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Efficiently check whether n is a multiple of 4 or not
• Difficulty Level : Medium
• Last Updated : 28 Apr, 2021

Given a number n. The problem is to efficiently check whether n is a multiple of 4 or not without using arithmetic operators.
Examples:

```Input : 16
Output : Yes

Input : 14
Output : No```

Approach: A multiple of 4 always has 00 as its last two digits in its binary representation. We have to check whether the last two digits of n are unset or not.
How to check whether the last two bits are unset or not.
If n & 3 == 0, then the last two bits are unset, else either both or one of them are set.

## C++

 `// C++ implementation to efficiently check whether n``// is a multiple of 4 or not``#include ``using` `namespace` `std;` `// function to check whether 'n' is``// a multiple of 4 or not``string isAMultipleOf4(``int` `n)``{``  ` `    ``// if true, then 'n' is a multiple of 4``    ``if` `((n & 3) == 0)``        ``return` `"Yes"``;` `    ``// else 'n' is not a multiple of 4``    ``return` `"No"``;``}` `// Driver program to test above``int` `main()``{``    ``int` `n = 16;``    ``cout << isAMultipleOf4(n);``    ``return` `0;``}`

## Java

 `// Java implementation to efficiently check``// whether n is a multiple of 4 or not` `class` `GFG {``    ``// method to check whether 'n' is``    ``// a multiple of 4 or not``    ``static` `boolean` `isAMultipleOf4(``int` `n)``    ``{``        ``// if true, then 'n' is a multiple of 4``        ``if` `((n & ``3``) == ``0``)``            ``return` `true``;` `        ``// else 'n' is not a multiple of 4``        ``return` `false``;``    ``}` `    ``// Driver method``    ``public` `static` `void` `main(String[] args)``    ``{``        ``int` `n = ``16``;``        ``System.out.println(isAMultipleOf4(n) ? ``"Yes"` `: ``"No"``);``    ``}``}`

## Python 3

 `# Python 3 implementation to``# efficiently check whether n``# is a multiple of 4 or not` `# function to check whether 'n'``# is a multiple of 4 or not``def` `isAMultipleOf4(n):` `    ``# if true, then 'n' is``    ``# a multiple of 4``    ``if` `((n & ``3``) ``=``=` `0``):``        ``return` `"Yes"` `    ``# else 'n' is not a``    ``# multiple of 4``    ``return` `"No"` `# Driver Code``if` `__name__ ``=``=` `"__main__"``:` `    ``n ``=` `16``    ``print` `(isAMultipleOf4(n))` `# This code is contributed``# by ChitraNayal`

## C#

 `// C# implementation to efficiently check``// whether n is a multiple of 4 or not``using` `System;` `class` `GFG {``    ` `    ``// method to check whether 'n' is``    ``// a multiple of 4 or not``    ``static` `bool` `isAMultipleOf4(``int` `n)``    ``{``        ``// if true, then 'n' is a multiple of 4``        ``if` `((n & 3) == 0)``            ``return` `true``;` `        ``// else 'n' is not a multiple of 4``        ``return` `false``;``    ``}` `    ``// Driver method``    ``public` `static` `void` `Main()``    ``{``        ``int` `n = 16;``        ``Console.WriteLine(isAMultipleOf4(n) ? ``"Yes"` `: ``"No"``);``    ``}``}` `// This code is contributed by vt_m.`

## PHP

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## Javascript

 ``

Output:

`Yes`

Can we generalize above solution?
Similarly we can check for other powers of 2. For example, a number n would be multiple of 8 if n & 7 is 0. In general we can say.

```// x must be a power of 2 for below
// logic to work
if (n & (x -1) == 0)
n is a multiple of x
Else
n is NOT a multiple of x```

https://youtu.be/ke

-Mai2m6Cg
This article is contributed by Ayush Jauhri. If you like GeeksforGeeks and would like to contribute, you can also write an article using contribute.geeksforgeeks.org or mail your article to contribute@geeksforgeeks.org. See your article appearing on the GeeksforGeeks main page and help other Geeks.