# Find a N-digit number such that it is not divisible by any of its digits

Given an integer N, the task is to find an N-digit number such that it is not divisible by any of its digits.**Note:** There can be multiple answers for each value of N.

**Examples:**

Input:N = 4Output:6789Explanation:

As the number 6789 is not divisible by any of its digits, it is 6, 7, 8 and 9 and it is also a four-digit number. Hence, it can be the desired number.

Input:N = 2Output:57Explanation:

As the number 57 is not divisible by any of its digits, it is 5 and 7 and it is also a 2-digit number. Hence, it can be the desired number.

**Approach:** The key observation in the problem is that 2 and 3 are those numbers that don’t divide each other. Also, the numbers “23, 233, 2333, …” are not divisible by neither 2 nor 3. Hence, for any N-digit number, the most significant digit will be 2 and the rest of the digits will be 3 to get the desired number.

**Algorithm:**

- Check if the value of the N is equal to 1, then there is no such number is possible, hence return -1.
- Otherwise, initialize a variable
**num**, to store the number by 2. - Run a loop from 1 to N and then, for each iteration, multiply the number by 10 and add 3 to it.

num = (num * 10) + 3

Below is the implementation of the above approach:

## C++

`// C++ implementation to find a` `// N-digit number such that the number` `// it is not divisible by its digits` `#include <bits/stdc++.h>` `using` `namespace` `std;` `typedef` `long` `long` `int` `ll;` `// Function to find the number` `// such that it is not divisible` `// by its digits` `void` `solve(ll n)` `{` ` ` `// Base Cases` ` ` `if` `(n == 1)` ` ` `{` ` ` `cout << -1;` ` ` `}` ` ` `else` `{` ` ` ` ` `// First Digit of the` ` ` `// number will be 2` ` ` `int` `num = 2;` ` ` ` ` `// Next digits of the numbers` ` ` `for` `(ll i = 0; i < n - 1; i++) {` ` ` `num = (num * 10) + 3;` ` ` `}` ` ` `cout << num;` ` ` `}` `}` `// Driver Code` `int` `main()` `{` ` ` `ll n = 4;` ` ` ` ` `// Function Call` ` ` `solve(n);` `}` |

## Java

`// Java implementation to find a` `// N-digit number such that the number` `// it is not divisible by its digits` `class` `GFG {` ` ` `long` `ll;` ` ` ` ` `// Function to find the number` ` ` `// such that it is not divisible` ` ` `// by its digits` ` ` `static` `void` `solve(` `long` `n)` ` ` `{` ` ` `// Base Cases` ` ` `if` `(n == ` `1` `)` ` ` `{` ` ` `System.out.println(-` `1` `);` ` ` `}` ` ` `else` `{` ` ` ` ` `// First Digit of the` ` ` `// number will be 2` ` ` `int` `num = ` `2` `;` ` ` ` ` `// Next digits of the numbers` ` ` `for` `(` `long` `i = ` `0` `; i < n - ` `1` `; i++) {` ` ` `num = (num * ` `10` `) + ` `3` `;` ` ` `}` ` ` `System.out.println(num);` ` ` `}` ` ` `}` ` ` ` ` `// Driver Code` ` ` `public` `static` `void` `main (String[] args)` ` ` `{` ` ` `long` `n = ` `4` `;` ` ` ` ` `// Function Call` ` ` `solve(n);` ` ` `}` `}` `// This code is contributed by AnkitRai01` |

## Python3

`# Python3 implementation to find a` `# N-digit number such that the number` `# it is not divisible by its digits` `# Function to find the number` `# such that it is not divisible` `# by its digits` `def` `solve(n) :` ` ` `# Base Cases` ` ` `if` `(n ` `=` `=` `1` `) :` ` ` `print` `(` `-` `1` `);` ` ` ` ` `else` `:` ` ` ` ` `# First Digit of the` ` ` `# number will be 2` ` ` `num ` `=` `2` `;` ` ` ` ` `# Next digits of the numbers` ` ` `for` `i ` `in` `range` `(n ` `-` `1` `) :` ` ` `num ` `=` `(num ` `*` `10` `) ` `+` `3` `;` ` ` ` ` `print` `(num);` `# Driver Code` `if` `__name__ ` `=` `=` `"__main__"` `:` ` ` `n ` `=` `4` `;` ` ` ` ` `# Function Call` ` ` `solve(n);` ` ` `# This code is contributed by AnkitRai01` |

## C#

`// C# implementation to find a` `// N-digit number such that the number` `// it is not divisible by its digits` `using` `System;` `class` `GFG {` ` ` ` ` `long` `ll;` ` ` ` ` `// Function to find the number` ` ` `// such that it is not divisible` ` ` `// by its digits` ` ` `static` `void` `solve(` `long` `n)` ` ` `{` ` ` `// Base Cases` ` ` `if` `(n == 1)` ` ` `{` ` ` `Console.WriteLine(-1);` ` ` `}` ` ` `else` `{` ` ` ` ` `// First Digit of the` ` ` `// number will be 2` ` ` `int` `num = 2;` ` ` ` ` `// Next digits of the numbers` ` ` `for` `(` `long` `i = 0; i < n - 1; i++) {` ` ` `num = (num * 10) + 3;` ` ` `}` ` ` `Console.WriteLine(num);` ` ` `}` ` ` `}` ` ` ` ` `// Driver Code` ` ` `public` `static` `void` `Main(String[] args)` ` ` `{` ` ` `long` `n = 4;` ` ` ` ` `// Function Call` ` ` `solve(n);` ` ` `}` `}` `// This code is contributed by sapnasingh4991` |

## Javascript

`<script>` `//Javascript implementation to find a` `// N-digit number such that the number` `// it is not divisible by its digits` `// Function to find the number` `// such that it is not divisible` `// by its digits` `function` `solve(n)` `{` ` ` `// Base Cases` ` ` `if` `(n == 1)` ` ` `{` ` ` `document.write( -1);` ` ` `}` ` ` `else` `{` ` ` ` ` `// First Digit of the` ` ` `// number will be 2` ` ` `var` `num = 2;` ` ` ` ` `// Next digits of the numbers` ` ` `for` `(` `var` `i = 0; i < n - 1; i++) {` ` ` `num = (num * 10) + 3;` ` ` `}` ` ` `document.write( num);` ` ` `}` `}` `// Given N` `var` `n = 4;` `// Function Call` `solve(n);` `// This code is contributed by SoumikMondal` `</script>` |

**Output:**

2333

**Performance Analysis:**

**Time Complexity:**O(N).**Auxiliary Space:**O(1).