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Print “Even” or “Odd” without using conditional statement

  • Difficulty Level : Easy
  • Last Updated : 17 Aug, 2021

Write a program that accepts a number from the user and prints “Even” if the entered number is even and prints “Odd” if the number is odd. You are not allowed to use any comparison (==, <,>,…etc) or conditional statements (if, else, switch, ternary operator,. Etc).

Method 1 
Below is a tricky code can be used to print “Even” or “Odd” accordingly. 


#include <iostream>
using namespace std;
int main()
    char arr[2][5] = { "Even", "Odd" };
    int no;
    cout << "Enter a number: ";
    cin >> no;
    cout << arr[no % 2];
    return 0;


import java.util.Scanner;
class GFG
    public static void main(String[] args)
        String[] arr = {"Even", "Odd"};
        Scanner s = new Scanner(;
        System.out.print("Enter the number: ");
        int no = s.nextInt();
// This code is contributed by divyeshrabadiya07.


arr = ["Even", "Odd"]
print ("Enter the number")
no = int(input())
print (arr[no % 2])


using System;
class GFG {
  static void Main() {
    string[] arr = {"Even", "Odd"};
    Console.Write("Enter the number: ");
    string val;
    val = Console.ReadLine();
    int no = Convert.ToInt32(val);
// This code is contributed by divyesh072019.


$arr = ["Even", "Odd"];
$input = 5;
echo ($arr[$input % 2]);
// This code is contributed
// by Aman ojha


    let arr = ["Even", "Odd"];
    let no = prompt("Enter a number: ");
    document.write(arr[no % 2]);
   // This code is contributed by suresh07

Method 2 
Below is another tricky code can be used to print “Even” or “Odd” accordingly. Thanks to student for suggesting this method.


int main()
    int no;
    printf("Enter a no: ");
    scanf("%d", &no);
    (no & 1 && printf("odd"))|| printf("even");
    return 0;
Enter a no: even

Please write comments if you find the above code incorrect, or find better ways to solve the same problem

Method 3
This can also be done using a concept known as Branchless Programming. Essentially, make use of the fact that a true statement in Python (other some other languages) evaluates to 1 and a false statements evaluates to false.


# code
n = int(input("Enter a number: "))
print("Even" * (n % 2 == 0), "Odd" * (n % 2 != 0))
Enter a number: Even 
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