# Find the other end point of a line with given one end and mid

Given a midpoint of line(m1, m2) and one coordinate of a line (x1, y1), find the other end point(x2, y2) of a line

Examples:

```Input  : x1 = –1, y1 = 2, and
m1 = 3, m2 = –6
Output : x2 = 7, y2 = 10

Input  : x1 = 6.4, y1 = 3 and
m1 = –10.7, m2 = 4
Output : x2 = 3, y2 = 4
```

## Recommended: Please try your approach on {IDE} first, before moving on to the solution. The Midpoint Formula: The midpoint of two points, (x1, y2) and (x2, y2) is the point M found by using:
M=((x1+x2)/2, (y1+y2)/2),
We have need of a (x2, y2) so we modifies the formula

```          m1 = ((x1+x2)/2),  m2 = ((y1+y2)/2)
2*m1 = (x1+x2),  2*m2 = (y1+y2)
x2 = (2*m1 - x1),  y2 = (2*m2 - y1)
```

## C++

 `// CPP program to find the end point of a line ` `#include ` `using` `namespace` `std; ` ` `  `// CPP function to find the end point of a line ` `void` `otherEndPoint(``int` `x1, ``int` `y1, ``int` `m1, ``int` `m2) ` `{ ` `    ``// find end point for x cordinates ` `    ``float` `x2 = (``float``)(2 * m1 - x1); ` ` `  `    ``// find end point for y cordinates ` `    ``float` `y2 = (``float``)(2 * m2 - y1); ` ` `  `    ``cout << ``"x2 = "` `<< x2 << ``", "` `         ``<< ``"y2 = "` `<< y2; ` `} ` ` `  `// Driven Program ` `int` `main() ` `{ ` `    ``int` `x1 = -4, y1 = -1, m1 = 3, m2 = 5; ` `    ``otherEndPoint(x1, y1, m1, m2); ` `    ``return` `0; ` `} `

## Java

 `// Java program to find the end point of a line ` `class` `GFG { ` `     `  `    ``// CPP function to find the end point ` `    ``// of a line ` `    ``static` `void` `otherEndPoint(``int` `x1, ``int` `y1,  ` `                               ``int` `m1, ``int` `m2) ` `    ``{ ` `        ``// find end point for x cordinates ` `        ``float` `x2 = (``float``)(``2` `* m1 - x1); ` `     `  `        ``// find end point for y cordinates ` `        ``float` `y2 = (``float``)(``2` `* m2 - y1); ` `     `  `        ``System.out.println(``"x2 = "` `+ x2 + ``", "` `                               ``+ ``"y2 = "` `+ y2); ` `    ``} ` `     `  `    ``// Driven Program ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `x1 = -``4``, y1 = -``1``, m1 = ``3``, m2 = ``5``; ` `        ``otherEndPoint(x1, y1, m1, m2); ` `    ``} ` `} ` ` `  `// This code is contributed by JaideepPyne. `

## Python3

 `# Python3 program to find the end ` `# point of a line ` ` `  `# function to find the end point ` `# of a line ` `def` `otherEndPoint(x1, y1, m1, m2): ` `     `  `    ``# find end point for x cordinates ` `    ``x2 ``=` `(``2` `*` `m1 ``-` `x1) ` ` `  `    ``# find end point for y cordinates ` `    ``y2 ``=` `(``2` `*` `m2 ``-` `y1) ` ` `  `    ``print` `(``"x2 = {}, y2 = {}"`  `               ``. ``format``(x2, y2)) ` ` `  `# Driven Program ` `x1 ``=` `-``4` `y1 ``=` `-``1` `m1 ``=` `3` `m2 ``=` `5` `otherEndPoint(x1, y1, m1, m2) ` ` `  `# This code is contributed by  ` `# Manish Shaw (manishshaw1) `

## C#

 `// C# program to find the ` `// end point of a line ` `using` `System; ` ` `  `class` `GFG { ` `     `  `    ``// function to find the  ` `    ``// end pointof a line ` `    ``static` `void` `otherEndPoint(``int` `x1, ``int` `y1,  ` `                              ``int` `m1, ``int` `m2) ` `    ``{ ` `         `  `        ``// find end point for x cordinates ` `        ``float` `x2 = (``float``)(2 * m1 - x1); ` `     `  `        ``// find end point for y cordinates ` `        ``float` `y2 = (``float``)(2 * m2 - y1); ` `     `  `        ``Console.WriteLine(``"x2 = "` `+ x2 + ``", "` `                          ``+ ``"y2 = "` `+ y2); ` `    ``} ` `     `  `    ``// Driver Program ` `    ``public` `static` `void` `Main(String []args) ` `    ``{ ` `        ``int` `x1 = -4, y1 = -1, m1 = 3, m2 = 5; ` `        ``otherEndPoint(x1, y1, m1, m2); ` `    ``} ` `} ` ` `  `// This code is contributed by nitin mittal. `

## PHP

 ` `

Output:

```x2 = 10, y2 = 11
```

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