# Find the compatibility difference between two arrays

Suppose there are two friends and now they want to test their friendship that how much compatible they are. Given the numbers n numbered from 1 …n and they are asked to rank the numbers. The task is find the compatibility difference between them. Compatibility difference is the number of mis-matches in the relative ranking of the same movie given by them.

Examples :

```Input : a1[] = {3, 1, 2, 4, 5}
a2[] = {3, 2, 4, 1, 5}
Output : 2
Explanation : Compatibility difference is two
because first ranks movie 1 before 2 and 4 but
other ranks it after.

Input : a1[] = {5, 3, 1, 2, 4}
a2[] = {3, 1, 2, 4, 5}
Output : 5
Total difference is four due to mis-match in
position of 5
```

## Recommended: Please solve it on “PRACTICE” first, before moving on to the solution.

The idea is traverse both arrays.
1) If current elements are same, do nothing.
2) Find next position of a1[i] in a2[]. Let this position be j. One by one move a2[j] to a2[i] (Similar to bubble step of bubble sort)

Below is the implementation of above steps.

## C++

 `// C++ program to count of misplacements ` `#include ` `using` `namespace` `std; ` `int` `findDifference(``int` `a1[], ``int` `a2[], ``int` `n) ` `{ ` `    ``int` `res = 0; ` ` `  `    ``for` `(``int` `i = 0; i < n; i++) { ` ` `  `        ``// If elements at current position ` `        ``// are not same  ` `        ``if` `(a1[i] != a2[i]) { ` ` `  `            ``// Find position of a1[i] in a2[] ` `            ``int` `j = i + 1; ` `            ``while` `(a1[i] != a2[j])  ` `                ``j++; ` `             `  `            ``// Insert the element a2[j] at ` `            ``// a2[i] by moving all intermediate ` `            ``// elements one position ahead. ` `            ``while` `(j != i) { ` `                ``swap(a2[j], a2[j - 1]); ` `                ``j--; ` `                ``res++; ` `            ``} ` `        ``} ` `    ``} ` `    ``return` `res; ` `} ` ` `  `// Driver code ` `int` `main() ` `{ ` `    ``int` `a1[] = { 3, 1, 2, 4, 5 }; ` `    ``int` `a2[] = { 3, 2, 4, 1, 5 }; ` `    ``int` `n = ``sizeof``(a1)/``sizeof``(a1); ` `    ``cout << findDifference(a1, a2, n); ` `    ``return` `0; ` `} `

## Java

 `// Java program to count of misplacements ` `public` `class` `Compatability_difference { ` ` `  `    ``static` `int` `findDifference(``int` `a1[], ``int` `a2[], ``int` `n) ` `    ``{ ` `        ``int` `res = ``0``; ` `      `  `        ``for` `(``int` `i = ``0``; i < n; i++) { ` `      `  `            ``// If elements at current position ` `            ``// are not same  ` `            ``if` `(a1[i] != a2[i]) { ` `      `  `                ``// Find position of a1[i] in a2[] ` `                ``int` `j = i + ``1``; ` `                ``while` `(a1[i] != a2[j])  ` `                    ``j++; ` `                  `  `                ``// Insert the element a2[j] at ` `                ``// a2[i] by moving all intermediate ` `                ``// elements one position ahead. ` `                ``while` `(j != i) { ` `                     `  `                    ``//swap ` `                    ``int` `temp = a2[j - ``1``]; ` `                    ``a2[j - ``1``] = a2[j]; ` `                    ``a2[j] = temp; ` `                    ``j--; ` `                    ``res++; ` `                ``} ` `            ``} ` `        ``} ` `        ``return` `res; ` `    ``} ` `      `  `    ``// Driver code ` `    ``public` `static` `void` `main(String args[]) ` `    ``{ ` `        ``int` `a1[] = { ``3``, ``1``, ``2``, ``4``, ``5` `}; ` `        ``int` `a2[] = { ``3``, ``2``, ``4``, ``1``, ``5` `}; ` `        ``int` `n = a1.length; ` `         `  `        ``System.out.println(findDifference(a1, a2, n)); ` `    ``} ` `} ` `// This code is contributed by Sumit Ghosh `

## Python3

 `# Python3 program to count misplacements ` ` `  `def` `findDifference(a1, a2, n): ` ` `  `    ``res ``=` `0` ` `  `    ``for` `i ``in` `range``(``0``, n): ` ` `  `        ``# If elements at current ` `        ``# position are not same  ` `        ``if` `a1[i] !``=` `a2[i]: ` ` `  `            ``# Find position of a1[i] in a2[] ` `            ``j ``=` `i ``+` `1` `            ``while` `(a1[i] !``=` `a2[j]):  ` `                ``j ``+``=` `1` `                ``if` `i >``=` `n ``or` `j >``=` `n: ` `                    ``break` `             `  `            ``# Insert the element a2[j] at ` `            ``# a2[i] by moving all intermediate ` `            ``# elements one position ahead. ` `            ``while` `(j !``=` `i):  ` `                ``a2[j],a2[j``-``1``] ``=` `a2[j``-``1``],a2[j] ` `                ``res ``+``=` `1` `                ``j ``-``=` `1`  `                ``if` `i >``=` `n ``or` `j >``=` `n: ` `                    ``break` `         `  `    ``return` `res ` ` `  `# Driver code ` `a1 ``=` `[ ``3``, ``1``, ``2``, ``4``, ``5` `] ` `a2 ``=` `[ ``3``, ``2``, ``4``, ``1``, ``5` `] ` `n ``=` `len``(a1) ` `print``(findDifference(a1, a2, n)) ` ` `  `# This code is contributed by Smitha Dinesh Semwal `

## C#

 `// C# program to count of misplacements ` `using` `System; ` ` `  `public` `class` `Compatability_difference  ` `{ ` `    ``static` `int` `findDifference(``int` `[]a1, ``int` `[]a2, ``int` `n) ` `    ``{ ` `        ``int` `res = 0; ` `     `  `        ``for` `(``int` `i = 0; i < n; i++) { ` `     `  `            ``// If elements at current  ` `            ``// position are not same  ` `            ``if` `(a1[i] != a2[i]) { ` `     `  `                ``// Find position of a1[i] in a2[] ` `                ``int` `j = i + 1; ` `                ``while` `(a1[i] != a2[j])  ` `                    ``j++; ` `                 `  `                ``// Insert the element a2[j] at ` `                ``// a2[i] by moving all intermediate ` `                ``// elements one position ahead. ` `                ``while` `(j != i) { ` `                     `  `                    ``//swap ` `                    ``int` `temp = a2[j - 1]; ` `                    ``a2[j - 1] = a2[j]; ` `                    ``a2[j] = temp; ` `                    ``j--; ` `                    ``res++; ` `                ``} ` `            ``} ` `        ``} ` `        ``return` `res; ` `    ``} ` `     `  `    ``// Driver code ` `    ``public` `static` `void` `Main() ` `    ``{ ` `        ``int` `[]a1 = {3, 1, 2, 4, 5}; ` `        ``int` `[]a2 = {3, 2, 4, 1, 5}; ` `        ``int` `n = a1.Length; ` `         `  `        ``// Function calling ` `        ``Console.WriteLine(findDifference(a1, a2, n)); ` `    ``} ` `} ` ` `  `// This code is contributed by vt_m. `

Output:

```2
```

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Improved By : vt_m

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