Find a point that lies inside exactly K given squares

Given an integer K and an array arr each of whose element x represents a square with two of its vertices as (0, 0) and (x, x). The task is to find a point which lies in exactly K squares.

Examples:

Input: arr[] = {1, 2, 3, 4}, K = 2
Output: (3, 3)
The point (3, 3) lies inside 3rd and 4th square only.



Input: arr[] = {8, 1, 55, 90}, K = 3
Output: (8, 8)

Approach: Since all squares have a common corner point (0, 0), any point which lies in any square would also lie in any larger square. Hence, we can simply print the other corner of the Kth largest square.

Below is the implementation of the above approach:

C++

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// C++ implementation of the approach
#include <bits/stdc++.h>
using namespace std;
  
int PointInKSquares(int n, int a[], int k)
{
    sort(a, a + n);
    return a[n - k];
}
  
// Driver Program to test above function
int main()
{
    int k = 2;
    int a[] = { 1, 2, 3, 4 };
    int n = sizeof(a) / sizeof(a[0]);
  
    int x = PointInKSquares(n, a, k);
    cout << "(" << x << ", " << x << ")";
}

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Java














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// Java implementation of the approach 


  


import java.io.*; 


import java.util.*; 


class GFG { 


  


  


static int PointInKSquares(int n, int a[], int k) 


{ 


    Arrays.sort(a); 


    return a[n - k]; 


} 


  


// Driver Program to test above function 


  


    public static void main (String[] args) { 


            int k = 2; 


    int []a = { 1, 2, 3, 4 }; 


    int n = a.length; 


  


    int x = PointInKSquares(n, a, k); 


    System.out.println( "(" + x + ", " + x +")"); 


  


      


    } 


} 


// This code is contributed by anuj_67.. 



















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Python3














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# Python 3 implementation of the 


# above approach 


def PointInKSquares(n, a, k) : 


      


    a.sort() 


    return a[n - k] 


  


# Driver Code 


if __name__ == "__main__" : 


      


    k = 2


    a = [1, 2, 3, 4] 


    n = len(a) 


      


    x = PointInKSquares(n, a, k) 


    print("(", x, ",", x, ")") 


  


# This code is contributed by Ryuga 



















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C#














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// C# implementation of the approach  


using System;  


class GFG  


{  


  


static int PointInKSquares(int n,  


                           int []a, int k)  


{  


    Array.Sort(a);  


    return a[n - k];  


}  


  


// Driver Code 


public static void Main (String[] args)  


{  


    int k = 2;  


    int []a = { 1, 2, 3, 4 };  


    int n = a.Length;  


      


    int x = PointInKSquares(n, a, k);  


    Console.WriteLine("(" + x + ", " + x +")");  


}  


}  


  


// This code is contributed  


// by Arnab Kundu 



















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PHP














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<?php 


// PHP implementation of the approach 


  


function PointInKSquares($n, $a, $k) 


{ 


    sort($a); 


    return $a[$n - $k]; 


} 


  


// Driver Code 


$k = 2; 


$a = array(1, 2, 3, 4); 


$n = sizeof($a); 


  


$x = PointInKSquares($n, $a, $k); 


echo "(" . $x . ", " . $x . ")"; 


  


// This code is contributed  


// by Akanksha Rai 


?> 



















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Output:


(3, 3)






          
          
          

          

    

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