Related Articles
Find elements larger than half of the elements in an array
• Difficulty Level : Basic
• Last Updated : 25 Mar, 2021

Given an array of n elements, the task is to find the elements that are greater than half of elements in an array. In case of odd elements, we need to print elements larger than floor(n/2) elements where n is total number of elements in array.

Examples :

```Input :  arr[] = {1, 6, 3, 4}
Output : 4 6

Input  :  arr[] = {10, 4, 2, 8, 9}
Output :  10 9 8```

A naive approach is to take an element and compare with all other elements and if it is greater then increment the count and then check if count is greater than n/2 elements then print.

An efficient method is to sort the array in ascending order and then print last ceil(n/2) elements from sorted array.
Below is the implementation of this sorting based approach.

## C++

 `// C++ program to find elements that are larger than``// half of the elements in array``#include ``using` `namespace` `std;` `// Prints elements larger than n/2 element``void` `findLarger(``int` `arr[], ``int` `n)``{``    ``// Sort the array in ascending order``    ``sort(arr, arr + n);` `    ``// Print last ceil(n/2) elements``    ``for` `(``int` `i = n-1; i >= n/2; i--)``        ``cout << arr[i] << ``" "``;    ``}` `// Driver program``int` `main()``{``    ``int` `arr[] = {1, 3, 6, 1, 0, 9};``    ``int` `n = ``sizeof``(arr)/``sizeof``(arr);``    ``findLarger(arr, n);``    ``return` `0;``}`

## Java

 `// Java program to find elements that are``// larger than half of the elements in array``import` `java.util.*;` `class` `Gfg``{``    ``// Prints elements larger than n/2 element``    ``static` `void` `findLarger(``int` `arr[], ``int` `n)``    ``{``        ``// Sort the array in ascending order``        ``Arrays.sort(arr);``     ` `        ``// Print last ceil(n/2) elements``        ``for` `(``int` `i = n-``1``; i >= n/``2``; i--)``            ``System.out.print(arr[i] + ``" "``); ``    ``}``     ` `    ``// Driver program``    ``public` `static` `void` `main(String[] args)``    ``{``        ``int` `arr[] = {``1``, ``3``, ``6``, ``1``, ``0``, ``9``};``        ``int` `n = arr.length;``        ``findLarger(arr, n);``    ``}   ``}` `// This code is contributed by Raghav Sharma`

## Python

 `# Python program to find elements that are larger than``# half of the elements in array``# Prints elements larger than n/2 element``def` `findLarger(arr,n):` `    ``# Sort the array in ascending order``    ``x ``=` `sorted``(arr)` `    ``# Print last ceil(n/2) elements``    ``for` `i ``in` `range``(n``/``2``,n):``        ``print``(x[i]),` `# Driver program``arr ``=` `[``1``, ``3``, ``6``, ``1``, ``0``, ``9``]``n ``=` `len``(arr);``findLarger(arr,n)` `# This code is contributed by Afzal Ansari`

## C#

 `// C# program to find elements``// that are larger than half``// of the elements in array``using` `System;` `class` `GFG``{``    ``// Prints elements larger``    ``// than n/2 element``    ``static` `void` `findLarger(``int` `[]arr,``                           ``int` `n)``    ``{``        ``// Sort the array``        ``// in ascending order``        ``Array.Sort(arr);``    ` `        ``// Print last ceil(n/2) elements``        ``for` `(``int` `i = n - 1; i >= n / 2; i--)``            ``Console.Write(arr[i] + ``" "``);``    ``}``    ` `    ``// Driver Code``    ``public` `static` `void` `Main()``    ``{``        ``int` `[]arr = {1, 3, 6, 1, 0, 9};``        ``int` `n = arr.Length;``        ``findLarger(arr, n);``    ``}``}` `// This code is contributed``// by nitin mittal.`

## PHP

 `= ``\$n` `/ 2; ``\$i``--)``        ``echo` `\$arr``[``\$i``] , ``" "``;``}` `// Driver Code``\$arr` `= ``array``(1, 3, 6, 1, 0, 9);``\$n` `= ``count``(``\$arr``);``findLarger(``\$arr``, ``\$n``);` `// This code is contributed by anuj_67.``?>`

## Javascript

 ``

Output :

`9 6 3`

This article is contributed by Sahil Chhabra (KILLER). If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.

Attention reader! Don’t stop learning now. Get hold of all the important DSA concepts with the DSA Self Paced Course at a student-friendly price and become industry ready.

My Personal Notes arrow_drop_up