Evaluate the Value of an Arithmetic Expression in Reverse Polish Notation in Java

Reverse Polish ‘Notation is postfix notation which in terms of mathematical notion signifies operators following operands. Let’s take a problem statement to implement RPN

Problem Statement: The task is to find the value of the arithmetic expression present in the array using valid operators like +, -, *, /. Each operand may be an integer or another expression.

Note:

1. The division between two integers should truncate toward zero.
2. The given RPN expression is always valid. That means the expression would always evaluate to a result and there won’t be any divide by zero operation.

Layman Working of RPN as shown

Input: ["2", "1", "+", "3", "*"]
Output: 9
Explanation: ((2 + 1) * 3) = 9

Input: ["4", "13", "5", "/", "+"]
Output: 6
Explanation: (4 + (13 / 5)) = 6

Input: ["10", "6", "9", "3", "+", "-11", "*", "/", "*", "17", "+", "5", "+"]
Output: 22
Explanation: 
  ((10 * (6 / ((9 + 3) * -11))) + 17) + 5
= ((10 * (6 / (12 * -11))) + 17) + 5
= ((10 * (6 / -132)) + 17) + 5
= ((10 * 0) + 17) + 5
= (0 + 17) + 5
= 17 + 5
= 22

Approach:

The basic approach for the problem is using the stack.

• Accessing all elements in the array, if the element is not matching with the special character (‘+’, ‘-‘,’*’, ‘/’) then push the element to the stack.
• Then whenever the special character is found then pop the first two-element from the stack and perform the action and then push the element to stack again.
• Repeat the above two process to all elements in the array
• At last pop the element from the stack and print the Result

Implementation:

C++

#include <bits/stdc++.h>
using namespace std;
int eval(vector<string>& A)
{
    stack<int> st;
    for (int i = 0; i < A.size(); i++) {
        if (A[i] != "+" && A[i] != "-" && A[i] != "/"
            && A[i] != "*") {
            st.push(stoi(A[i]));
            continue;
        }
        else {
            int b = st.top();
            st.pop();
            int a = st.top();
            st.pop();
            if (A[i] == "+")
                st.push(a + b);
            else if (A[i] == "-")
                st.push(a - b);
            else if (A[i] == "*")
                st.push(a * b);
            else
                st.push(a / b);
        }
    }
    return st.top();
}

int main()
{
    vector<string> A
        = { "10", "6", "9",  "3", "+", "-11", "*",
            "/",  "*", "17", "+", "5", "+" };

    int res = eval(A);
    cout << res << endl;
}

Java

// Java Program to find the
// solution of the arithmetic
// using the stack
import java.io.*;
import java.util.*;

class solution {
    public int stacky(String[] tokens)
    {

        // Initialize the stack and the variable
        Stack<String> stack = new Stack<String>();
        int x, y;
        String result = "";
        int get = 0;
        String choice;
        int value = 0;
        String p = "";

        // Iterating to the each character
        // in the array of the string
        for (int i = 0; i < tokens.length; i++) {

            // If the character is not the special character
            // ('+', '-' ,'*' , '/')
            // then push the character to the stack
            if (tokens[i] != "+" && tokens[i] != "-"
                && tokens[i] != "*" && tokens[i] != "/") {
                stack.push(tokens[i]);
                continue;
            }
            else {
                // else if the character is the special
                // character then use the switch method to
                // perform the action
                choice = tokens[i];
            }

            // Switch-Case
            switch (choice) {
            case "+":

                // Performing the "+" operation by popping
                // put the first two character
                // and then again store back to the stack

                x = Integer.parseInt(stack.pop());
                y = Integer.parseInt(stack.pop());
                value = x + y;
                result = p + value;
                stack.push(result);
                break;

            case "-":

                // Performing the "-" operation by popping
                // put the first two character
                // and then again store back to the stack
                x = Integer.parseInt(stack.pop());
                y = Integer.parseInt(stack.pop());
                value = y - x;
                result = p + value;
                stack.push(result);
                break;

            case "*":

                // Performing the "*" operation
                // by popping put the first two character
                // and then again store back to the stack

                x = Integer.parseInt(stack.pop());
                y = Integer.parseInt(stack.pop());
                value = x * y;
                result = p + value;
                stack.push(result);
                break;

            case "/":

                // Performing the "/" operation by popping
                // put the first two character
                // and then again store back to the stack

                x = Integer.parseInt(stack.pop());
                y = Integer.parseInt(stack.pop());
                value = y / x;
                result = p + value;
                stack.push(result);
                break;

            default:
                continue;
            }
        }

        // Method to convert the String to integer
        return Integer.parseInt(stack.pop());
    }
}

class GFG {

    public static void main(String[] args)
    {
        // String Input
        String[] s
            = { "10", "6", "9",  "3", "+", "-11", "*",
                "/",  "*", "17", "+", "5", "+" };

        solution str = new solution();
        int result = str.stacky(s);
        System.out.println(result);
    }
}

Python3

# Python 3 code to evaluate reverse polish notation

"""
This code is contributed by Harshal Gupta
"""

# function to evaluate reverse polish notation
def evaluate(expression):
  # splitting expression at whitespaces
  expression = expression.split()

  # stack
  stack = []

  # iterating expression
  for ele in expression:

    # ele is a number
    if ele not in '/*+-':
      stack.append(int(ele))

    # ele is an operator
    else:
      # getting operands
      right = stack.pop()
      left = stack.pop()

      # performing operation according to operator
      if ele == '+':
        stack.append(left + right)

      elif ele == '-':
        stack.append(left - right)

      elif ele == '*':
        stack.append(left * right)

      elif ele == '/':
        stack.append(int(left / right))

  # return final answer.
  return stack.pop()

# input expression
arr = "10 6 9 3 + -11 * / * 17 + 5 +"

# calling evaluate()
answer = evaluate(arr)
# printing final value of the expression
print(f"Value of given expression'{arr}' = {answer}")

C#

// C# Program to find the
// solution of the arithmetic
// using the stack

using System;
using System.Collections.Generic;

public class GFG {

  public class Solution {
    public int stacky(string[] tokens)
    {
      // Initialize the stack and the variable
      Stack<string> stack = new Stack<string>();
      int x, y;
      string result = "";
      string choice;
      int value = 0;
      string p = "";

      // Iterating to the each character
      // in the array of the string
      for (int i = 0; i < tokens.Length; i++) {
        // If the character is not the special
        // character
        // ('+', '-' ,'*' , '/')
        // then push the character to the stack
        if (tokens[i] != "+" && tokens[i] != "-"
            && tokens[i] != "*"
            && tokens[i] != "/") {
          stack.Push(tokens[i]);
          continue;
        }
        else {
          // else if the character is the special
          // character then use the switch method
          // to perform the action
          choice = tokens[i];
        }

        // Switch-Case
        switch (choice) {
          case "+":
            // Performing the "+" operation by
            // popping put the first two character
            // and then again store back to the
            // stack

            x = int.Parse(stack.Pop());
            y = int.Parse(stack.Pop());
            value = x + y;
            result = p + value;
            stack.Push(result);
            break;

          case "-":
            // Performing the "-" operation by
            // popping put the first two character
            // and then again store back to the
            // stack
            x = int.Parse(stack.Pop());
            y = int.Parse(stack.Pop());
            value = y - x;
            result = p + value;
            stack.Push(result);
            break;

          case "*":
            // Performing the "*" operation
            // by popping put the first two
            // character and then again store back
            // to the stack

            x = int.Parse(stack.Pop());
            y = int.Parse(stack.Pop());
            value = x * y;
            result = p + value;
            stack.Push(result);
            break;

          case "/":
            // Performing the "/" operation by
            // popping put the first two character
            // and then again store back to the
            // stack

            x = int.Parse(stack.Pop());
            y = int.Parse(stack.Pop());
            value = y / x;
            result = p + value;
            stack.Push(result);
            break;

          default:
            continue;
        }
      }

      // Method to convert the String to integer
      return int.Parse(stack.Pop());
    }
  }

  static public void Main()
  {

    // String Input
    string[] s
      = { "10", "6", "9",  "3", "+", "-11", "*",
         "/",  "*", "17", "+", "5", "+" };

    Solution str = new Solution();
    int result = str.stacky(s);
    Console.WriteLine(
      "Value of given expression'10 6 9 3 + -11 * / * 17 + 5 +' = "
      + result);
  }
}

// This code is contributed by lokesh

Javascript

// Javascript code to evaluate reverse polish notation
function eval(A)
{

    // Initialize the stack
    let st = [];

    // Iterating to the each character
    // in the array of the string
    for (let i = 0; i < A.length; i++)
    {

        // If the character is not the special character
        // ('+', '-' ,'*' , '/')
        // then push the character to the stack
        if (A[i] != "+" && A[i] != "-" && A[i] != "/"
            && A[i] != "*") {
            st.push(parseInt(A[i]));
            continue;
        }

         // else if the character is the special
         // character then use them to
         // perform the action
        else {
            let b = parseInt(st.pop());
            let a = parseInt(st.pop());
            if (A[i] == "+")
                st.push(a + b);
            else if (A[i] == "-")
                st.push(a - b);
            else if (A[i] == "*")
                st.push(a * b);
            else
                st.push(parseInt(a / b));
        }
    }
    return parseInt(st[st.length-1]);
}

    let A = [ "10", "6", "9", "3", "+", "-11", "*",
            "/", "*", "17", "+", "5", "+" ];

    let res = eval(A);
    console.log(res);

    // This code is contributed by Pushpesh Raj.

Output

Value of given expression'10 6 9 3 + -11 * / * 17 + 5 +' = 22

Time complexity: O(n)

Auxiliary Space: O(n)