n, k);
  return 0;
}

Java

// Java program to find value 
// if we double  the value after 
// every successful search

class GFG
{
    // Function to Find the value of k
    static int findValue(int arr[], int n, int k) {
    
    // Search for k. After every successful
    // search, double k.
    for (int i = 0; i < n; i++) 
        if (arr[i] == k)
        k *= 2;
    
    return k;
    }

    // Driver Code
    public static void main(String[] args) 
    {
    int arr[] = {2, 3, 4, 10, 8, 1}, k = 2;
    int n = arr.length;
    System.out.print(findValue(arr, n, k));
    }
}
// This code is contriubted by
// Smitha Dinesh Semwal

Output: 16 

Time Complexity : O(n)

Reference:href=”https://www.geeksforgeeks.org/flipkart-interview-experience-set-35-on-campus-for-sde-1/”


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