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Factor Tree of a given Number
• Difficulty Level : Medium
• Last Updated : 17 Feb, 2021

Factor Tree is an intuitive method to understand the factors of a number. It shows how all the factors are been derived from the number. It is a special diagram where you find the factors of a number, then the factors of those numbers, etc until you can’t factor anymore. The ends are all the prime factors of the original number.
Example:

```Input : v = 48
Output : Root of below tree
48
/\
2  24
/\
2  12
/\
2  6
/\
2  3```

The factor tree is created recursively. A binary tree is used.

1. We start with a number and find the minimum divisor possible.
2. Then, we divide the parent number by the minimum divisor.
3. We store both the divisor and quotient as two children of the parent number.
4. Both the children are sent into function recursively.
5. If a divisor less than half the number is not found, two children are stored as NULL.

## CPP

 `// C++ program to construct Factor Tree for``// a given number``#include``using` `namespace` `std;` `// Tree node``struct` `Node``{``    ``struct` `Node *left, *right;``    ``int` `key;``};` `// Utility function to create a new tree Node``Node* newNode(``int` `key)``{``    ``Node* temp = ``new` `Node;``    ``temp->key = key;``    ``temp->left = temp->right = NULL;``    ``return` `temp;``}` `// Constructs factor tree for given value and stores``// root of tree at given reference.``void` `createFactorTree(``struct` `Node **node_ref, ``int` `v)``{``    ``(*node_ref) = newNode(v);` `    ``// the number is factorized``    ``for` `(``int` `i = 2 ; i < v/2 ; i++)``    ``{``        ``if` `(v % i != 0)``          ``continue``;` `        ``// If we found a factor, we construct left``        ``// and right subtrees and return. Since we``        ``// traverse factors starting from smaller``        ``// to greater, left child will always have``        ``// smaller factor``        ``createFactorTree(&((*node_ref)->left), i);``        ``createFactorTree(&((*node_ref)->right), v/i);``        ``return``;``    ``}``}` `// Iterative method to find the height of Binary Tree``void` `printLevelOrder(Node *root)``{``    ``// Base Case``    ``if` `(root == NULL)  ``return``;` `    ``queue q;``    ``q.push(root);` `    ``while` `(q.empty() == ``false``)``    ``{``        ``// Print front of queue and remove``        ``// it from queue``        ``Node *node = q.front();``        ``cout << node->key << ``" "``;``        ``q.pop();``        ``if` `(node->left != NULL)``            ``q.push(node->left);``        ``if` `(node->right != NULL)``            ``q.push(node->right);``    ``}``}` `// driver program``int` `main()``{``    ``int` `val = 48;``// sample value``    ``struct` `Node *root = NULL;``    ``createFactorTree(&root, val);``    ``cout << ``"Level order traversal of "``            ``"constructed factor tree"``;``    ``printLevelOrder(root);``    ``return` `0;``}`

## Java

 `// Java program to conFactor Tree for``// a given number``import` `java.util.*;``class` `GFG``{` `  ``// Tree node``  ``static` `class` `Node``  ``{``    ``Node left, right;``    ``int` `key;``  ``};``  ``static` `Node root;` `  ``// Utility function to create a new tree Node``  ``static` `Node newNode(``int` `key)``  ``{``    ``Node temp = ``new` `Node();``    ``temp.key = key;``    ``temp.left = temp.right = ``null``;``    ``return` `temp;``  ``}` `  ``// Constructs factor tree for given value and stores``  ``// root of tree at given reference.``  ``static` `Node createFactorTree(Node node_ref, ``int` `v)``  ``{``    ``(node_ref) = newNode(v);` `    ``// the number is factorized``    ``for` `(``int` `i = ``2` `; i < v/``2` `; i++)``    ``{``      ``if` `(v % i != ``0``)``        ``continue``;` `      ``// If we found a factor, we conleft``      ``// and right subtrees and return. Since we``      ``// traverse factors starting from smaller``      ``// to greater, left child will always have``      ``// smaller factor``      ``node_ref.left = createFactorTree(((node_ref).left), i);``      ``node_ref.right =  createFactorTree(((node_ref).right), v/i);``      ``return` `node_ref;``    ``}``    ``return` `node_ref;``  ``}` `  ``// Iterative method to find the height of Binary Tree``  ``static` `void` `printLevelOrder(Node root)``  ``{` `    ``// Base Case``    ``if` `(root == ``null``)  ``return``;``    ``Queue q = ``new` `LinkedList<>();``    ``q.add(root);``    ``while` `(q.isEmpty() == ``false``)``    ``{` `      ``// Print front of queue and remove``      ``// it from queue``      ``Node node = q.peek();``      ``System.out.print(node.key + ``" "``);``      ``q.remove();``      ``if` `(node.left != ``null``)``        ``q.add(node.left);``      ``if` `(node.right != ``null``)``        ``q.add(node.right);``    ``}``  ``}` `  ``// Driver program``  ``public` `static` `void` `main(String[] args)``  ``{``    ``int` `val = ``48``;``// sample value``    ``root = ``null``;``    ``root = createFactorTree(root, val);``    ``System.out.println(``"Level order traversal of "``+``                       ``"constructed factor tree"``);``    ``printLevelOrder(root);``  ``}``}` `// This code is contributed by Rajput-Ji`

## C#

 `// C# program to conFactor Tree for``// a given number``using` `System;``using` `System.Collections.Generic;` `public` `class` `GFG``{` `  ``// Tree node``  ``public``    ``class` `Node``    ``{``      ``public``        ``Node left, right;``      ``public``        ``int` `key;``    ``};``  ``static` `Node root;` `  ``// Utility function to create a new tree Node``  ``static` `Node newNode(``int` `key)``  ``{``    ``Node temp = ``new` `Node();``    ``temp.key = key;``    ``temp.left = temp.right = ``null``;``    ``return` `temp;``  ``}` `  ``// Constructs factor tree for given value and stores``  ``// root of tree at given reference.``  ``static` `Node createFactorTree(Node node_ref, ``int` `v)``  ``{``    ``(node_ref) = newNode(v);` `    ``// the number is factorized``    ``for` `(``int` `i = 2 ; i < v/2 ; i++)``    ``{``      ``if` `(v % i != 0)``        ``continue``;` `      ``// If we found a factor, we conleft``      ``// and right subtrees and return. Since we``      ``// traverse factors starting from smaller``      ``// to greater, left child will always have``      ``// smaller factor``      ``node_ref.left = createFactorTree(((node_ref).left), i);``      ``node_ref.right =  createFactorTree(((node_ref).right), v/i);``      ``return` `node_ref;``    ``}``    ``return` `node_ref;``  ``}` `  ``// Iterative method to find the height of Binary Tree``  ``static` `void` `printLevelOrder(Node root)``  ``{` `    ``// Base Case``    ``if` `(root == ``null``)  ``return``;``    ``Queue q = ``new` `Queue();``    ``q.Enqueue(root);``    ``while` `(q.Count != 0)``    ``{` `      ``// Print front of queue and remove``      ``// it from queue``      ``Node node = q.Peek();``      ``Console.Write(node.key + ``" "``);``      ``q.Dequeue();``      ``if` `(node.left != ``null``)``        ``q.Enqueue(node.left);``      ``if` `(node.right != ``null``)``        ``q.Enqueue(node.right);``    ``}``  ``}` `  ``// Driver program``  ``public` `static` `void` `Main(String[] args)``  ``{``    ``int` `val = 48;``// sample value``    ``root = ``null``;``    ``root = createFactorTree(root, val);``    ``Console.WriteLine(``"Level order traversal of "``+``                      ``"constructed factor tree"``);``    ``printLevelOrder(root);``  ``}``}` `// This code is contributed by gauravrajput1`

Output:

```Level order traversal of constructed factor tree
48 2 24 2 12 2 6 2 3 ```

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