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Evaluate the Value of an Arithmetic Expression in Reverse Polish Notation in Python

Last Updated : 07 Nov, 2022
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Reverse Polish ‘Notation is postfix notation which in terms of mathematical notion signifies operators following operands. Let’s take a problem statement to implement RPN

Problem Statement: The task is to find the value of the arithmetic expression present in the array using valid operators like +, -, *, /. Each operand may be an integer or another expression.

Note:

  1. The division between two integers should truncate toward zero.
  2. The given RPN expression is always valid. That means the expression would always evaluate to a result and there won’t be any divide by zero operation.

Layman Working of RPN as shown

Input: ["2", "1", "+", "3", "*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9

Input: ["4", "13", "5", "/", "+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6

Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
Output: 22
Explanation: 
  ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22

Approach:

The basic approach for the problem is using the stack.

  • Accessing all elements in the array, if the element is not matching with the special character (‘+’, ‘-‘,’*’, ‘/’) then push the element to the stack.
  • Then whenever the special character is found then pop the first two-element from the stack and perform the action and then push the element to stack again.
  • Repeat the above two process to all elements in the array
  • At last pop the element from the stack and print the Result

Implementation:

Python3




# Python 3 code to evaluate reverse polish notation
  
# function to evaluate reverse polish notation
def evaluate(expression):
  # splitting expression at whitespaces
  expression = expression.split()
    
  # stack
  stack = []
    
  # iterating expression
  for ele in expression:
      
    # ele is a number
    if ele not in '/*+-':
      stack.append(int(ele))
      
    # ele is an operator
    else:
      # getting operands
      right = stack.pop()
      left = stack.pop()
        
      # performing operation according to operator
      if ele == '+':
        stack.append(left + right)
          
      elif ele == '-':
        stack.append(left - right)
          
      elif ele == '*':
        stack.append(left * right)
          
      elif ele == '/':
        stack.append(int(left / right))
    
  # return final answer.
  return stack.pop()
  
# input expression
arr = "10 6 9 3 + -11 * / * 17 + 5 +"
  
# calling evaluate()
answer = evaluate(arr)
# printing final value of the expression
print(f"Value of given expression'{arr}' = {answer}")
          
          
          
          
          
         


Output

Value of given expression'10 6 9 3 + -11 * / * 17 + 5 +' = 22

Time complexity: O(n)

Auxiliary Space: O(n)

Please refer complete article on Evaluate the Value of an Arithmetic Expression in Reverse Polish Notation in Java for more details!



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