Given an array of n elements, the task is to find the elements that are greater than half of elements in an array. In case of odd elements, we need to print elements larger than floor(n/2) elements where n is total number of elements in array.

**Examples :**

Input :arr[] = {1, 6, 3, 4}Output :4 6Input :arr[] = {10, 4, 2, 8, 9}Output :10 9 8

A **naive approach** is to take an element and compare with all other elements and if it is greater then increment the count and then check if count is greater than n/2 elements then print.

An **efficient method** is to sort the array in ascending order and then print last ceil(n/2) elements from sorted array.

Below is the implementation of this sorting based approach.

## C++

`// C++ program to find elements that are larger than` `// half of the elements in array` `#include <bits/stdc++.h>` `using` `namespace` `std;` `// Prints elements larger than n/2 element` `void` `findLarger(` `int` `arr[], ` `int` `n)` `{` ` ` `// Sort the array in ascending order` ` ` `sort(arr, arr + n);` ` ` `// Print last ceil(n/2) elements` ` ` `for` `(` `int` `i = n-1; i >= n/2; i--)` ` ` `cout << arr[i] << ` `" "` `; ` `}` `// Driver program` `int` `main()` `{` ` ` `int` `arr[] = {1, 3, 6, 1, 0, 9};` ` ` `int` `n = ` `sizeof` `(arr)/` `sizeof` `(arr[0]);` ` ` `findLarger(arr, n);` ` ` `return` `0;` `}` |

## Java

`// Java program to find elements that are` `// larger than half of the elements in array` `import` `java.util.*;` `class` `Gfg` `{` ` ` `// Prints elements larger than n/2 element` ` ` `static` `void` `findLarger(` `int` `arr[], ` `int` `n)` ` ` `{` ` ` `// Sort the array in ascending order` ` ` `Arrays.sort(arr);` ` ` ` ` `// Print last ceil(n/2) elements` ` ` `for` `(` `int` `i = n-` `1` `; i >= n/` `2` `; i--)` ` ` `System.out.print(arr[i] + ` `" "` `); ` ` ` `}` ` ` ` ` `// Driver program` ` ` `public` `static` `void` `main(String[] args)` ` ` `{` ` ` `int` `arr[] = {` `1` `, ` `3` `, ` `6` `, ` `1` `, ` `0` `, ` `9` `};` ` ` `int` `n = arr.length;` ` ` `findLarger(arr, n);` ` ` `} ` `}` `// This code is contributed by Raghav Sharma` |

## Python

`# Python program to find elements that are larger than` `# half of the elements in array` `# Prints elements larger than n/2 element` `def` `findLarger(arr,n):` ` ` `# Sort the array in ascending order` ` ` `x ` `=` `sorted` `(arr)` ` ` `# Print last ceil(n/2) elements` ` ` `for` `i ` `in` `range` `(n` `/` `2` `,n):` ` ` `print` `(x[i]),` `# Driver program` `arr ` `=` `[` `1` `, ` `3` `, ` `6` `, ` `1` `, ` `0` `, ` `9` `]` `n ` `=` `len` `(arr);` `findLarger(arr,n)` `# This code is contributed by Afzal Ansari` |

## C#

`// C# program to find elements` `// that are larger than half` `// of the elements in array` `using` `System;` `class` `GFG` `{` ` ` `// Prints elements larger` ` ` `// than n/2 element` ` ` `static` `void` `findLarger(` `int` `[]arr,` ` ` `int` `n)` ` ` `{` ` ` `// Sort the array` ` ` `// in ascending order` ` ` `Array.Sort(arr);` ` ` ` ` `// Print last ceil(n/2) elements` ` ` `for` `(` `int` `i = n - 1; i >= n / 2; i--)` ` ` `Console.Write(arr[i] + ` `" "` `);` ` ` `}` ` ` ` ` `// Driver Code` ` ` `public` `static` `void` `Main()` ` ` `{` ` ` `int` `[]arr = {1, 3, 6, 1, 0, 9};` ` ` `int` `n = arr.Length;` ` ` `findLarger(arr, n);` ` ` `}` `}` `// This code is contributed` `// by nitin mittal.` |

## PHP

`<?php` `// PHP program to find elements` `// that are larger than half of` `// the elements in array` `// Prints elements larger` `// than n/2 element` `function` `findLarger(` `$arr` `, ` `$n` `)` `{` ` ` `// Sort the array in` ` ` `// ascending order` ` ` `sort(` `$arr` `);` ` ` `// Print last ceil(n/2) elements` ` ` `for` `(` `$i` `= ` `$n` `- 1; ` `$i` `>= ` `$n` `/ 2; ` `$i` `--)` ` ` `echo` `$arr` `[` `$i` `] , ` `" "` `;` `}` `// Driver Code` `$arr` `= ` `array` `(1, 3, 6, 1, 0, 9);` `$n` `= ` `count` `(` `$arr` `);` `findLarger(` `$arr` `, ` `$n` `);` `// This code is contributed by anuj_67.` `?>` |

## Javascript

`<script>` `// JavaScript program to find elements that are` `// larger than half of the elements in array` `// Prints elements larger than n/2 element` `function` `findLarger(arr, n)` `{` ` ` ` ` `// Sort the array in ascending order` ` ` `arr.sort();` ` ` ` ` `// Print last ceil(n/2) elements` ` ` `for` `(let i = n - 1; i >= n / 2; i--)` ` ` `document.write(arr[i] + ` `" "` `); ` `}` `// Driver Code` `let arr = [1, 3, 6, 1, 0, 9];` `let n = arr.length;` `findLarger(arr, n);` `// This code is contributed by chinmoy1997pal` ` ` `</script>` |

**Output :**

9 6 3

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