Given the volume V of a tank in liter. There is a pump which is filling the tank at speed of M liter per minute. There is a leakage at the bottom of the tank which wasting water at speed N liter per minute. Given N is less than M. The task is to calculate how much amount of water will be wasted if leakage is seen after filling the full tank.
Examples:
Input : V = 700, M = 10, N = 3 Output : 300 Input : V = 1000, M = 100, N = 50 Output : 1000
Approach : Given the speed of filling pump is M liter per minute. So, the amount of water filled in one minute is M Liter. Also, N litres of water is wasted in a minute. Therefore after one minute the amount of water in the tank will be (M – N). Hence total time taken to fill the tank with leakage will be V / (M-N).
Therefore the amount of wasted water will be (V / (M-N)) * N.
Below is the implementation of the above approach:
C++
// C++ program to find the volume of water wasted #include <iostream> using namespace std; // Function to calculate amount of wasted water double wastedWater(double V, double M, double N) { double wasted_amt, amt_per_min, time_to_fill; // filled amount of water in one minute amt_per_min = M - N; // total time taken to fill the tank // because of leakage time_to_fill = V / amt_per_min; // wasted amount of water wasted_amt = N * time_to_fill; return wasted_amt; } // Driver code int main() { double V, M, N; V = 700; M = 10; N = 3; cout << wastedWater(V, M, N) << endl; V = 1000; M = 100; N = 50; cout << wastedWater(V, M, N) << endl; return 0; } |
Java
// Java program to find the // volume of water wasted class GFG { // Function to calculate amount of wasted water static double wastedWater(double V, double M, double N) { double wasted_amt, amt_per_min, time_to_fill; // filled amount of water in one minute amt_per_min = M - N; // total time taken to fill the tank // because of leakage time_to_fill = V / amt_per_min; // wasted amount of water wasted_amt = N * time_to_fill; return wasted_amt; } // Driver code public static void main(String[] args) { double V, M, N; V = 700; M = 10; N = 3; System.out.println(wastedWater(V, M, N)) ; V = 1000; M = 100; N = 50; System.out.println(wastedWater(V, M, N)); } } // This Code is Contributed by Code_Mech. |
Python3
# Python3 program to find the volume # of water wasted # Function to calculate amount # of wasted water def wastedWater(V, M, N): # filled amount of water in one minute amt_per_min = M - N # total time taken to fill the tank # because of leakage time_to_fill = V / amt_per_min # wasted amount of water wasted_amt = N * time_to_fill return wasted_amt # Driver code V = 700M = 10N = 3print(wastedWater(V, M, N)) V = 1000M = 100N = 50print(wastedWater(V, M, N)) # This code is contributed by Shrikant13 |
C#
// C# program to find the // volume of water wasted using System; class GFG { // Function to calculate amount of wasted water static double wastedWater(double V, double M, double N) { double wasted_amt, amt_per_min, time_to_fill; // filled amount of water in one minute amt_per_min = M - N; // total time taken to fill the tank // because of leakage time_to_fill = V / amt_per_min; // wasted amount of water wasted_amt = N * time_to_fill; return wasted_amt; } // Driver code public static void Main() { double V, M, N; V = 700; M = 10; N = 3; Console.WriteLine(wastedWater(V, M, N)) ; V = 1000; M = 100; N = 50; Console.WriteLine(wastedWater(V, M, N)); } } // This Code is Contributed by ihritik |
PHP
<?php // PHP program to find the // volume of water wasted // Function to calculate amount of wasted water function wastedWater($V, $M, $N) { // filled amount of water in one minute $amt_per_min = $M - $N; // total time taken to fill the tank // because of leakage $time_to_fill = $V / $amt_per_min; // wasted amount of water $wasted_amt = $N * $time_to_fill; return $wasted_amt; } // Driver code $V = 700; $M = 10; $N = 3; echo wastedWater($V, $M, $N), "\n"; $V = 1000; $M = 100; $N = 50; echo wastedWater($V, $M, $N); // This Code is Contributed by ihritik ?> |
300 1000
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