Given a positive integer n. The task is to find count of digits of number which evenly divides the number n.
Input : n = 12 Output : 2 1 and 2 divide 12. Input : n = 1012 Output : 3 1, 1 and 2 divide 1012.
The idea is to find each digit of the number n by modulus 10 and then check whether it divides n or not. Accordingly, increment the counter. Notice that the digit can be 0, so take care of that case.
Below is implementation of this approach:
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